Problem 5
Question
The quadratic in \(t\), such that \(\mathrm{A} \cdot \mathrm{M}\). of its roots in \(A\) and G.M. is \(G\), is (a) \(t^{2}-2 A t+G^{2}=0\) (b) \(t^{2}-2 A t-G^{2}=0\) (c) \(t^{2}+2 A t+G^{2}=0\) (d) none of these
Step-by-Step Solution
Verified Answer
The correct quadratic equation is (a) \( t^2 - 2At + G^2 = 0 \).
1Step 1: Understanding the Problem
We are given that the Arithmetic Mean (A) and the Geometric Mean (G) of the roots of a quadratic equation are known. We need to form the corresponding quadratic equation.
2Step 2: Recall the Concepts of AM and GM
For a quadratic equation with roots \( \alpha \) and \( \beta \), the Arithmetic Mean of the roots is \( A = \frac{\alpha + \beta}{2} \), and the Geometric Mean is \( G = \sqrt{\alpha \beta} \).
3Step 3: Formulate AM Equation
From the AM, we can write \( \alpha + \beta = 2A \).
4Step 4: Formulate GM Equation
From the GM, we can express \( \alpha \beta = G^2 \) since \( G = \sqrt{\alpha \beta} \).
5Step 5: Write the Standard Quadratic Equation
The standard form for a quadratic equation with roots \( \alpha \) and \( \beta \) is \( t^2 - (\alpha + \beta)t + \alpha \beta = 0 \).
6Step 6: Substitute AM and GM into the Equation
By substituting \( \alpha + \beta = 2A \) and \( \alpha \beta = G^2 \), the equation becomes \( t^2 - 2At + G^2 = 0 \).
7Step 7: Conclusion
The quadratic equation that fits the given conditions is \( t^2 - 2At + G^2 = 0 \), matching option (a).
Key Concepts
Understanding the Arithmetic MeanGrasping the Geometric MeanIdentifying the Roots of a Quadratic EquationFormulating a Quadratic Equation
Understanding the Arithmetic Mean
The Arithmetic Mean (AM) is a fundamental concept in mathematics and is often referred to as the "average". This calculation helps us determine what the 'average' value in a data set is. When considering the roots of a quadratic equation, let's denote these roots as \( \alpha \) and \( \beta \). The arithmetic mean gives us an idea of where the middle of these values lies. For two numbers, like our roots, the arithmetic mean is calculated as:
- \( A = \frac{\alpha + \beta}{2} \)
Grasping the Geometric Mean
The Geometric Mean (GM) is another useful concept, especially when dealing with two numbers that can be related multiplicatively. Unlike the arithmetic mean, which is concerned with the sum of values, the geometric mean considers their product. Given the same roots \( \alpha \) and \( \beta \) of a quadratic equation, the geometric mean is calculated as:
- \( G = \sqrt{\alpha \beta} \)
Identifying the Roots of a Quadratic Equation
Roots of a quadratic equation are simply the values of \( t \) that satisfy the equation \( at^2 + bt + c = 0 \). In our equation \( t^2 - 2At + G^2 = 0 \), these roots can be represented as \( \alpha \) and \( \beta \). The roots are important because they provide the values that make the quadratic equation true. By using the formulas for arithmetic and geometric means, we have already linked roots to certain numerical expressions. Specifically, the sum of the roots \( \alpha + \beta = 2A \) and the product \( \alpha \beta = G^2 \).To find these roots, we solve the quadratic equation by various methods, like factoring, using the quadratic formula, or completing the square. However, because we use an equation derived from known means, the roots \( \alpha \) and \( \beta \) abide by these relationships inherently due to the design of the equation.
Formulating a Quadratic Equation
Formulating a quadratic equation using its roots is an orderly process consisting of different steps that stem from the relationship between the equation and its roots. We can start forming such an equation using the convolution of these steps:Firstly, recall that any quadratic equation can be expressed as \( t^2 - (\alpha + \beta)t + \alpha \beta = 0 \). In this form, the expression \( \alpha + \beta \) represents the total sum of the roots, while \( \alpha \beta \) represents their product.
- Given \( \alpha + \beta = 2A \), substitute it into the equation for the sum of the roots.
- Given \( \alpha \beta = G^2 \), replace the product in the equation with this expression.
Other exercises in this chapter
Problem 4
If \(x\) is real, then the maximum and minimum values of the expression \(\frac{x^{2}-3 x+4}{x^{2}+3 x+4}\) will be (a) 2,1 (b) \(5,1 / 5\) (c) \(7,1 / 7\) (d)
View solution Problem 5
If \(\alpha, \beta\) are roots of the quadratic equation \(x^{2}\) \(+p x+p^{2}+q=0\), then prove that \(\alpha^{2}+\alpha \beta+\) \(\beta^{2}+q=0\)
View solution Problem 6
If both roots of equations \(K\left(6 x^{2}+3\right)+r x+\) \(2 x^{2}-1=0\) and \(6 K\left(2 x^{2}+1\right)+p x+4 x^{2}-2=\) 0 are common, then prove that \(2 r
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Let \(f(x)=x^{2}+4 x+1\), then (a) \(f(x)>0\) for all \(x\) (b) \(f(x)>1\) when \(x \geq 0\) (c) \(f(x) \geq 1\) when \(x \leq-4\) (d) \(f(x)=f(-x)\) for all \(
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