Problem 5
Question
Solve each of the equations. $$\frac{x}{3}=\frac{5}{2}$$
Step-by-Step Solution
Verified Answer
The solution is \( x = \frac{15}{2} \).
1Step 1: Understand the Equation
We are given the equation \( \frac{x}{3} = \frac{5}{2} \). This is a simple proportion where \( x \) is divided by 3, and it equals \( \frac{5}{2} \). Our goal is to solve for \( x \).
2Step 2: Cross-Multiply to Eliminate Fractions
To solve for \( x \), we can eliminate the fractions by cross-multiplying: \( 2 \cdot x = 5 \cdot 3 \). This simplifies the equation, allowing us to solve directly for \( x \).
3Step 3: Simplify the Result
After performing the cross-multiplication, we simplify the equation: \( 2x = 15 \).
4Step 4: Solve for x
To isolate \( x \), divide both sides of the equation by 2: \( x = \frac{15}{2} \). This is our final solution.
Key Concepts
Solving EquationsCross-MultiplicationProportionsLinear Equations
Solving Equations
Solving equations is a fundamental skill in algebra. Equations are statements that express equality between two expressions. They can include numbers, variables (like \( x \)), and mathematical operations such as addition or multiplication. Our objective when solving an equation is to find the value of the variable that makes the equation true. This process often involves several steps:
Understanding how to navigate and simplify each part of an equation is the key to becoming proficient at solving them.
- Simplify both sides: Break down complex expressions into more manageable parts by simplifying or combining like terms.
- Isolate the variable: Use inverse operations to get the variable by itself on one side of the equation. This usually involves adding, subtracting, multiplying, or dividing both sides of the equation.
- Check your solution: Substitute the value back into the original equation to ensure it satisfies the equation.
Understanding how to navigate and simplify each part of an equation is the key to becoming proficient at solving them.
Cross-Multiplication
Cross-multiplication is a technique used to eliminate fractions from an equation, making it easier to solve. When you have an equation in the form of a proportion, like \( \frac{x}{a} = \frac{b}{c} \), cross-multiplication involves multiplying the numerator of one fraction by the denominator of the other and vice versa. Here's how it works in simple steps:
- Multiply the numerator of the first fraction (\( x \)) by the denominator of the second fraction (\( c \))
- Multiply the denominator of the first fraction (\( a \)) by the numerator of the second fraction (\( b \))
- Set these two products equal to each other: \( xc = ab \)
Proportions
Proportions describe a relationship between two ratios or fractions. A proportion states that two ratios are equivalent. For example, \( \frac{x}{y} = \frac{a}{b} \) expresses that the ratio of \( x \) to \( y \) is the same as the ratio of \( a \) to \( b \). Proportions are powerful in solving problems where one set of quantities is compared to another, allowing you to predict one value if others are known. Here are some common applications:
- Recipe Adjustments: If a recipe ratios ingredients to servings, you can adjust the numbers to serve more or fewer people while maintaining taste.
- Map Work: Map scales are proportions that help translate distances on a map to real-life distances.
- Scaling Models: Architects and engineers use proportions to create scale models, maintaining accurate relationships between dimensions.
Linear Equations
Linear equations are a type of equation where the highest power of the variable is 1. They can often be written in the form \( ax + b = c \), where \( x \) is the variable, \( a \), \( b \), and \( c \) are constants. These equations create straight lines when graphed, and are characterized by consistent rates of change. To solve a linear equation, you follow a series of steps:
- Combine like terms on each side of the equation if necessary.
- Move variable terms to one side of the equation and constants to the other.
- Divide or multiply to isolate the variable and solve for it.
Other exercises in this chapter
Problem 5
For Problems \(1-10\), solve for the specified variable using the given facts. (Objective 1) $$ \text { Solve } \mathrm{F}=\frac{9}{5} \mathrm{C}+32 \text { for
View solution Problem 5
Solve each of the equations. $$0.62-y=0.14$$
View solution Problem 6
For Problems 1-12, solve each equation. You will be using these types of equations in Problems \(13-41\). $$ 0.8(25)-x=0.7(25-x) $$
View solution Problem 6
For Problems \(1-12\), solve each of the equations. These equations are the types you will be using in Problems 13-40. $$ 800(0.11) t=1600 $$
View solution