Problem 50
Question
A bucket of mass \(m\) is tied to a massless cable that is wrapped around the outer rim of a frictionless uniform pulley of radius \(R\) , similar to the system shown in Fig. \(9.32 .\) In terms of the stated variables, what must be the moment of inertia of the pulley so that it always has half as much kinetic energy as the bucket?
Step-by-Step Solution
Verified Answer
The moment of inertia of the pulley is \( \frac{1}{2} m R^2 \).
1Step 1: Understand the Problem
We are given a bucket with mass \(m\) tied to a massless cable around a frictionless pulley with radius \(R\). The problem asks us to find the moment of inertia \(I\) of the pulley so that it has half the kinetic energy of the bucket in terms of the given variables.
2Step 2: Set the Known Relationships
The kinetic energy of the bucket, which is moving linearly, is given by \( K_{b} = \frac{1}{2} m v^2 \), where \( v \) is the velocity. The kinetic energy of the pulley, which is rotating, is \( K_{p} = \frac{1}{2} I \omega^2 \). Given, \( K_{p} = \frac{1}{2} K_{b} \).
3Step 3: Express Angular Velocity
Since linear velocity \( v \) and angular velocity \( \omega \) are related by the radius \( R \) of the pulley, we use \( v = R \omega \). Hence, \( \omega = \frac{v}{R} \).
4Step 4: Substitute Relationships in Kinetic Energy
Substitute the expression for \( \omega \) into the kinetic energy of the pulley to make it in terms of \( v \): \( K_{p} = \frac{1}{2} I \left(\frac{v}{R}\right)^2 = \frac{1}{2} I \frac{v^2}{R^2} \).
5Step 5: Set up the Kinetic Energy Equation
Setting \( K_{p} = \frac{1}{2} K_{b} \), we get \( \frac{1}{2} I \frac{v^2}{R^2} = \frac{1}{2} \left(\frac{1}{2} m v^2\right) \). Simplifying gives \( \frac{1}{2} I \frac{v^2}{R^2} = \frac{1}{4} m v^2 \).
6Step 6: Solve for Moment of Inertia \(I\)
From the equation \( \frac{1}{2} I \frac{v^2}{R^2} = \frac{1}{4} m v^2 \), cancel out \( v^2 \) on both sides and solve for \( I \): \( \frac{1}{2} \frac{I}{R^2} = \frac{1}{4} m \), which simplifies to \( I = \frac{1}{2} m R^2 \).
Key Concepts
Kinetic EnergyLinear VelocityAngular Velocity
Kinetic Energy
Kinetic energy is a fundamental concept in physics that describes the energy of an object in motion. For any object with mass, if it's moving, it possesses kinetic energy. This energy is dependent both on the mass of the object and its velocity. The formula for kinetic energy is given by \[ K = \frac{1}{2} m v^2 \]where:
- \( K \) is the kinetic energy,
- \( m \) is the mass, and
- \( v \) is the velocity of the object.
Linear Velocity
Linear velocity represents the rate of change of an object's position over time, in a straight line. It's a vector quantity, meaning it has both magnitude and direction. For the bucket in the exercise, its linear velocity is crucial as its motion dictates many parts of the system's behavior. The speed of the bucket can be denoted as:\[ v = R \omega \]where \( \omega \) is the angular velocity of the pulley. Here, linear velocity and angular velocity are interdependent, affecting each other proportionally depending on the radius \( R \). When considering systems involving pulleys, ropes, or other mechanics, understanding linear velocity helps clarify how movement translates throughout a system, particularly in energy calculations.
Angular Velocity
Angular velocity describes how fast an object is rotating, denoted by \( \omega \), and is crucial in understanding rotary motion. It connects directly to linear velocity. The formula:\[ \omega = \frac{v}{R} \]links it to the linear velocity \( v \) of the bucket and the radius \( R \) of the pulley. Angular velocity is essential when assessing the kinetic energy of rotating systems, like the pulley in this exercise. This relationship underscores how rotational dynamics can be understood in terms of more familiar linear dynamics. To calculate the pulley’s kinetic energy, you use the angular velocity and moment of inertia, emphasizing the interconnectedness of these physical properties.
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