Problem 5
Question
Use the product rule to multiply. See Example \(I\). \(\sqrt[3]{4} \cdot \sqrt[3]{9}\)
Step-by-Step Solution
Verified Answer
The product is \(\sqrt[3]{36}\); it is already simplified.
1Step 1: Understanding the Problem
We have the expression \(\sqrt[3]{4} \cdot \sqrt[3]{9}\). Our task is to multiply these two cube roots using the product rule for radicals, which states that \(\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}\) if \(n\) is the same for both radicals.
2Step 2: Apply the Product Rule
According to the product rule for radicals, we can multiply the expressions inside the roots. Therefore, we use \(\sqrt[3]{4} \cdot \sqrt[3]{9} = \sqrt[3]{4 \cdot 9}\). Simplifying the multiplication inside the cube root: \(4 \cdot 9 = 36\). So, the expression is now \(\sqrt[3]{36}\).
3Step 3: Simplify the Expression
To simplify \(\sqrt[3]{36}\), we need to determine if 36 has a perfect cube factor. The prime factorization of 36 is \(36 = 2^2 \times 3^2\). This doesn't directly give a perfect cube, so \(\sqrt[3]{36}\) is the simplified form since 36 itself isn't a perfect cube.
Key Concepts
Cube RootsRadicalsSimplifying Expressions
Cube Roots
Understanding cube roots is crucial when working with expressions involving radicals. A cube root of a number is another number that, when multiplied by itself three times, results in the original number. It's denoted as \( \sqrt[3]{x} \). So, for example, \( \sqrt[3]{8} = 2 \) because 2 multiplied by itself three times results in 8.
- Cube roots are closely related to cube numbers, like 1, 8, 27, 64, etc.
- Not every number has a whole number as its cube root.
Radicals
Radicals are expressions that include roots, such as square roots or cube roots. The symbol \( \sqrt{ } \) represents a radical, and the small number to the left (if present) is what type of root it is.
It's important when dealing with radicals to remember their relationship with exponents. Roots can be converted into fractional exponents, which can often make them easier to manipulate in algebraic operations. Understanding radicals is a key skill in algebra that helps in simplifying expressions and solving complex equations more intuitively.
- Square root: \( \sqrt{4} = 2 \)
- Cube root is shown as \( \sqrt[3]{27} = 3 \)
It's important when dealing with radicals to remember their relationship with exponents. Roots can be converted into fractional exponents, which can often make them easier to manipulate in algebraic operations. Understanding radicals is a key skill in algebra that helps in simplifying expressions and solving complex equations more intuitively.
Simplifying Expressions
Simplifying expressions involves rewriting them in a more concise, clearer, or standard form. When working with radicals, simplifying often means reducing the expression inside the root as much as possible.
Simplification is crucial because it reduces the complexity of problems. It helps to lay the groundwork for more advanced mathematical manipulations and ensures results are expressed as simply as possible, making them easier to interpret and use in real-world applications. Always strive to simplify where you can for a clearer mathematical solution.
- Identifying and factoring out perfect powers, such as perfect squares or cubes, makes simplification easier.
- Use the properties of radicals: \( \sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab} \).
Simplification is crucial because it reduces the complexity of problems. It helps to lay the groundwork for more advanced mathematical manipulations and ensures results are expressed as simply as possible, making them easier to interpret and use in real-world applications. Always strive to simplify where you can for a clearer mathematical solution.
Other exercises in this chapter
Problem 5
Use radical notation to write each expression. Simplify if possible. $$ \left(\frac{1}{16}\right)^{1 / 4} $$
View solution Problem 5
Simplify. See Example 1. $$ -\sqrt{16} $$
View solution Problem 5
Add or subtract. $$ 2 \sqrt{50}-3 \sqrt{125}+\sqrt{98} $$
View solution Problem 5
Solve. \(\sqrt{2 x}=-4\)
View solution