Problem 5
Question
Sketch the graph of a function that is continuous everywhere except at \(x=3\) and is continuous from the left at \(3 .\)
Step-by-Step Solution
Verified Answer
A piecewise function: \( f(x) = x \) for \( x < 3 \), \( f(x) = 3 \) at \( x = 3 \), and \( f(x) = x + 1 \) for \( x > 3 \).
1Step 1: Identify Discontinuity
We need a function that is continuous everywhere except at a single point, which is specified as \(x=3\). This means there must be some form of discontinuity at \(x=3\).
2Step 2: Choose a Function Type
A suitable choice for such functions is a piecewise function, which defines the function differently in different intervals while introducing a discontinuity at \(x=3\).
3Step 3: Define the Left-side Continuity
Ensure the function is continuous from the left at \(x=3\). This means \(\lim\limits_{x \to 3^-} f(x) = f(3)\). Choose the left-side function to be a simple linear function, such as \(f(x) = x\), applicable for \(x < 3\). Set \(f(3) = 3\) to ensure left-side continuity.
4Step 4: Define the Right-side of the Function
To introduce discontinuity at \(x=3\), the right-side function can be different from the left. Example: let \(f(x) = x + 1\) for \(x > 3\). Then, \(\lim\limits_{x \to 3^+} f(x) = 4\), creating a discontinuity as \(4 eq 3\).
5Step 5: Sketch the Graph
On a graph, draw a straight line for \(f(x) = x\) on the left side of \(x=3\) including the point \((3,3)\). Draw a different line for \(f(x) = x+1\) starting just after \(x=3\), which does not include the point \((3,4)\). There should be an open circle at \((3,4)\) indicating the discontinuity point.
Key Concepts
DiscontinuityPiecewise FunctionsLimits and Continuity
Discontinuity
A discontinuity in a function occurs when there is a sudden break or jump in the graph of the function. In our problem, the discontinuity happens at the point where the curve of the function breaks at \(x=3\). This means the function is not smooth at this particular point. There are different types of discontinuities, such as:
- Jump Discontinuity: This occurs when the left-hand and right-hand limits at a point exist but are not equal. Our example has a jump discontinuity at \(x=3\) because the left limit approaches 3, but the right limit approaches 4, causing a break or jump in the graph.
- Removable Discontinuity: This happens when a single point is undefined on the function's graph, but the function is otherwise continuous.
- Infinite Discontinuity: This happens when the function approaches infinity at a certain point.
Piecewise Functions
Piecewise functions are excellent tools for defining different behaviors of a function over various intervals. They are composed of multiple functions, each applying to a different span of the domain. In our exercise, we constructed a piecewise function to handle discontinuity:
- The function is defined as \(f(x) = x\) for values less than \(x=3\).
- For \(x=3\), we set \(f(3) = 3\). This ensures the function connects smoothly from the left, keeping the function continuous from this direction.
- For values greater than \(x=3\), the function changes to \(f(x) = x+1\). This creates the needed discontinuity since it results in a different value than the left-side function, namely \(4\) when approaching from the right side.
Limits and Continuity
The concept of limits is essential when discussing the continuity of a function. A limit helps us understand the behavior of a function as it approaches a specific point. When we say a function is continuous at \(x=3\), we mean that the left-hand limit, the value of the function at \(3\), and the right-hand limit all coincide at that point. However, if any of these values differ, a discontinuity is present.
- Left-hand limit: \( \lim\limits_{x \to 3^-} f(x) = 3 \). This is the limit as the function approaches \(x=3\) from values less than \(3\), which in our function, matches the defined value of the function at \(3\).
- Right-hand limit: \( \lim\limits_{x \to 3^+} f(x) = 4 \). This is the limit as the function approaches \(x=3\) from values greater than \(3\), which differs in our setup, creating the discontinuity.
Other exercises in this chapter
Problem 5
\(5-8\) Find an equation of the tangent line to the curve at the given point. $$y=\frac{x-1}{x-2}, \quad(3,2)$$
View solution Problem 5
Evaluate the limit and justify each step by indicating the appropriate Limit Law(s). $$\lim _{x \rightarrow 8}(1+\sqrt[3]{x})\left(2-6 x^{2}+x^{3}\right)$$
View solution Problem 6
If a rock is thrown upward on the planet Mars with a velocity of \(10 \mathrm{m} / \mathrm{s},\) its height in meters t seconds later is given by \(\mathrm{y}=1
View solution Problem 6
\(5-8\) Find an equation of the tangent line to the curve at the given point. $$y=2 x^{3}-5 x,(-1,3)$$
View solution