Problem 5
Question
$$ \text { Find the frequency of electromagnetic radiation with energy } 5.50 \times 10^{-26} \mathrm{~J} \text { . } $$
Step-by-Step Solution
Verified Answer
The frequency of the electromagnetic radiation is \(8.30 \times 10^7 \text{ Hz}\).
1Step 1: Recall the Energy-Frequency Formula
To find the frequency of electromagnetic radiation from its energy, we use the formula \(E = h \cdot f\), where \(E\) is the energy, \(h\) is the Planck's constant \(6.626 \times 10^{-34} \text{ J s}\), and \(f\) is the frequency. This formula relates the energy of photons to their frequency.
2Step 2: Rearrange the Formula to Isolate Frequency
Rearrange the equation \(E = h \cdot f\) to solve for the frequency \(f\). This gives \(f = \frac{E}{h}\). This rearrangement allows us to plug in the energy value and Planck's constant to find the frequency.
3Step 3: Substitute Values into the Equation
Substitute the given energy \(E = 5.50 \times 10^{-26} \text{ J}\) and Planck's constant \(h = 6.626 \times 10^{-34} \text{ J s}\) into the equation \(f = \frac{E}{h}\). This gives \(f = \frac{5.50 \times 10^{-26}}{6.626 \times 10^{-34}}\).
4Step 4: Calculate the Frequency
Perform the calculation \(f = \frac{5.50 \times 10^{-26}}{6.626 \times 10^{-34}}\). Divide \(5.50\) by \(6.626\), and subtract the exponents \(-26\) and \(-34\) to determine \(f = 8.30 \times 10^7 \text{ Hz}\). This result gives us the frequency in hertz.
Key Concepts
Energy-Frequency RelationshipPlanck's ConstantPhoton Energy
Energy-Frequency Relationship
Electromagnetic radiation, like light, carries energy. This energy is connected to the frequency of the waves. How? Through the formula: \(E = h \cdot f\). Here, \(E\) stands for energy, \(h\) is Planck's constant, and \(f\) is the frequency of the electromagnetic waves.
This relationship tells us that when frequency increases, energy also increases. Conversely, if you know the energy of electromagnetic radiation, you can determine its frequency by rearranging the formula to \(f = \frac{E}{h}\).
Understanding this relationship is crucial:
This relationship tells us that when frequency increases, energy also increases. Conversely, if you know the energy of electromagnetic radiation, you can determine its frequency by rearranging the formula to \(f = \frac{E}{h}\).
Understanding this relationship is crucial:
- The larger the frequency, the more energetic the radiation.
- High-frequency radiation (like X-rays) carries more energy than low-frequency radiation (like radio waves).
Planck's Constant
Planck's constant, denoted as \(h\), is a fundamental constant in quantum mechanics. Its value is approximately \(6.626 \times 10^{-34} \text{ J s}\). It serves as a bridge between the wave and particle natures of light.
Plank's constant:
Plank's constant:
- Is essential in calculating photon energy.
- Works as a proportionality factor in the energy-frequency relationship of electromagnetic radiation.
- It's tiny because energy at atomic scales is typically small.
- Controls the smallest packet of energy that can be emitted or absorbed as electromagnetic radiation - the photon.
Photon Energy
Photons are packets of electromagnetic energy. The energy of a photon is directly related to its frequency, as described by the equation \(E = h \cdot f\).
This simple relationship reveals:
This simple relationship reveals:
- Photon energy increases with increasing frequency.
- The energy of each photon is a tiny but significant amount, crucial for quantum physics.
- A higher-energy gamma-ray photon has a higher frequency than an infrared photon.
- Every color of light corresponds to photons with specific energy based on their frequency.
Other exercises in this chapter
Problem 4
$$ \text { Find the frequency of electromagnetic radiation with energy } 2.00 \times 10^{-24} \mathrm{~J} \text { . } $$
View solution Problem 4
$$ \begin{aligned} &c=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} \\ &f=24.2 \mathrm{MHz} \\ &\lambda=? \end{aligned} $$
View solution Problem 5
$$ \begin{aligned} &c=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} \\ &f=45.6 \mathrm{MHz} \\ &\lambda=? \end{aligned} $$
View solution Problem 6
$$ \begin{aligned} &\text { Find the energy of a photon of electromagnetic radiation with frequency }\\\ &2.50 \times 10^{12} \mathrm{~Hz} \end{aligned} $$
View solution