Problem 50
Question
$$\begin{array}{l}\text { If } P(B)=0.30, P(A \cup B)=0.65, \text { and } P(A \cap B)=0.15 \\\\\text { find } P(A) .\end{array}$$
Step-by-Step Solution
Verified Answer
P(A) = 0.50
1Step 1: Understand the Given Information
The problem provides the following probabilities: - Probability of event B, written as: \( P(B) = 0.30 \)- Probability of either event A or event B (union), written as: \( P(A \,\cup\, B) = 0.65 \)- Probability of both events A and B occurring together (intersection), written as: \( P(A \,\cap\, B) = 0.15 \)
2Step 2: Use the Formula for the Union of Two Events
Recall the formula for the union of two events, which is given by:\[ P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B) \]This formula can be rearranged to solve for \( P(A) \).
3Step 3: Insert the Given Values into the Formula
Substitute the given probabilities into the formula:\[ 0.65 = P(A) + 0.30 - 0.15 \]
4Step 4: Solve for P(A)
Isolate \( P(A) \) by solving the equation:\[ 0.65 = P(A) + 0.15 \]Subtract 0.15 from both sides:\[ 0.65 - 0.15 = P(A) \]This simplifies to:\[ P(A) = 0.50 \]
Key Concepts
Union of EventsIntersection of EventsSolving Equations
Union of Events
In probability, the union of two events, denoted as \(P(A \,\cup\, B)\), represents the probability that either event A occurs, event B occurs, or both events occur. The key formula for the union of two events is:
\[P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B)\]
This formula helps us ensure we do not double-count the probability of both events occurring.
Example: If you know \(P(B) = 0.30\), \(P(A \,\cup\, B) = 0.65\), and \(P(A \,\cap\, B) = 0.15\), you can use the union of events formula to find \(P(A)\). First, rearrange the formula to solve for \(P(A)\). Substitute the given probabilities:
\[0.65 = P(A) + 0.30 - 0.15\]
Then, isolate \(P(A)\):
\[P(A) = 0.65 - 0.15 = 0.50\]
This means the probability of event A occurring is 0.50.
\[P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B)\]
This formula helps us ensure we do not double-count the probability of both events occurring.
Example: If you know \(P(B) = 0.30\), \(P(A \,\cup\, B) = 0.65\), and \(P(A \,\cap\, B) = 0.15\), you can use the union of events formula to find \(P(A)\). First, rearrange the formula to solve for \(P(A)\). Substitute the given probabilities:
\[0.65 = P(A) + 0.30 - 0.15\]
Then, isolate \(P(A)\):
\[P(A) = 0.65 - 0.15 = 0.50\]
This means the probability of event A occurring is 0.50.
Intersection of Events
The intersection of two events, symbolized as \(P(A \,\cap\, B)\), refers to the probability that both events A and B happen at the same time. To understand this better, think of it as the overlap in a Venn diagram where both circles intersect.
Example: Suppose \(P(A \,\cap\, B) = 0.15\). This means there's a 15% chance that both events A and B occur together.
In our given problem, knowing the intersection value was crucial to finding \(P(A)\). We used the formula:
\[P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B)\]
Substituting the known values allowed us to eliminate the double-counted area, thus accurately determining \(P(A)\).
Example: Suppose \(P(A \,\cap\, B) = 0.15\). This means there's a 15% chance that both events A and B occur together.
In our given problem, knowing the intersection value was crucial to finding \(P(A)\). We used the formula:
\[P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B)\]
Substituting the known values allowed us to eliminate the double-counted area, thus accurately determining \(P(A)\).
Solving Equations
Solving equations is a fundamental skill in probability and many other areas of mathematics. It involves finding the value of a variable that makes an equation true. Let's break down how we solve the equation in this problem step-by-step:
- Start with the equation given by the formula \(P(A \,\cup\, B) = P(A) + P(B) - P(A \,\cap\, B)\).
- Insert the known values: \[0.65 = P(A) + 0.30 - 0.15.\]
- Combine like terms on the right-hand side: \[0.65 = P(A) + 0.15.\]
- Isolate \(P(A)\) by subtracting 0.15 from both sides: \[0.50 = P(A).\]
Other exercises in this chapter
Problem 49
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