Problem 50
Question
COMMON FACTOR Factor the expression. $$ 2 x^{2}+28 x y+98 y^{2} $$
Step-by-Step Solution
Verified Answer
The factorized form of the expression \(2x^{2}+28xy+98y^{2}\) is \(2(x+7y)^{2}\).
1Step 1: Identify the Common Factor
Look at all the terms in the expression \(2x^{2}+28xy+98y^{2}\) to identify a common factor. In this case, we can see that \(2\) is a common factor among all the terms.
2Step 2: Factor out the Common Factor
Factor out the common factor, which in this case is 2. So the expression becomes \(2(x^{2}+14xy+49y^{2})\).
3Step 3: Recognize and Factor the Quadratic
The expression inside the parenthesis \(x^{2}+14xy+49y^{2}\) is a quadratic trinomial. We should try to express it as the square of a binomial. By trial, error and observation we obtain \(x^{2}+14xy+49y^{2}=(x+7y)^{2}\).
4Step 4: Write the Final Factorized Expression
Replace the quadratic trinomial in the expression with its factorized form to get the final answer: \(2(x+7y)^{2}\).
Key Concepts
Common FactorQuadratic TrinomialBinomial Square
Common Factor
Finding a common factor is often the first step when factoring expressions. It simplifies the expression by reducing its terms. In the expression \(2x^{2} + 28xy + 98y^{2}\), the common factor is \(2\). Here’s how you spot it:
- Look at all numerical coefficients in the terms: \(2, 28, 98\).
- Find the greatest number that divides all these coefficients. In this case, it is \(2\).
Quadratic Trinomial
A quadratic trinomial typically has three terms with degrees that appear in descending order. The expression within the parentheses: \(x^{2}+14xy+49y^{2}\) is a good illustration of a quadratic trinomial. Here's what makes it one:
- The first term, \(x^2\), is quadratic because of the square power on \(x\).
- The middle term, \(14xy\), contains both variables \(x\) and \(y\), contributing a linear mix.
- The last term, \(49y^2\), is a perfect square with too a degree of 2.
Binomial Square
A binomial square refers to an expression that is the square of a binomial expression. In the context of the expression \(x^{2}+14xy+49y^{2}\), we recognize it can be rewritten as a binomial square, \((x+7y)^{2}\).This form emerges because:
- The term \((x)^{2}\) is the square of \(x\).
- The term \((7y)^{2}\) is the square of \(7y\).
- The middle term, \(14xy\), is twice the product of the first term \(x\) and the last term \(7y\) of the binomial.
Other exercises in this chapter
Problem 49
$$ (d-5)\left(d^{2}-2 d-6\right) $$
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Solve the equation by factoring. $$ 6 x^{2}-23 x=18 $$
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Use a vertical format or a horizontal format to add or subtract. $$ \left(10 x^{3}+2 x^{2}-11\right)+\left(9 x^{2}+2 x-1\right) $$
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Find the greatest common factor. $$ 12,36 $$
View solution