Problem 5
Question
Write both the parametric equations and the symmetric equations for the line through the given point parallel to the given vector. \((4,5,6),\langle 3,2,1\rangle\)
Step-by-Step Solution
Verified Answer
Parametric: \(x = 4 + 3t\), \(y = 5 + 2t\), \(z = 6 + t\); Symmetric: \(\frac{x-4}{3} = \frac{y-5}{2} = z-6\).
1Step 1: Identify Given Point and Direction Vector
We are given a point \((4, 5, 6)\) and a direction vector \(\langle 3, 2, 1 \rangle\). We will use these to write the parametric and symmetric equations of the line.
2Step 2: Write the Parametric Equations
The parametric equations of a line can be expressed as \(x = x_0 + at\), \(y = y_0 + bt\), \(z = z_0 + ct\), where \((x_0, y_0, z_0)\) is the point on the line and \(\langle a, b, c \rangle\) is the direction vector. Substituting the given point and vector, we have:\[ x = 4 + 3t \]\[ y = 5 + 2t \]\[ z = 6 + 1t \]
3Step 3: Write the Symmetric Equations
Symmetric equations are derived by eliminating the parameter \(t\) from the parametric equations. Setting each parametric equation equal to \(t\), we have:\[ t = \frac{x - 4}{3} \]\[ t = \frac{y - 5}{2} \]\[ t = z - 6 \]Thus, the symmetric equations can be written as:\[ \frac{x - 4}{3} = \frac{y - 5}{2} = z - 6 \]
Key Concepts
Symmetric EquationsDirection VectorLine EquationCoordinate Geometry
Symmetric Equations
Symmetric equations provide a concise and elegant way to describe lines in three-dimensional space. They are useful because they eliminate the parameter, making the relation between the coordinates more direct. By setting each component of the parametric equation equal to the same parameter \(t\), we derive the symmetric form. For the line through the point \((4, 5, 6)\) with the direction vector \(\langle 3, 2, 1 \rangle\), the symmetric equations are
- \(\frac{x - 4}{3} = \frac{y - 5}{2} = z - 6\)
Direction Vector
A direction vector is crucial when defining a line, especially in three-dimensional coordinate geometry. It shows the direction in which the line extends. Given a direction vector \(\langle a, b, c \rangle\), it tells us how much to move in each coordinate direction to step along the line. In our example, the direction vector is \(\langle 3, 2, 1 \rangle\).
- The number 3 indicates movement along the x-axis.
- The number 2 shows the shift on the y-axis.
- The number 1 provides the change on the z-axis.
Line Equation
The line equation in parametric form summarizes how we can reach any point on the line by varying the parameter \(t\). It uses a specific point on the line and a direction vector. In our parametric equations,
- \(x = 4 + 3t\)
- \(y = 5 + 2t\)
- \(z = 6 + 1t\)
- It clearly indicates both a specific point on the line (the starting point)
- Shows how to extend along the line (using the direction vector)
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, enables us to describe the geometric shapes using equations. By using numbers and equations, it offers a practical way to represent lines, curves, and other shapes in a coordinate system. In three-dimensional space, like in our example, it becomes crucial to understand how points, lines, and planes interact.
- Points are described by coordinates \((x, y, z)\).
- Lines use parametric and symmetric equations.
- Planes might be expressed with a certain equation \(Ax + By + Cz = D\).
Other exercises in this chapter
Problem 5
Change the following from Cartesian to spherical coordinates. (a) \((2,-2 \sqrt{3}, 4)\) (b) \((-\sqrt{2}, \sqrt{2}, 2 \sqrt{3})\)
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sketch the curve over the indicated domain for \(t\). Find \(\mathbf{v}, \mathbf{a}, \mathbf{T}\), and \(\kappa\) at the point where \(t=t_{1} .\) $$ \mathbf{r}
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Find the required limit or indicate that it does not exist. $$ \lim _{t \rightarrow 0}\left[\frac{\sin t \cos t}{t} \mathbf{i}-\frac{7 t^{3}}{e^{t}} \mathbf{j}+
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Find the unit vectors perpendicular to the plane determined by the three points \((1,3,5),(3,-1,2)\), and \((4,0,1)\).
View solution