Problem 50
Question
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=\cot \pi x$$
Step-by-Step Solution
Verified Answer
The period is 1 with vertical asymptotes at each integer value of \(x\).
1Step 1: Identify the Standard Form of the Cotangent Function
The given function is \(y = \cot(\pi x)\). The standard form of the cotangent function is \(y = \cot(bx)\). In our function, \(b = \pi\). The cotangent function in the standard form has a period \(\frac{\pi}{b}\).
2Step 2: Calculate the Period
The period \(T\) of the function \(y = \cot(bx)\) is given by the formula:\[T = \frac{\pi}{b}\]Substitute \(b = \pi\) from our function:\[T = \frac{\pi}{\pi} = 1\]Thus, the period of \(y = \cot(\pi x)\) is 1.
3Step 3: Determine Asymptotes
The standard cotangent function \(y = \cot(bx)\) has asymptotes where \(bx = n\pi\), for integer \(n\). Thus for \(y = \cot(\pi x)\), this means:\[\pi x = n\pi\]Simplifying gives \(x = n\). Therefore, vertical asymptotes occur at every integer value of \(x\).
4Step 4: Sketch the Graph
Start by sketching a single period from \(x=0\) to \(x=1\). Since there are vertical asymptotes at \(x=0\) and \(x=1\), the cotangent curve begins near \(x=0\), decrements, and approaches another asymptote at \(x=1\). Match this cycle for consecutive periods, repeating every 1 unit along the x-axis.
Key Concepts
Period of a FunctionAsymptotesTrigonometric Graph Sketching
Period of a Function
The period of a function refers to the length of the interval over which the function repeats itself. For trigonometric functions, determining the period is crucial for understanding how the wave-like pattern repeats across the x-axis.
To find the period of the cotangent function, we use its general form: \(y = \cot(bx)\). The formula for the period \(T\) is \(T = \frac{\pi}{b}\), where \(b\) is a constant multiplying the variable \(x\).
In our exercise with the function \(y = \cot(\pi x)\), we substitute \(b = \pi\) into the formula:
To find the period of the cotangent function, we use its general form: \(y = \cot(bx)\). The formula for the period \(T\) is \(T = \frac{\pi}{b}\), where \(b\) is a constant multiplying the variable \(x\).
In our exercise with the function \(y = \cot(\pi x)\), we substitute \(b = \pi\) into the formula:
- T = \(\frac{\pi}{\pi} = 1\)
Asymptotes
Asymptotes are lines that a graph approaches but never actually touches or crosses. For trigonometric graphs like the cotangent function, vertical asymptotes occur periodically and are vital to graphing.
The standard cotangent function \(y = \cot(bx)\) has vertical asymptotes at \(bx = n\pi\), where \(n\) is an integer. This is because \(\cot(\theta)\) is undefined at these points, causing the graph to "shoot" towards infinity.
For the specific function \(y = \cot(\pi x)\), setting up the equation \(\pi x = n\pi\) gives:
The standard cotangent function \(y = \cot(bx)\) has vertical asymptotes at \(bx = n\pi\), where \(n\) is an integer. This is because \(\cot(\theta)\) is undefined at these points, causing the graph to "shoot" towards infinity.
For the specific function \(y = \cot(\pi x)\), setting up the equation \(\pi x = n\pi\) gives:
- x = \(n\)
Trigonometric Graph Sketching
Sketching the graph of a trigonometric function involves several steps, including identifying periods and locating asymptotes. For \(y = \cot(\pi x)\), understanding these features ensures an accurate representation.
To sketch the graph:
To sketch the graph:
- Begin within one period, from \(x=0\) to \(x=1\).
- Mark the vertical asymptotes at \(x=0\) and \(x=1\). This will create a boundary for a single cycle within this interval.
- The cotangent curve starts near one asymptote, moves downwards, and approaches the next asymptote.
- Repeat this pattern for each additional period, as the cotangent function repeats every unit.
Other exercises in this chapter
Problem 50
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