Problem 50
Question
Determine the end behavior of the following transcendental functions by analyzing appropriate limits. Then provide a simple sketch of the associated graph, showing asymptotes if they exist. $$f(x)=\frac{50}{e^{2 x}}$$
Step-by-Step Solution
Verified Answer
Answer: As x approaches both positive and negative infinity, the function approaches 0, with a horizontal asymptote at y = 0.
1Step 1: Analyze the limit as x approaches positive and negative infinity
First, let's find the limit as x approaches positive infinity:
$$\lim_{x \to \infty} \frac{50}{e^{2x}}$$
Since the exponential function grows faster than any polynomial function, this limit will go to 0:
$$\lim_{x \to \infty} \frac{50}{e^{2x}} = 0$$
Now, let's find the limit as x approaches negative infinity:
$$\lim_{x \to -\infty} \frac{50}{e^{2x}}$$
Since \(e^x\) will go to infinity as x approaches negative infinity, the function will also go to 0:
$$\lim_{x \to -\infty} \frac{50}{e^{2x}} = 0$$
This means, as x approaches both positive and negative infinity, the function approaches 0.
2Step 2: Determine any horizontal or vertical asymptotes
Since the limit of the function as x approaches both positive and negative infinity is 0, there exists a horizontal asymptote at y=0.
There are no vertical asymptotes in this function as the denominator will never equal 0.
3Step 3: Sketch the graph of the function
Based on the information gathered in the previous steps, we will now sketch the graph of the function $$f(x)=\frac{50}{e^{2 x}}$$
1. The function approaches 0 as x approaches both positive and negative infinity, forming a horizontal asymptote at y = 0.
2. There are no vertical asymptotes.
3. The function starts at a positive value and then decreases as x increases.
Using this information, we can sketch a simple graph of the function. Note that the sketch may not be to scale, but it serves to demonstrate the overall behavior of the function.
Key Concepts
End BehaviorLimitsHorizontal Asymptotes
End Behavior
End behavior refers to how a function behaves as the input, or x-value, approaches extreme values such as positive or negative infinity. In the context of transcendental functions like \( f(x) = \frac{50}{e^{2x}} \), understanding the end behavior helps in predicting how the function will trend in the long term.
For our function, as \( x \) approaches positive infinity, the term \( e^{2x} \) grows extremely large at an exponential rate. Thus, the denominator becomes very large, and the whole fraction approaches zero. This illustrates the rapid decay or shrinking of \( f(x) \) towards zero.
For our function, as \( x \) approaches positive infinity, the term \( e^{2x} \) grows extremely large at an exponential rate. Thus, the denominator becomes very large, and the whole fraction approaches zero. This illustrates the rapid decay or shrinking of \( f(x) \) towards zero.
- The limit \( \lim_{x \to \infty} \frac{50}{e^{2x}} = 0 \) clearly shows the end behavior as x grows larger.
- Conversely, as \( x \) approaches negative infinity, \( e^{2x} \) again tends to grow towards positive infinity, due to the negative sign flipping in the exponent.
- Therefore, \( \lim_{x \to -\infty} \frac{50}{e^{2x}} = 0 \) is another indication of decay.
Limits
Limits are a fundamental concept in calculus, used to find the value that a function approaches as the input approaches a specific point. For transcendental functions, this concept is crucial in determining end behavior and asymptotes.
In analyzing \( f(x) = \frac{50}{e^{2x}} \), calculating the limit as \( x \to \infty \) demonstrates how \( f(x) \) behaves as x grows without bounds.
In analyzing \( f(x) = \frac{50}{e^{2x}} \), calculating the limit as \( x \to \infty \) demonstrates how \( f(x) \) behaves as x grows without bounds.
- The limit \( \lim_{x \to \infty} \frac{50}{e^{2x}} \) yields a result of 0, indicating the output value diminishes.
- Similarly, for \( x \to -\infty \), the function also approaches 0, \( \lim_{x \to -\infty} \frac{50}{e^{2x}} = 0 \).
Horizontal Asymptotes
Horizontal asymptotes graphically represent a line that a function approaches but never touches. These are commonly found by analyzing limits as \( x \) tends towards infinity or negative infinity.
For the function \( f(x) = \frac{50}{e^{2x}} \), the previously calculated limits both approaching 0 imply the presence of a horizontal asymptote along the line \( y = 0 \).
For the function \( f(x) = \frac{50}{e^{2x}} \), the previously calculated limits both approaching 0 imply the presence of a horizontal asymptote along the line \( y = 0 \).
- Since as \( x \to \infty \) and \( x \to -\infty \), \( f(x) \to 0 \), this establishes \( y = 0 \) as a horizontal asymptote.
- There are no vertical asymptotes because the exponential expression in the denominator never reaches zero; hence the function remains continuous.
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