Problem 5
Question
Write an equation in \(x\) and \(y\) that results in the desired transformation. Do not use a calculator. The absolute value function, vertically stretched by applying a factor of 3 and reflected across the \(x\) -axis
Step-by-Step Solution
Verified Answer
The equation is \( y = -3|x| \).
1Step 1: Understanding Standard Formula
The standard form for the absolute value function is given by \( y = |x| \). Our goal is to apply a vertical stretch and reflection.
2Step 2: Applying Vertical Stretch
To stretch the absolute value function vertically by a factor of 3, we multiply the whole function by 3. This leads to the equation \( y = 3|x| \).
3Step 3: Reflecting Across x-axis
To reflect the function across the x-axis, multiply the entire equation by -1. This transforms the equation to \( y = -3|x| \).
4Step 4: Final Equation
Combining both transformations, the final equation representing the desired transformation is \( y = -3|x| \).
Key Concepts
Vertical StretchReflection Across x-axisAbsolute Value Function
Vertical Stretch
A vertical stretch involves making a graph steeper or 'taller'. When we vertically stretch a function, we multiply the entire function by a positive constant greater than 1. In our situation, this factor is 3. This means each point on the graph moves three times further from the x-axis, giving it that 'stretched' look.
Consider the absolute value function, which typically looks like a 'V' centered at the origin of a graph. When vertically stretched by a factor of 3, the equation is altered from the standard form of \(y = |x|\) to \(y = 3|x|\).
Here are some key points about vertical stretching:
Consider the absolute value function, which typically looks like a 'V' centered at the origin of a graph. When vertically stretched by a factor of 3, the equation is altered from the standard form of \(y = |x|\) to \(y = 3|x|\).
Here are some key points about vertical stretching:
- The graph of the function is transformed by pulling it away from the x-axis.
- Only affects the y-values of the graph, while x-values remain unchanged.
- The larger the factor, the steeper or more stretched the graph will appear.
Reflection Across x-axis
When a function is reflected across the x-axis, every point on the graph is flipped over the x-axis to the opposite side. This can be visualized as flipping the graph upside down.
Mathematically, to achieve a reflection across the x-axis, we multiply the function by -1. This action changes the equation from \(y = 3|x|\) to \(y = -3|x|\).
Here's what happens during a reflection across the x-axis:
Mathematically, to achieve a reflection across the x-axis, we multiply the function by -1. This action changes the equation from \(y = 3|x|\) to \(y = -3|x|\).
Here's what happens during a reflection across the x-axis:
- The y-values of the function change sign (positive values become negative and vice versa).
- The x-values stay the same, maintaining the shape of the graph but inverting its position vertically.
- This reflection gives a 'mirror image' of the original graph across the x-axis.
Absolute Value Function
The absolute value function is one of the most basic yet important functions in algebra. It is expressed as \(y = |x|\) and resembles a 'V' shape when graphed, with its vertex at the origin (0,0). The absolute value of a number is its distance from zero, so it is always non-negative.
Here are some essential points about the absolute value function:
Here are some essential points about the absolute value function:
- The graph always forms a 'V' shape.
- The vertex of the graph is the pivot point and it lies at the origin.
- It reflects points on the left of the y-axis onto the right and vice versa due to the nature of absolute value.
Other exercises in this chapter
Problem 5
Let \(f(x)=x^{2}\) and \(g(x)=2 x-5 .\) Match each function in Group I with the correct expression in Group $I$$$I$$$$(f \circ g)(x)$$$$\mathbf{II}$$$$A.\quad4
View solution Problem 5
For each piecewise-defined function, find (a) \(f(-5),\) (b) \(f(-1)\) (c) \(f(0),\) and (d) \(f(3) .\) Do not use a calculator. $$f(x)=\left\\{\begin{array}{ll
View solution Problem 6
Let \(f(x)=x^{2}\) and \(g(x)=2 x-5 .\) Match each function in Group I with the correct expression in Group $I$$$I$$$$(g \circ f)(x)$$ $$\mathbf{II}$$$$A.\quad4
View solution Problem 6
For each piecewise-defined function, find (a) \(f(-5),\) (b) \(f(-1)\) (c) \(f(0),\) and (d) \(f(3) .\) Do not use a calculator. $$f(x)=\left\\{\begin{array}{ll
View solution