Problem 5
Question
Simplify the expression. $$\frac{x}{x^{2}-25} \cdot \frac{x-5}{x+5}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \( \frac{x}{x+5}\)
1Step 1: Factorize the quadratic expression
The quadratic expression \(x^{2}-25\) can be factorized into \( (x-5)(x+5) \), since \(x^{2}-25\) is a difference of two squares, and can be written as \( (x)^2 - (5)^2 \).
2Step 2: Replace the quadratic expression with its factorized form
Now the given problem can be rewritten by replacing the quadratic expression \(x^{2}-25\) with its factorized form \( (x-5)(x+5) \). So it becomes, \(\frac{x}{(x-5)(x+5)} \cdot \frac{(x-5)}{(x+5)}\).
3Step 3: Cancel out common factors
In the expression \(\frac{x}{(x-5)(x+5)} \cdot \frac{(x-5)}{(x+5)}\), we see that \(x-5\) and \(x+5\) are present in the numerator and the denominator. These are common factors, and we hence cancel these out. After cancelling, we obtain the simplified expression as \( \frac{x}{x+5}\).
Other exercises in this chapter
Problem 5
Find the least common denominator. \(\frac{5}{x}, \frac{2}{3 x^{2}}, \frac{1}{x^{3}}\)
View solution Problem 5
Solve the proportion. Check your solution. $$ \frac{4}{x+1}=\frac{7}{2} $$
View solution Problem 5
Simplify the expression. If not possible, write already in simplest form. $$ \frac{16}{128 c} $$
View solution Problem 6
Does the equation model direct variation, inverse variation, or neither? $$ x=\frac{4}{y} $$
View solution