Problem 50
Question
A sport-utility vehicle has an average mileage rating of 18 miles per gallon. How many gallons of gasoline are needed for a 389 -mile trip?
Step-by-Step Solution
Verified Answer
Answer: 22 gallons
1Step 1: Identify the given values and what we need to find
The given values in this problem are:
- Average mileage rating: 18 miles/gallon
- Trip distance: 389 miles
We need to find the number of gallons needed for a 389-mile trip.
2Step 2: Set up a proportion
To find the number of gallons needed, we will set up a proportion as follows:
\(\frac{18 \text{ miles}}{1 \text{ gallon}} = \frac{389 \text{ miles}}{x \text{ gallons}}\)
Here, we are comparing the average mileage rating with the trip distance and the number of gallons needed for the trip.
3Step 3: Solve for x (number of gallons)
To solve for x, we can cross-multiply:
\(18 \text{ miles} \times x \text{ gallons} = 1 \text{ gallon} \times 389 \text{ miles}\)
Now, divide both sides of the equation by 18 miles:
\(x \text{ gallons} = \frac{389 \text{ miles}}{18 \text{ miles}}\)
4Step 4: Calculate the number of gallons
Now, let's calculate the value of x:
\(x \text{ gallons} = \frac{389}{18}\)
\(x \approx 21.61\)
Since we cannot have a fraction of a gallon, we will round up to the nearest whole number. Therefore, 22 gallons of gasoline are needed for a 389-mile trip.
Key Concepts
Proportion MethodAverage MileageFuel Consumption
Proportion Method
The proportion method is a helpful and simple mathematical technique used to solve problems involving ratios. When you want to find a missing value that is directly proportional to another, the proportion method comes in handy.
The equation \[\frac{18 \text{ miles}}{1 \text{ gallon}} = \frac{389 \text{ miles}}{x \text{ gallons}}\]organizes this relationship and allows you to solve for the unknown variable, which is the amount of gasoline needed. Once the equation is set, solving for the missing part is straightforward using algebraic techniques.
- You set up two fractions that express the same relationship.
- The value you want to find is in one of these fractions as a variable.
- You solve the equation by multiplying across the diagonal (cross-multiplication) and dividing as necessary.
The equation \[\frac{18 \text{ miles}}{1 \text{ gallon}} = \frac{389 \text{ miles}}{x \text{ gallons}}\]organizes this relationship and allows you to solve for the unknown variable, which is the amount of gasoline needed. Once the equation is set, solving for the missing part is straightforward using algebraic techniques.
Average Mileage
Understanding average mileage is crucial for calculating fuel efficiency. The average mileage, often referred to as fuel economy, tells you how many miles a vehicle can travel per gallon of fuel.
This average is a simplified expression of the vehicle's efficiency under typical conditions.
- This is expressed in miles per gallon (mpg).
- It's an important factor when calculating long-distance fuel needs.
- Average mileage can vary based on driving conditions, vehicle maintenance, and other factors.
This average is a simplified expression of the vehicle's efficiency under typical conditions.
Fuel Consumption
Fuel consumption describes how much gasoline a vehicle uses to travel a specific distance. It's an essential aspect of both cost management and environmental consideration.
In connection with our example, fuel consumption was determined through the equation\[x \text{ gallons} = \frac{389 \text{ miles}}{18 \text{ miles per gallon}}\]After calculation, we find out we need approximately 21.61 gallons, which means buying 22 gallons to complete the 389-mile journey without worrying about running out of fuel.
- Efficient fuel consumption leads to savings in fuel costs.
- It also reduces environmental impact due to lower emissions.
- Consumption rates can be calculated for individual trips or average use over time.
In connection with our example, fuel consumption was determined through the equation\[x \text{ gallons} = \frac{389 \text{ miles}}{18 \text{ miles per gallon}}\]After calculation, we find out we need approximately 21.61 gallons, which means buying 22 gallons to complete the 389-mile journey without worrying about running out of fuel.
Other exercises in this chapter
Problem 48
Can a temperature in "C ever have the same value in ' \(\mathrm{F} ?\)
View solution Problem 49
Olympic Mile An Olympic "mile" is actually 1500 m. What percentage is an Olympic mile of a U.S. mile \((5280 \mathrm{ft}) ?\)
View solution Problem 51
A single strand of natural silk may be as long as \(4.0 \times 10^{3} \mathrm{m}\) What is this length in miles?
View solution Problem 52
The speed of light in a vacuum is \(2.998 \times 10^{8} \mathrm{m} / \mathrm{s} .\) What is the speed of light in \(\mathrm{km} / \mathrm{h}\) ?
View solution