Problem 5

Question

Perform the matrix operation, or if it is impossible, explain why. $$ 3\left[\begin{array}{rr}{1} & {2} \\ {4} & {-1} \\ {1} & {0}\end{array}\right] $$

Step-by-Step Solution

Verified
Answer
The resulting matrix is \(\begin{array}{rr} 3 & 6 \\ 12 & -3 \\ 3 & 0 \end{array}\).
1Step 1: Understand the Matrix and Scalar
The given matrix is \[\begin{array}{rr}1 & 2 \4 & -1 \1 & 0\end{array}\]and the scalar to multiply the matrix by is 3. This means we will multiply each element of the matrix by 3.
2Step 2: Multiply Each Element
We perform the operation by multiplying each element in the matrix by the scalar 3. - The element in the first row and first column becomes \(3 \cdot 1 = 3\).- The element in the first row and second column becomes \(3 \cdot 2 = 6\).- The element in the second row and first column becomes \(3 \cdot 4 = 12\).- The element in the second row and second column becomes \(3 \cdot -1 = -3\).- The element in the third row and first column becomes \(3 \cdot 1 = 3\).- The element in the third row and second column becomes \(3 \cdot 0 = 0\).
3Step 3: Write the Resulting Matrix
After multiplying each element by 3, the resulting matrix is\[\begin{array}{rr}3 & 6 \12 & -3 \3 & 0\end{array}\]This is the final transformation of the initial matrix by the scalar 3.

Key Concepts

Matrix OperationsScalar MultiplicationElement-wise Multiplication
Matrix Operations
Matrix operations are a type of mathematical processes that involve matrices, which are rectangular arrays of numbers. These operations allow us to manipulate and transform matrices in various ways. One common matrix operation is scalar multiplication, which involves multiplying every element of a matrix by the same number, known as a scalar. Matrices can have different sizes, often referred to by their "rows" and "columns" count, and knowing this size is important for understanding how different operations can be performed.

Another common operation is matrix addition, where matrices of the same size can be added by simply adding corresponding elements to each other. Matrix multiplication is also important, but it is not as straightforward as it involves dot products. Understanding matrix operations is crucial, as they form the base for many complex calculations in linear algebra, and are widely used in fields like physics, computer graphics, and statistics.
Scalar Multiplication
Scalar multiplication is the simplest of matrix operations. When we talk about scalar multiplication, we mean multiplying every element of a matrix by a single number, known as a scalar. This is done element-by-element, meaning each entry in the matrix gets multiplied by the scalar independently.

The process of scalar multiplication is straightforward:
  • Start with a matrix and a scalar.
  • Multiply each element of the matrix by the scalar.
  • Replace the original matrix element with the new value.
This operation changes the size, but not the structure of the matrix. For example, multiplying the matrix \(\begin{bmatrix}1 & 2 \4 & -1 \1 & 0\end{bmatrix}\) by the scalar 3 results in \(\begin{bmatrix}3 & 6 \12 & -3 \3 & 0\end{bmatrix}\).

Scalar multiplication is widely used for adjusting the magnitude of a matrix's elements and is essential in many mathematical applications.
Element-wise Multiplication
Element-wise multiplication, sometimes known as the Hadamard product, involves multiplying corresponding elements of two matrices of the same size. This operation is different from traditional matrix multiplication, which involves a more complex calculation involving rows and columns.
  • Both matrices must have the same dimensions.
  • Each element in the resulting matrix is the product of corresponding elements in the input matrices.
Element-wise multiplication is often used in tasks like filtering images or applying weights to datasets. It's essential to distinguish it from matrix multiplication, as confusing the two can lead to significant errors in calculations.

In contrast to scalar multiplication, element-wise multiplication requires two matrices, and each product is calculated independently for each position in the matrix. Understanding this operation is key for applications where pairwise interactions are needed within data sets.