Problem 50
Question
Because of the increasingly important role played by coal as a viable alternative energy source, the production of coal has been growing at the rate of $$ 3.5 e^{0.05 \mathrm{y}} $$ billion metric tons/year, \(t\) yr from 1980 (which corresponds to \(t=0\) ). Had it not been for the energy crisis, the rate of production of coal since 1980 might have been only $$ 3.5 e^{0.011} $$ billion metric tons/year, \(t\) yr from 1980 . Determine how much additional coal was produced between 1980 and the end of the century as an alternate energy source.
Step-by-Step Solution
Verified Answer
The additional coal produced between 1980 and the end of the century as an alternate energy source is approximately 42.91 billion metric tons.
1Step 1: Find the difference between the current and hypothetical rate of production
To find the difference between the current rate of coal production and the hypothetical rate of coal production without the energy crisis, subtract the hypothetical rate from the current rate.
Difference = Current rate - Hypothetical rate = \(3.5e^{0.05t} - 3.5e^{0.01t}\)
2Step 2: Set up the integral
Now, we need to integrate the difference of the two rates over the given time period (1980 to 2000). The integral will be:
$$
\int_{0}^{20} (3.5e^{0.05t} - 3.5e^{0.01t}) dt
$$
3Step 3: Evaluate the integral
To evaluate the integral, split it into two separate integrals:
$$
3.5 \int_{0}^{20} e^{0.05t} dt - 3.5 \int_{0}^{20} e^{0.01t} dt
$$
Now, integrate each part:
$$
3.5 [\frac{1}{0.05} e^{0.05t}]_{0}^{20} - 3.5 [\frac{1}{0.01} e^{0.01t}]_{0}^{20}
$$
4Step 4: Apply the limits
Next, apply the limits to each part of the integral:
$$
3.5 [\frac{1}{0.05} (e^{0.05(20)} - e^{0.05(0)})] - 3.5 [\frac{1}{0.01} (e^{0.01(20)} - e^{0.01(0)})]
$$
5Step 5: Simplify the expression
Finally, simplify the expression to find the total additional coal produced:
$$
3.5 [\frac{1}{0.05} (e^{1} - 1)] - 3.5 [\frac{1}{0.01} (e^{0.2} - 1)]
$$
$$
\approx 3.5 (20e^1 - 20) - 3.5 (100e^{0.2} - 100)
$$
$$
\approx 3.5 (20e - 20 -100e^{0.2} +100)
$$
Now, calculate the value:
$$
\approx 3.5(20(2.718) - 20 -100(1.221) +100) = 3.5(54.36 - 20 - 122.1 +100) \approx 3.5(12.26) \approx 42.91
$$
So, the additional coal produced between 1980 and the end of the century as an alternate energy source is approximately 42.91 billion metric tons.
Key Concepts
IntegrationExponential GrowthEnergy Production
Integration
Integration is a key concept in calculus, often used to find the total accumulation of quantities. In the context of our problem about coal production, integration helps us calculate the total amount of coal produced over a specific time frame.
The process involves setting up an integral that represents the difference in production rates, which addresses how much more coal was produced due to the crises compared to a hypothetical scenario where it didn't occur. The fundamental idea is that through integration, we can measure these total differences over time by calculating the area under the curve of the production rate.
The process involves setting up an integral that represents the difference in production rates, which addresses how much more coal was produced due to the crises compared to a hypothetical scenario where it didn't occur. The fundamental idea is that through integration, we can measure these total differences over time by calculating the area under the curve of the production rate.
- The rate of production is modeled as an exponential function, which reflects how production grows over time.
- The exponential nature of the function hints at continuous growth, making integration the tool we use to find the accumulation over discrete intervals.
- The definite integral from 0 to 20 reflects the time from 1980 to 2000, two decades where this increased production took place.
Exponential Growth
Exponential growth is a powerful concept that explains how quickly things can increase. It is characterized by a growth rate that becomes ever faster as time passes. In the case of coal production, exponential growth is reflected in the rate of production formula:
\[3.5 e^{0.05t}\]
\[3.5 e^{0.05t}\]
- Here, the base (\(e\)) is the mathematical constant approximately equal to 2.718, symbolizing continuous growth.
- \(0.05t\) represents the exponent, where the growth rate is 5% per year compounding continuously from 1980.
Energy Production
Energy production is at the heart of economic and technological development. The significant role of coal in energy production during the 1980s was amplified due to increased demand. The use of coal as an alternative energy source cannot be overstated.
Several factors contribute to the surge in coal production:
Several factors contribute to the surge in coal production:
- Coal served as a primary backup when other energy resources became less reliable or cost-effective due to the energy crisis.
- The readiness to increase coal production showcased its feasibility as a scalable solution to meet rising energy demands.
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