Problem 5
Question
Suppose that \(X\) is normally distributed with mean \(\mu\) and variance \(\sigma^{2}\). Calculate $$ \mathbb{E}\left[e^{\theta X}\right] $$ and hence evaluate \(\mathbb{E}\left[X^{4}\right]\).
Step-by-Step Solution
Verified Answer
\(\mathbb{E}[e^{\theta X}] = e^{\mu \theta + \frac{1}{2} \sigma^2 \theta^2}\) and \(\mathbb{E}[X^4] = 3\sigma^4 + 6\sigma^2\mu^2 + \mu^4\).
1Step 1: Define the Moment Generating Function (MGF)
The moment generating function (MGF) of a random variable provides a way to find moments. For a normal random variable \(X\) with mean \(\mu\) and variance \(\sigma^2\), the MGF is \(M_X(t) = \mathbb{E}\left[e^{tX}\right] = e^{\mu t + \frac{1}{2} \sigma^2 t^2}\). This is the starting point to calculate \(\mathbb{E}\left[e^{\theta X}\right]\).
2Step 2: Substitute \(\theta\) into the MGF
Substitute \(t = \theta\) into the MGF expression to get \(M_X(\theta) = \mathbb{E}\left[e^{\theta X}\right] = e^{\mu \theta + \frac{1}{2} \sigma^2 \theta^2}\). This gives us the desired expected value of the exponential function.
3Step 3: Differentiate the MGF to Find Moments
Finding the moments involves differentiating the MGF. The \(n\)-th moment is obtained by differentiating the MGF \(n\) times with respect to \(t\) and evaluating at \(t = 0\). To find \(\mathbb{E}[X^4]\), we need the fourth derivative of the MGF.
4Step 4: Compute the First Four Derivatives
1. First derivative: \( \frac{d}{dt} M_X(t) = (\mu + \sigma^2 t) e^{\mu t + \frac{1}{2} \sigma^2 t^2} \) 2. Second derivative: \( \frac{d^2}{dt^2} M_X(t) = (\sigma^2 + (\mu + \sigma^2 t)^2) e^{\mu t + \frac{1}{2} \sigma^2 t^2} \) 3. Third derivative: \( \frac{d^3}{dt^3} M_X(t) = (3\sigma^2 (\mu + \sigma^2 t) + (\mu + \sigma^2 t)^3) e^{\mu t + \frac{1}{2} \sigma^2 t^2} \) 4. Fourth derivative: \( \frac{d^4}{dt^4} M_X(t) = (3\sigma^4 + 6 \sigma^2 (\mu + \sigma^2 t)^2 + (\mu + \sigma^2 t)^4) e^{\mu t + \frac{1}{2} \sigma^2 t^2} \).
5Step 5: Evaluate the Fourth Derivative at 0
Evaluate the fourth derivative at \(t = 0\): \( \frac{d^4}{dt^4} M_X(t) \bigg|_{t=0} = (3\sigma^4 + 6 \sigma^2 \mu^2 + \mu^4) e^{0} = 3\sigma^4 + 6\sigma^2\mu^2 + \mu^4 \). This is \(\mathbb{E}[X^4]\).
Key Concepts
Normal DistributionExpectationVarianceHigher Moments
Normal Distribution
Understanding normal distribution is key to comprehending the behavior of many natural phenomena. Also known as the Gaussian distribution, it is a continuous probability distribution that is symmetric about the mean. A normal distribution is characterized by two parameters:
Statistical methods assume normality because of its convenient mathematical properties, making normal distribution foundational in probability and statistics.
- Mean (\(\mu\)): This is the peak center of the distribution curve and determines its position on the horizontal axis.
- Variance (\(\sigma^2\)): This measures the spread or width of the distribution curve. A larger variance implies a wider curve.
Statistical methods assume normality because of its convenient mathematical properties, making normal distribution foundational in probability and statistics.
Expectation
The expectation of a random variable, often referred to as the expected value or mean, is a forecast of the variable's probable average outcome. It is denoted by \(\mathbb{E}[X]\), representing the average value you would anticipate \(X\) obtaining per trial if the trials could be repeated infinitely. For a normally distributed random variable, the expectation or mean is \(\mu\).
By understanding expectation, one can predict outcomes and make informed decisions based on probabilistic data.
- This mean serves as the central tendency of the distribution.
- It's a crucial indicator for understanding the distribution's location on the horizontal axis.
By understanding expectation, one can predict outcomes and make informed decisions based on probabilistic data.
Variance
Variance is a measure of the spread or dispersion within a set of data. It quantifies the degree of variation of data points from the mean. The formula for variance is:\[\sigma^2 = \mathrm{Var}(X) = \mathbb{E}[(X - \mu)^2]\]where:
Understanding variance is integral for risk assessment and statistical inference, helping to predict and understand variability in datasets.
- \(\sigma^2\) is the variance.
- \(X\) is the random variable.
- \(\mu\) is the mean of the distribution.
Understanding variance is integral for risk assessment and statistical inference, helping to predict and understand variability in datasets.
Higher Moments
Higher moments of a distribution provide deeper insights into its shape and characteristics beyond the basic mean and variance. They capture more details about the distribution's behavior.1. **Third Moment (Skewness):** Skewness measures asymmetry of the probability distribution of a real-valued random variable about its mean. Skewness can be:
- Zero (mean = median = mode) indicating a perfectly symmetrical distribution.
- Positive (right skewed) indicating longer tails to the right.
- Negative (left skewed) indicating longer tails to the left.
- A higher kurtosis means more of the variance is due to infrequent extreme deviations.
- Normal distribution has a kurtosis of 3 (mesokurtic).
Other exercises in this chapter
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