Problem 5
Question
The maximum number of possible oxidation states of actinoides are shown by: (a) Nobelium (No) and lawrencium (Lr) (b) Actinium (Ac) and thorium (Th) (c) Berkelium (Bk) and californium (Cf) (d) Neptunium (Np) and plutonium (Pu)
Step-by-Step Solution
Verified Answer
The answer is (d) Neptunium (Np) and Plutonium (Pu).
1Step 1: Understand the Problem
The question asks us to identify the actinides that exhibit the maximum number of possible oxidation states. Actinides are elements found in the actinide series, and key examples are those that have
multiple oxidation states due to their electron configurations.
2Step 2: List Known Oxidation States
Review the common oxidation states for the actinides mentioned in the options:
- Nobelium (No) typically shows +2 and +3 states.
- Lawrencium (Lr) typically shows a +3 state.
- Actinium (Ac) shows a +3 state.
- Thorium (Th) shows +4 state predominantly.
- Berkelium (Bk) shows +3 and +4 states.
- Californium (Cf) shows +3 and +4 states.
- Neptunium (Np) exhibits +3, +4, +5, +6, and +7 states.
- Plutonium (Pu) exhibits +3, +4, +5, and +6 states.
3Step 3: Compare the Possible Oxidation States
Compare the oxidation states from Step 2. Neptunium (Np) has the widest array of oxidation states ranging from +3 to +7. Plutonium (Pu) also has multiple states but fewer than neptunium. Both have more variety compared to the others.
4Step 4: Select the Correct Answer
Based on Step 3 observations, Neptunium (Np) and Plutonium (Pu) show the maximum number of oxidation states compared to other options.
Key Concepts
Oxidation statesNeptuniumPlutoniumElectron configurations
Oxidation states
Oxidation states are like different sets of clothes an element can wear, depending on how it interacts with other elements. They tell us how many electrons an atom loses, gains, or shares when it forms chemical bonds. In simple terms, the oxidation state is a number that represents an atom's degree of oxidation.
Actinides, which are elements with atomic numbers from 89 to 103, can have multiple oxidation states. This flexibility is mainly due to their electron configurations. Many actinides, like neptunium and plutonium, can exhibit a wide range of oxidation states, enabling them to form various compounds. For example:
- Neptunium (Np) has oxidation states from +3 to +7.
- Plutonium (Pu) typically displays +3, +4, +5, and +6 states.
Neptunium
Neptunium (Np) is an intriguing element with several unique characteristics. It's the first transuranic element, meaning it comes right after uranium on the periodic table.
- Neptunium can have oxidation states of +3, +4, +5, +6, and even as high as +7.
- This wide range makes neptunium quite versatile in chemical reactions.
Plutonium
Plutonium (Pu) is another fascinating actinide, renowned for its use in nuclear power and weapons. It has a rich chemistry due to its multiple oxidation states, making it very reactive.
- Plutonium commonly exhibits oxidation states of +3, +4, +5, and +6.
- In each state, plutonium forms different types of compounds, influencing its reactivity and interactions.
Electron configurations
Electron configurations describe the arrangement of electrons in an element's atom. For the actinides like neptunium and plutonium, the electron configuration plays a significant role in their chemical properties.
- Actinides have electrons filling the 5f orbitals, which are more complex than the simpler s, p, or d orbitals.
- This complex filling leads to multiple possible oxidation states.
Other exercises in this chapter
Problem 4
The electronic configurations of bivalent europium and trivalent cerium are: (atomic number : \(\mathrm{Xe}=54, \mathrm{Ce}=58, \mathrm{Eu}=63\) ) (a) \([\mathr
View solution Problem 5
Thermal decomposition of a Mn compound (X) at \(513 \mathrm{~K}\) results in compound \(\mathrm{Y}, \mathrm{MnO}_{2}\) and a gaseous product. \(\mathrm{MnO}_{2}
View solution Problem 6
The lanthanide ion that would show colour is : (a) \(\mathrm{Gd}^{3+}\) (b) \(\mathrm{Sm}^{3+}\) (c) \(\mathrm{La}^{3+}\) (d) \(\mathrm{Lu}^{3+}\)
View solution Problem 7
The INCORRECT statement is : (a) the gemstone, ruby, has \(\mathrm{Cr}^{3+}\) ions occupying the octahedral sites of beryl. (b) the spin-only magnetic moment of
View solution