Problem 50
Question
For the following exercises, solve each equation for \(x\). $$ \log _{3}(3 x)-\log _{3}(6)=\log _{3}(77) $$
Step-by-Step Solution
Verified Answer
The solution is \( x = 154 \).
1Step 1: Apply the Logarithm Difference Property
The equation given is \( \log_{3}(3x) - \log_{3}(6) = \log_{3}(77) \). Use the logarithmic property \( \log_{b}(m) - \log_{b}(n) = \log_{b}\left( \frac{m}{n} \right) \). This transforms the left side to \( \log_{3}\left( \frac{3x}{6} \right) \).
2Step 2: Simplify the Expression
Simplify the expression \( \frac{3x}{6} \) to \( \frac{x}{2} \). The equation is now \( \log_{3}\left( \frac{x}{2} \right) = \log_{3}(77) \).
3Step 3: Equate the Arguments of Logarithms
Since the bases of the logarithms are the same and the logs are equal, equate the arguments: \( \frac{x}{2} = 77 \).
4Step 4: Solve for x
Multiply both sides of the equation \( \frac{x}{2} = 77 \) by 2 to solve for \( x \). This gives \( x = 154 \).
Key Concepts
Applying Logarithmic PropertiesEquating Arguments of LogarithmsSolving Equations for Variables
Applying Logarithmic Properties
Understanding logarithmic properties is crucial when solving logarithmic equations. One such property is the difference property, which allows us to combine two logarithms that are subtracted. If you have \( \log_{b}(m) - \log_{b}(n) \), you can rewrite it as \( \log_{b}\left( \frac{m}{n} \right) \). This property simplifies the expression and makes equations easier to handle.
In the exercise, the original equation is \( \log_{3}(3x) - \log_{3}(6) \). By applying the difference property, this becomes \( \log_{3}\left( \frac{3x}{6} \right) \). This step is instrumental in reducing the equation to a simpler form, which then is simplified further in subsequent steps.
In the exercise, the original equation is \( \log_{3}(3x) - \log_{3}(6) \). By applying the difference property, this becomes \( \log_{3}\left( \frac{3x}{6} \right) \). This step is instrumental in reducing the equation to a simpler form, which then is simplified further in subsequent steps.
Equating Arguments of Logarithms
Once we have applied the logarithmic properties and simplified the equation, the next step is to equate the arguments. When you have an equation like \( \log_{b}(A) = \log_{b}(B) \), provided the bases are the same, you can deduce that the arguments must be equal: \( A = B \). This logical step is based on the fact that logarithmic functions are one-to-one.In our problem, after simplification, we are left with \( \log_{3}\left( \frac{x}{2} \right) = \log_{3}(77) \). Since the base on both sides of the equation is \( 3 \), it follows that \( \frac{x}{2} = 77 \). Equating the arguments reduces the problem to a more straightforward algebraic expression, allowing us to solve for \( x \) in the final step.
Solving Equations for Variables
The final step in solving the logarithmic equation is solving for the unknown variable. After equating the arguments, the problem often reduces to a simple algebraic equation, like \( \frac{x}{2} = 77 \). This step involves basic algebraic operations to isolate and find the value of the variable you are solving for.
To find \( x \), you multiply both sides of the equation by 2 to remove the fraction, yielding \( x = 154 \). This step reintroduces the solution into a practical context, completing the problem-solving process for the equation. Successfully solving for variables in logarithmic equations often requires comfort with basic algebra and arithmetic, thus reinforcing these skills in the learning process.
To find \( x \), you multiply both sides of the equation by 2 to remove the fraction, yielding \( x = 154 \). This step reintroduces the solution into a practical context, completing the problem-solving process for the equation. Successfully solving for variables in logarithmic equations often requires comfort with basic algebra and arithmetic, thus reinforcing these skills in the learning process.
Other exercises in this chapter
Problem 49
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