Problem 5
Question
The second degree Taylor polynomial for \(f(x)=(1+x)^{p}\) is \(1+p x+\frac{p(p-1)}{2 !} x^{2} .\) If the second degree Taylor polynomial is used to approximate \(\sqrt{1+x}\) for \(|x| \leq 0.2\), nd an upper bound for the magnitude of the error. Use the Taylor Inequality; then check your answer by graphing \(R_{2}(x)\).
Step-by-Step Solution
Verified Answer
The upper bound for the magnitude of the error, when using the second degree Taylor polynomial to approximate \(\sqrt{1+x}\), is approximately 0.004.
1Step 1: Find the third derivative of \(f(x)\)
Start with the function \(f(x) = (1+x)^p\). The first derivative is \(f'(x) = p(1+x)^{p-1}\) through the power rule. The second derivative is then \(f''(x) = p(p-1)(1+x)^{p-2}\), again using the power rule. The third derivative, which is needed for the Taylor Approximation formula, is \(f'''(x) = p(p-1)(p-2)(1+x)^{p-3}\). In the case of approximating \(\sqrt{1+x}\), set \(p = 1/2\) to get \(f'''(x) = (-3/8)(1+x)^{-5/2}\).
2Step 2: Find the maximum of the third derivative in \([-0.2, 0.2]\)
For \(|x|\leq 0.2\), the maximum of the absolute value of the third derivative will occur at the endpoint \(x = -0.2\). Plug this into \(f'''(x)\) to get \(|f'''(x)| = |-3/8(-1.2)^{-5/2}| = 5.8838.\
3Step 3: Use Taylor Inequality to approximate the error
The Taylor inequality states that the error of using the nth degree Taylor polynomial to approximate a function is less than or equal to (M / (n+1)!) * |x - a|^(n+1), where M is the maximum of the (n+1)th derivative on the interval and a is the point around which the Taylor polynomial is centered (in this case, a = 0). Here, the Taylor polynomial is second degree, so n = 2 and \(M = 5.8838\). Plugging these in gives an error less than or equal to \(5.8838 / (3!) * 0.2^{3}\), which equals 0.003922533333 or roughly 0.004.
4Step 4: Check the answer with a graph of \(R_{2}(x)\)
To confirm whether the theoretical answer is reasonable, check with a graph of \(R_{2}(x)\), which is the remainder term of the second degree Taylor polynomial. If the graph and the calculated error from Step 3 agree (i.e. the maximum value of \(R_{2}(x)\) in \([-0.2, 0.2]\) is around 0.004), then it validates the answer.
Key Concepts
Taylor seriesError estimationPower ruleDerivative calculation
Taylor series
The Taylor series is a mathematical concept used to approximate complex functions with simpler polynomial forms. It expands a function into an infinite sum of terms calculated from the values of its derivatives at a single point. For example, for a function \( f(x) \) centered at \( a \), the Taylor series is given by:
- \( f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \ldots \)
Error estimation
Error estimation in the context of Taylor series is crucial as it allows us to understand how far off our polynomial approximation is from the true value of a function. The error, also known as the remainder, is the difference between the actual function and its Taylor polynomial approximation. An effective way to bound this error is using Taylor's Inequality, which states that:
- The error of an \( n \)-th degree Taylor polynomial is \( \leq \frac{M}{(n+1)!} |x-a|^{n+1} \).
Power rule
The power rule is a simple and essential rule in calculus for differentiating functions of the form \( x^n \). The rule states:
- The derivative of \( x^n \) is \( n \cdot x^{n-1} \).
- The first derivative: \( f'(x) = p(1+x)^{p-1} \)
- The second derivative: \( f''(x) = p(p-1)(1+x)^{p-2} \)
- The third derivative: \( f'''(x) = p(p-1)(p-2)(1+x)^{p-3} \)
Derivative calculation
Derivative calculation is a core skill in calculus and is integral for finding both the Taylor series and error estimation. In the process of building a Taylor polynomial, derivatives at a specific point provide the coefficients for each term of the polynomial. In our exercise:
- We begin with the function \( f(x) = (1+x)^p \) and find its higher-order derivatives.
- For \( p = 1/2 \) representing \( \sqrt{1+x} \), we compute the first three derivatives using the power rule.
- Each derivative is evaluated to help form the second degree Taylor polynomial and for calculating the error bound using Taylor's Inequality.
Other exercises in this chapter
Problem 5
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