Problem 5
Question
\(\mathrm{f} 0<\alpha<\beta<\frac{\pi}{2}\) then (A) \(\frac{\tan \beta}{\tan \alpha}<\frac{\alpha}{\beta}\) (B) \(\frac{\tan \beta}{\tan \alpha}>\frac{\alpha}{\beta}\) (C) \(\frac{\tan \alpha}{\tan \beta}<\frac{\alpha}{\beta}\) (D) \(\frac{\tan \alpha}{\tan \beta}>\frac{\alpha}{\beta}\)
Step-by-Step Solution
Verified Answer
Option (B): \( \frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta} \).
1Step 1: Understand the Inequalities
The inequality involves comparing two fractions \( \frac{\tan \beta}{\tan \alpha} \) and \( \frac{\alpha}{\beta} \). We need to determine the relationship between \( \tan \alpha \), \( \tan \beta \), \( \alpha \), and \( \beta \), knowing that \( 0 < \alpha < \beta < \frac{\pi}{2} \).
2Step 2: Analyze the Behavior of the Tan Function
Since the function \( \tan \theta \) is increasing in the interval \( (0, \frac{\pi}{2}) \), we conclude that \( \tan \alpha < \tan \beta \) whenever \( \alpha < \beta \). This fact is fundamental to the inequality comparisons.
3Step 3: Compare the Two Fractions
We need to compare \( \frac{\tan \beta}{\tan \alpha} \) and \( \frac{\alpha}{\beta} \). Since \( \tan \beta > \tan \alpha \) (because \( \beta > \alpha \)), the fraction \( \frac{\tan \beta}{\tan \alpha} \) is greater than 1, whereas \( \frac{\alpha}{\beta} < 1 \) since \( \alpha < \beta \). Thus, \( \frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta} \).
4Step 4: Choose the Correct Option
With the conclusion from Step 3, we determine that the correct inequality is \( \frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta} \), which corresponds to option (B).
Key Concepts
Tan Function BehaviorInequality ComparisonsAngle Relationships in Trigonometry
Tan Function Behavior
The tangent function, denoted as \(\tan \theta\), plays an integral role in trigonometry. One crucial aspect to understand is that it is an increasing function in the interval \((0, \frac{\pi}{2})\). This means that as the angle \(\theta\) increases within this range, the value of \(\tan \theta\) also increases. This behavior is especially important when looking at inequalities, such as the relationship between \(\tan \alpha\) and \(\tan \beta\), given that \(\alpha<\beta\).
For any angles \(0 < \alpha < \beta < \frac{\pi}{2}\), we know that:
For any angles \(0 < \alpha < \beta < \frac{\pi}{2}\), we know that:
- \(\tan \alpha < \tan \beta\)
- This implies the function's increasing nature as the angle grows nearer to \(\frac{\pi}{2}\)
Inequality Comparisons
When tackling trigonometric inequalities, especially like those involving tangent, the key lies in comparing the relationships between ratios or fractions. In the given problem, we compare \(\frac{\tan \beta}{\tan \alpha}\) with \(\frac{\alpha}{\beta}\).
Here are some steps to consider in such comparisons:
Here are some steps to consider in such comparisons:
- First, recognize that since \(\tan \beta > \tan \alpha\) for \(\beta > \alpha\), \(\frac{\tan \beta}{\tan \alpha} > 1\).
- Secondly, because \(\frac{\alpha}{\beta} < 1\) (as \(\alpha < \beta\)), you're comparing something greater than 1 with something less than 1.
- This establishes that \(\frac{\tan \beta}{\tan \alpha}\) is clearly greater than \(\frac{\alpha}{\beta}\), affirming an important inequality difference due to the non-linear growth of the tan function compared to linear angles.
Angle Relationships in Trigonometry
Understanding angle relationships is fundamental in trigonometry especially when you're dealing with trigonometric functions like tangent. For angles \(\alpha\) and \(\beta\) where \(0 < \alpha < \beta < \frac{\pi}{2}\), several relationships become apparent.
Here's what we know about these angles:
Here's what we know about these angles:
- All angles within \((0, \frac{\pi}{2})\) are positive, making trigonometric functions like tangent, positive too.
- Since \(\alpha < \beta\), geometrically, this implies that the line segment associated with \(\beta\) is longer than that associated with \(\alpha\).
- This length difference influences the tangent values, making \(\tan \beta > \tan \alpha\), directly tied to how these angles and their trigonometric functions relate to one another.
Other exercises in this chapter
Problem 3
The function \(f(x)=\frac{\sin x}{x}\) is decreasing in the interval (A) \(\left(-\frac{\pi}{2}, 0\right)\) (B) \(\left(0, \frac{\pi}{2}\right)\) (C) \((0, \pi)
View solution Problem 4
If \(a x+\frac{b}{x} \geq c\) for all positive \(x\), where \(a, b>0\), then (A) \(a b
View solution Problem 6
If \(a0\) (B) \(x1\) (D) \(x
View solution Problem 8
The values of \(k\) for which the function \(f(x)=k x^{3}-9 x^{2}+9 x+3\) may be increasing on \(R\) are (A) \(k>3\) (B) \(k
View solution