Problem 5
Question
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$2^{2 x-1}=32$$
Step-by-Step Solution
Verified Answer
The solution to the equation \( 2^{2x -1} = 32 \) is \( x = 3 \).
1Step 1: Express Right Hand Side as Power of 2
The first step is to express 32 as a power of 2. We know that \( 32 = 2^5 \) , so the equation becomes \( 2^{2x-1} = 2^5 \).
2Step 2: Set Exponents Equal
In step 2, once the bases are the same, we can equate the exponents. The equation becomes \( 2x - 1 = 5 \).
3Step 3: Solve for \( x \)
Finally, in step 3, solve the equation for \( x \). First, add 1 to both sides to get \( 2x = 6 \). Then divide both sides by 2 to obtain \( x = 3 \).
Other exercises in this chapter
Problem 4
Write each equation in its equivalent exponential form. $$2=\log _{9} x$$
View solution Problem 4
Approximate each number using a calculator. Round your answer to three decimal places. $$5^{\sqrt{3}}$$
View solution Problem 5
Use properties of logarithms to expand logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator.
View solution Problem 5
Write each equation in its equivalent exponential form. $$5=\log _{b} 32$$
View solution