Problem 5
Question
Solve the inequality \(|6-3 x|<18\) and sketch the solution on the real number line.
Step-by-Step Solution
Verified Answer
Answer: The solution set for the inequality \(|6-3x|<18\) is the open interval \((-4, 8)\).
1Step 1: Break the inequality into two cases
Consider the two cases for the absolute value:
1) \(6 - 3x \ge 0 \Rightarrow 6-3x < 18\)
2) \(6 - 3x < 0 \Rightarrow -(6-3x) < 18\)
2Step 2: Solve each case
Now, let's solve each case:
1) \(6-3x < 18\)
Subtract 6 from both sides:
\(-3x < 12\)
Divide by -3 (notice that we need to flip the inequality sign since we're dividing by a negative number):
\(x > -4\)
2) \(-(6-3x) < 18\)
Distribute the negative sign:
\(-6+3x < 18\)
Add 6 to both sides:
\(3x < 24\)
Divide by 3:
\(x < 8\)
3Step 3: Union of the solutions
Now, we'll take the union of the solutions for each case. In other words, we need to consider the values of x that satisfy either case:
\(x > -4\) or \(x < 8\)
This means that the solution for the inequality \(|6-3 x|<18\) is the open interval \((-4, 8)\).
4Step 4: Sketch the real number line
To sketch the solution on the real number line, we need to represent the interval \((-4, 8)\) by drawing a line and highlighting the region between -4 and 8 with open circles at both end-points. An example sketch is shown below:
```
------(----------)---------------
-5 -4 8 10
```
In this sketch, the parentheses at -4 and 8 indicate open circles, meaning the end-points are not included in the solution. The highlighted region between -4 and 8 shows all values of x that satisfy the inequality.
Key Concepts
Solving InequalitiesReal Number LineInterval Notation
Solving Inequalities
Inequalities are similar to equations, but instead of an equal sign, they use symbols such as ">", "<", "≥", or "≤". In this problem, the inequality involves an absolute value expression, which requires a unique approach.
Consider \(|6 - 3x| < 18\). Since absolute value denotes distance from zero, the inequality translates to ensuring the expression inside falls within a certain range relative to zero.
For this, we break down the inequality into two cases:
The first case gives \(x > -4\), and the second yields \(x < 8\). Combining these informs us that \(x\) exists between these two values.
Consider \(|6 - 3x| < 18\). Since absolute value denotes distance from zero, the inequality translates to ensuring the expression inside falls within a certain range relative to zero.
For this, we break down the inequality into two cases:
- One where \(6 - 3x\) is positive or zero, leading to \(6 - 3x < 18\).
- The other where \(6 - 3x\) is negative, translating to \(- (6 - 3x) < 18\).
The first case gives \(x > -4\), and the second yields \(x < 8\). Combining these informs us that \(x\) exists between these two values.
Real Number Line
Visualizing inequalities is often aided by sketches or diagrams. The real number line is a key tool here, stretching infinitely in both directions, representing all real numbers as points.
When sketching \((-4, 8)\) on the real number line, our focus is on illustrating which values of \(x\) meet the inequality's conditions:
When sketching \((-4, 8)\) on the real number line, our focus is on illustrating which values of \(x\) meet the inequality's conditions:
- Numbers between \(-4\) and \(8\) are marked.
- Open circles at \(-4\) and \(8\) indicate these endpoints are not part of the solution.
Interval Notation
Interval notation is a concise and standardized way to express ranges of numbers. Rather than writing an inequality with cumbersome symbols, interval notation provides a cleaner statement of which values are included.
For the solution \((-4, 8)\), this type of notation uses parentheses to denote a range excluding the endpoints, known as an 'open interval.'
For the solution \((-4, 8)\), this type of notation uses parentheses to denote a range excluding the endpoints, known as an 'open interval.'
- Use \( (, )\) for solutions excluding endpoints, a hallmark of open intervals.
- A closed interval uses brackets \[ [, ]\] to indicate inclusivity.
- Mixed sets utilize both when solutions include one endpoint but not the other.
Other exercises in this chapter
Problem 2
The vertices of a triangle are \(A(-2,0), B(0,6),\) and \(C(4,0) .\) Find an equation of a line containing the median from vertex \(A\) to \(\overline{B C}\).
View solution Problem 3
Write an equation of a circle whose center is at (2,-3) and tangent to the line \(y=-1\)
View solution Problem 6
Given \(f(x)=x^{2}+3 x,\) find \(\frac{f(x+h)-f(x)}{h}\) in simplest form.
View solution Problem 7
Determine which of the following equations represent \(y\) as a function of \(x\) : (1) \(x y=-8\) (2) \(4 x^{2}+9 y^{2}=36\) (3) \(3 x^{2}-y=1\) (4) \(y^{2}-x^
View solution