Problem 5
Question
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summary chart in this section. Do not use a calculator. $$x-1=-3(y-4)^{2}$$
Step-by-Step Solution
Verified Answer
The equation represents a parabola that opens to the left.
1Step 1: Identify the General Form
The given equation is \( x - 1 = -3(y - 4)^2 \). This equation resembles the standard form of a conic section. To identify the type of conic, we need to compare it with the standard forms.
2Step 2: Standard Form for Parabolas
In conic sections, a parabola can be expressed in the form \((x - h)^2 = 4p(y - k)\) or \((y - k)^2 = 4p(x - h)\). The given equation resembles the latter, i.e., \( (y - k)^2 = 4p(x - h) \) with transformations.
3Step 3: Match the Equation to Parabola Form
Rewriting the given equation, \( x - 1 = -3(y - 4)^2 \), we see it matches the form \((y - k)^2 = 4p(x - h)\) if we solve for \(x\): \( y - 4 = \pm \sqrt{\frac{x - 1}{-3}} \). The negative sign before the \(3\) indicates a parabola that opens horizontally and to the left.
4Step 4: Determine Type of Conic Section
Since the equation fits the pattern \((y - k)^2 = 4p(x - h)\), this indicates it is a parabola. The negative coefficient \(-3\) implies that the parabola opens leftward.
Key Concepts
ParabolaEquation TransformationGraph Analysis
Parabola
A parabola is a specific type of conic section with a distinct U-shaped curve. It can open upwards, downwards, left, or right, based on the orientation of the equation. When we talk about parabolas, we often refer to their standard forms:
For instance, in the given equation \(x - 1 = -3(y - 4)^2\), we identify that it fits the structure of a horizontal parabola. The signs and coefficients inform us more about its orientation and movement.
- Vertical parabolas: \((x - h)^2 = 4p(y - k)\)
- Horizontal parabolas: \((y - k)^2 = 4p(x - h)\)
For instance, in the given equation \(x - 1 = -3(y - 4)^2\), we identify that it fits the structure of a horizontal parabola. The signs and coefficients inform us more about its orientation and movement.
Equation Transformation
Equation transformation is a key concept in recognizing and rewriting expressions to better understand their geometrical properties. The given equation \(x - 1 = -3(y - 4)^2\) needs some tweaking to reveal its underlying conic form.
By transforming the equation, we rewrite it as \((y - 4) = \pm \sqrt{\frac{(x - 1)}{-3}}\), showcasing its relationship to the standard parabola form \((y - k)^2 = 4p(x - h)\).
By transforming the equation, we rewrite it as \((y - 4) = \pm \sqrt{\frac{(x - 1)}{-3}}\), showcasing its relationship to the standard parabola form \((y - k)^2 = 4p(x - h)\).
- The presence of the square root indicates the dependency on \(x\), aligning with a horizontal orientation.
- Moreover, the negative sign in front of 3 points to the direction the parabola opens, which is towards the left.
Graph Analysis
Although the task doesn't require graphing, understanding how the equation relates to a graph is crucial in identifying its attributes. In graph analysis, the vertex \((h, k)\) is the focal point, guiding us in visualizing direction and shape.
The transformation derived: \(y - 4 = \pm \sqrt{\frac{x - 1}{-3}}\) corresponds to a leftward-opening parabola with a vertex at \((1, 4)\). This information tells us:
The transformation derived: \(y - 4 = \pm \sqrt{\frac{x - 1}{-3}}\) corresponds to a leftward-opening parabola with a vertex at \((1, 4)\). This information tells us:
- The vertex, situated at \(x = 1\) and \(y = 4\), acts as the starting point for the parabola.
- The negative coefficient indicates horizontal westward movement, which opposes the usual right or up directions.
Other exercises in this chapter
Problem 4
Match each equation with the appropriate description . Do not use a calculator. $$y^{2}=-3 x$$ A. Circle; center \((3,-4) ;\) radius 5 B. Parabola; opens left C
View solution Problem 5
Graph each pair of parametric equations by hand, using values of tin \([-2,2] .\) Make a table of \(t_{*}, x_{*}\) and \(y\) -values, using \(t=-2,-1,0,1,\) and
View solution Problem 5
Match each equation with the appropriate description . Do not use a calculator. $$x^{2}+y^{2}=5$$ A. Circle; center \((3,-4) ;\) radius 5 B. Parabola; opens lef
View solution Problem 6
Graph each pair of parametric equations by hand, using values of tin \([-2,2] .\) Make a table of \(t_{*}, x_{*}\) and \(y\) -values, using \(t=-2,-1,0,1,\) and
View solution