Problem 5
Question
Perform each indicated operation. Simplify if possible. \(\frac{3}{x}+\frac{5}{2 x^{2}}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{6x + 5}{2x^2} \).
1Step 1: Identify the fractions
The expression is made up of two fractions: \( \frac{3}{x} \) and \( \frac{5}{2x^2} \). Our goal is to add these fractions.
2Step 2: Find a common denominator
To add fractions, they must have the same denominator. The denominators are \( x \) and \( 2x^2 \). The least common denominator (LCD) of these is \( 2x^2 \).
3Step 3: Adjust the fractions
Convert each fraction to have the LCD \( 2x^2 \) as its denominator. Multiply the numerator and denominator of \( \frac{3}{x} \) by \( 2x \) to get \( \frac{6x}{2x^2} \). The fraction \( \frac{5}{2x^2} \) already has the correct denominator.
4Step 4: Add the fractions
Now that both fractions have the same denominator, add the numerators: \( \frac{6x + 5}{2x^2} \).
5Step 5: Simplify the expression
Check if the numerator can be simplified. In this case, \( 6x + 5 \) cannot be factored further to cancel out with the denominator, so the expression remains \( \frac{6x + 5}{2x^2} \).
Key Concepts
Least Common DenominatorAdding FractionsSimplifying Expressions
Least Common Denominator
When working with algebraic fractions, just like with numerical fractions, you need a common denominator to add or subtract them. The **least common denominator (LCD)** is the smallest expression that all denominators can divide into without remainder. For this exercise, the fractions are \( \frac{3}{x} \) and \( \frac{5}{2x^2} \), with denominators \( x \) and \( 2x^2 \), respectively. To find the LCD:
- List the distinct variables and constants in the denominators: here we have \( x \) and \( 2 \).
- Take the highest power of each variable present in the denominators: \( 2x^2 \) includes both \( 2 \) and \( x^2 \).
- This gives us the LCD of \( 2x^2 \). All terms in each fraction can now be aligned using this common denominator.
Adding Fractions
Once the least common denominator is determined, you can focus on transforming each fraction to have this denominator before combining them. For the fractions \( \frac{3}{x} \) and \( \frac{5}{2x^2} \), you need each to share the denominator \( 2x^2 \).Steps to align denominators:
- Multiply both the top (numerator) and bottom (denominator) of \( \frac{3}{x} \) by \( 2x \) to get \( \frac{6x}{2x^2} \). Note that we multiply by \( 2x \) because \( x \cdot 2x = 2x^2 \), which matches our LCD.
- The fraction \( \frac{5}{2x^2} \) already has this common denominator, so no changes are necessary for it.
Combining the Fractions
Simply add the numerators over the common denominator. After adjustment, the expression is \( \frac{6x}{2x^2} + \frac{5}{2x^2} \), and adding these gives \( \frac{6x + 5}{2x^2} \). Always verify that numerators are correctly combined as mistakes can happen.Simplifying Expressions
Once the fractions are added and combined into a single expression, the next step is **simplifying**. To simplify a fraction, check if the numerator and denominator have common factors that can be cancelled. In our expression \( \frac{6x + 5}{2x^2} \), we aim to simplify the numerator.Steps to check for simplification:
- Examine the numerator and see if it can be factored. In this case, \( 6x + 5 \) is a simple binomial that cannot be factored further.
- Look at both the numerator and the denominator for any common factors. Here, there are none common to both \( 6x + 5 \) and \( 2x^2 \).
- If there are no common factors, the fraction is already in its simplest form.
Other exercises in this chapter
Problem 5
Solve each equation and check each solution. See Examples 1 through 3. $$ 2-\frac{8}{x}=6 $$
View solution Problem 5
Solve each proportion. $$ \frac{x+1}{2 x+3}=\frac{2}{3} $$
View solution Problem 6
$$ \frac{8 y}{y-2}-\frac{16}{y-2} $$
View solution Problem 6
Find the value of the following expressions when \(x=2, y=-2,\) and \(z=-5\). $$ \frac{x+5}{x^{2}+4 x-8} $$
View solution