Problem 5
Question
List the possibilities for rational roots. $$4 x^{3}-9 x^{2}-15 x+3=0$$
Step-by-Step Solution
Verified Answer
Possible rational roots: \(\pm 1, \pm \frac{1}{2}, \pm \frac{1}{4}, \pm 3, \pm \frac{3}{2}, \pm \frac{3}{4}\).
1Step 1: Identify Coefficients and Constant Terms
In the polynomial \(4x^3 - 9x^2 - 15x + 3 = 0\), identify the leading coefficient \(a\) and the constant term \(b\). Here, \(a = 4\) and \(b = 3\).
2Step 2: List Factors of the Constant Term
Factors of the constant term \(3\) are \(\pm 1\) and \(\pm 3\). List these as possible numerators for rational roots.
3Step 3: List Factors of the Leading Coefficient
Factors of the leading coefficient \(4\) are \(\pm 1\), \(\pm 2\), and \(\pm 4\). List these as possible denominators for rational roots.
4Step 4: Form Possible Rational Roots
Using the Rational Root Theorem, possible rational roots are formed by the fraction of factors of the constant term over factors of the leading coefficient. Combine them to get: \(\pm 1, \pm \frac{1}{2}, \pm \frac{1}{4}, \pm 3, \pm \frac{3}{2}, \pm \frac{3}{4}\).
Key Concepts
Factors of Constant TermLeading CoefficientPossible Rational Roots
Factors of Constant Term
When dealing with polynomials, particularly in the context of the Rational Root Theorem, it's important to start by identifying the factors of the constant term. In our example polynomial, \(4x^3 - 9x^2 - 15x + 3 = 0\), the constant term is \(3\). The factors of a number are the integers that can divide it without leaving a remainder.
For \(3\), the factors are simple:
For \(3\), the factors are simple:
- \(+1\)
- \(-1\)
- \(+3\)
- \(-3\)
Leading Coefficient
The leading coefficient of a polynomial is the coefficient of the term with the highest degree. It's usually represented by the letter \(a\) in expressions like \(ax^n + bx^{n-1} + ...\).
In the polynomial equation \(4x^3 - 9x^2 - 15x + 3 = 0\), the leading term is \(4x^3\). Thus, the leading coefficient is \(4\). Why is this significant? Because the factors of the leading coefficient serve as the denominators for the possible rational roots. Let's consider the factors of \(4\):
In the polynomial equation \(4x^3 - 9x^2 - 15x + 3 = 0\), the leading term is \(4x^3\). Thus, the leading coefficient is \(4\). Why is this significant? Because the factors of the leading coefficient serve as the denominators for the possible rational roots. Let's consider the factors of \(4\):
- \(+1\)
- \(-1\)
- \(+2\)
- \(-2\)
- \(+4\)
- \(-4\)
Possible Rational Roots
With the factors of both the constant term and the leading coefficient in hand, we can use the Rational Root Theorem to determine the possible rational roots of the polynomial. The theorem states that any possible rational root, expressed as a fraction \(\frac{p}{q}\), must have:
- \(p\) as a factor of the constant term, \(3\)
- \(q\) as a factor of the leading coefficient, \(4\)
- \(+1\)
- \(-1\)
- \(\frac{1}{2}\)
- \(-\frac{1}{2}\)
- \(\frac{1}{4}\)
- \(-\frac{1}{4}\)
- \(+3\)
- \(-3\)
- \(\frac{3}{2}\)
- \(-\frac{3}{2}\)
- \(\frac{3}{4}\)
- \(-\frac{3}{4}\)
Other exercises in this chapter
Problem 5
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