Problem 5
Question
Write balanced equations for the reactions of (a) metallic sodium with water, (b) metallic sodium with methanol, (c) sodium hydride with water, and (d) sodium hydride with ethanol.
Step-by-Step Solution
Verified Answer
Write balanced equations for (a) 2Na + 2H₂O → 2NaOH + H₂, (b) 2Na + 2CH₃OH → 2CH₃ONa + H₂, (c) NaH + H₂O → NaOH + H₂, and (d) NaH + C₂H₅OH → C₂H₅ONa + H₂.
1Step 1: Reaction of Metallic Sodium with Water
When sodium (Na) reacts with water (H₂O), it produces sodium hydroxide (NaOH) and hydrogen gas (H₂). The balanced chemical equation is:\[2 \, \text{Na} + 2 \, \text{H}_2\text{O} \rightarrow 2 \, \text{NaOH} + \text{H}_2 \uparrow\]
2Step 2: Reaction of Metallic Sodium with Methanol
Sodium reacts with methanol (CH₃OH) to form sodium methoxide (CH₃ONa) and hydrogen gas (H₂). The balanced chemical equation is:\[2 \, \text{Na} + 2 \, \text{CH}_3\text{OH} \rightarrow 2 \, \text{CH}_3\text{ONa} + \text{H}_2 \uparrow\]
3Step 3: Reaction of Sodium Hydride with Water
Sodium hydride (NaH) reacts with water to produce sodium hydroxide (NaOH) and hydrogen gas (H₂). The balanced chemical equation is:\[\text{NaH} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \uparrow\]
4Step 4: Reaction of Sodium Hydride with Ethanol
Sodium hydride reacts with ethanol (C₂H₅OH) to produce sodium ethoxide (C₂H₅ONa) and hydrogen gas (H₂). The balanced chemical equation is:\[\text{NaH} + \text{C}_2\text{H}_5\text{OH} \rightarrow \text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \uparrow\]
Key Concepts
Balancing Chemical EquationsSodium ReactionsSodium Hydride Reactions
Balancing Chemical Equations
Balancing chemical equations is an essential skill in chemistry that ensures the same number of atoms for each element are present on both sides of a reaction. This is crucial because it adheres to the law of conservation of mass, stating that matter cannot be created or destroyed. When balancing an equation, you adjust the coefficients (numbers before the molecules) to achieve balance, but the subscripts within a chemical formula must remain unchanged.
Here's a simple step-by-step approach to balance an equation:
Here's a simple step-by-step approach to balance an equation:
- Identify each element present in the reactants and products.
- List the number of atoms of each element on both sides of the equation.
- Use coefficients to balance the elements, starting with the most complex molecule.
- Check your work to confirm that the number of atoms for each element is equal on both sides.
Sodium Reactions
Sodium, a highly reactive metal, is known for its vigorous reactions, especially with water and alcohols such as methanol. These reactions release hydrogen gas, which is highly flammable. When sodium interacts with water, for example:For the reaction of sodium with water:
- The balanced equation is: \[ 2 \, \text{Na} + 2 \, \text{H}_2\text{O} \rightarrow 2 \, \text{NaOH} + \text{H}_2 \, \uparrow \]
- Sodium hydroxide (NaOH) and hydrogen gas (\( \text{H}_2 \)) are formed.
- This reaction is exothermic, meaning it releases heat.
- Sodium exchanges places with the hydrogen in methanol, creating sodium methoxide (\( \text{CH}_3\text{ONa} \)) and hydrogen gas.
- The balanced equation is: \[ 2 \, \text{Na} + 2 \, \text{CH}_3\text{OH} \rightarrow 2 \, \text{CH}_3\text{ONa} + \text{H}_2 \, \uparrow \]
Sodium Hydride Reactions
Sodium hydride (NaH) is an ionic compound, where sodium donates an electron to hydrogen. It's less reactive than metallic sodium but still capable of vigorous reactions, especially with water and alcohols.For sodium hydride reacting with water:
- The balanced chemical equation is: \[ \text{NaH} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \, \uparrow \]
- Sodium hydroxide and hydrogen gas are produced, similar to the reaction of metallic sodium with water.
- The reaction releases hydrogen gas, which may require safety precautions due to its flammability.
- Sodium hydride reacts with ethanol to form sodium ethoxide (\( \text{C}_2\text{H}_5\text{ONa} \)) and hydrogen gas.
- Balanced equation: \[ \text{NaH} + \text{C}_2\text{H}_5\text{OH} \rightarrow \text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \, \uparrow \]
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