Problem 5
Question
Let \(q_{1}\) and \(q_{2}\) be two relatively prime natural numbers. The Chinese Remainder Theorem claims that the natural homomorphism \(\mathbb{Z} / q_{1} q_{2} \mathbb{Z} \rightarrow \mathbb{Z} / q_{1} \mathbb{Z} \times \mathbb{Z} / q_{2} \mathbb{Z}\) is an isomorphism. Deduce from this that the natural homomorphism $$ \mathrm{GL}\left(2, \mathbb{Z} / q_{1} q_{2} \mathbb{Z}\right) \longrightarrow \mathrm{GL}\left(2, \mathbb{Z} / q_{1} \mathbb{Z}\right) \times \mathrm{GL}\left(2, \mathbb{Z} / q_{2} \mathbb{Z}\right) $$ is an isomorphism.
Step-by-Step Solution
Verified Answer
The isomorphism of \(\mathrm{GL}(2, \mathbb{Z} / q_1 q_2 \mathbb{Z})\) to \(\mathrm{GL}(2, \mathbb{Z} / q_1 \mathbb{Z}) \times \mathrm{GL}(2, \mathbb{Z} / q_2 \mathbb{Z})\) follows by applying the Chinese Remainder Theorem.
1Step 1: Understand the Chinese Remainder Theorem
The Chinese Remainder Theorem states that if \(q_1\) and \(q_2\) are relatively prime, then the natural homomorphism \(\mathbb{Z} / q_1 q_2 \mathbb{Z} \rightarrow \mathbb{Z} / q_1 \mathbb{Z} \times \mathbb{Z} / q_2 \mathbb{Z}\) is an isomorphism, meaning there is a one-to-one correspondence between these structures.
2Step 2: Understand General Linear Group
The group \(\mathrm{GL}(2, R)\), where \(R\) is a ring, consists of 2x2 invertible matrices over \(R\). The determinant of each matrix should be invertible within \(R\), implying it should not be divisible by any element that would make it zero in \(R\).
3Step 3: Apply Chinese Remainder Theorem to Matrices
The Chinese Remainder Theorem implies matrices over \(\mathbb{Z} / q_1 q_2 \mathbb{Z}\) can be uniquely reconstructed from matrices over \(\mathbb{Z} / q_1 \mathbb{Z}\) and \(\mathbb{Z} / q_2 \mathbb{Z}\). This means there exists a natural isomorphism from \(\mathrm{GL}(2, \mathbb{Z} / q_1 q_2 \mathbb{Z})\) to \(\mathrm{GL}(2, \mathbb{Z} / q_1 \mathbb{Z}) \times \mathrm{GL}(2, \mathbb{Z} / q_2 \mathbb{Z})\).
4Step 4: Show Isomorphism of General Linear Groups
Given that the Chinese Remainder Theorem provides a one-to-one correspondence for scalar multiplication and addition, it preserves matrix multiplication and inversion properties. Thus, this ensures the homomorphism \(\mathrm{GL}(2, \mathbb{Z} / q_1 q_2 \mathbb{Z}) \to \mathrm{GL}(2, \mathbb{Z} / q_1 \mathbb{Z}) \times \mathrm{GL}(2, \mathbb{Z} / q_2 \mathbb{Z})\) is injective and surjective, making it an isomorphism.
Key Concepts
Group TheoryGeneral Linear GroupHomomorphismIsomorphism
Group Theory
Group theory is the study of algebraic structures known as groups. A group is a set, combined with an operation that fulfills certain conditions. These conditions are: associativity, identity element presence, and the possibility of inversion for each element within the group. A classic example of a group is the set of integers under addition. For any integers a, b, and c, you have associativity since
In our case, group theory is essential as it deals with the structures of groups like the General Linear Group (GL) and how they transform under homomorphisms like those involved in the Chinese Remainder Theorem application.
- a + (b + c) = (a + b) + c
In our case, group theory is essential as it deals with the structures of groups like the General Linear Group (GL) and how they transform under homomorphisms like those involved in the Chinese Remainder Theorem application.
General Linear Group
The General Linear Group, denoted as \( \mathrm{GL}(n, R) \), is the group of invertible \( n \times n \) matrices with elements in a ring \( R \). Invertibility means a matrix possesses an inverse such that when the matrix is multiplied by its inverse, it results in the identity matrix.
This group includes all matrices whose determinants are non-zero, as a non-zero determinant indicates that an inverse matrix does exist.
In the context of solving the exercise, \( \mathrm{GL}(2, \mathbb{Z} / q_1 q_2 \mathbb{Z}) \) consists of all invertible \( 2 \times 2 \) matrices over integers modulo \( q_1 q_2 \), with similar interpretations for \( \mathrm{GL}(2, \mathbb{Z} / q_1 \mathbb{Z}) \) and \( \mathrm{GL}(2, \mathbb{Z} / q_2 \mathbb{Z}) \).
These groups allow for operations like matrix multiplication and inversion while respecting the modulo conditions specified by the respective rings.
This group includes all matrices whose determinants are non-zero, as a non-zero determinant indicates that an inverse matrix does exist.
In the context of solving the exercise, \( \mathrm{GL}(2, \mathbb{Z} / q_1 q_2 \mathbb{Z}) \) consists of all invertible \( 2 \times 2 \) matrices over integers modulo \( q_1 q_2 \), with similar interpretations for \( \mathrm{GL}(2, \mathbb{Z} / q_1 \mathbb{Z}) \) and \( \mathrm{GL}(2, \mathbb{Z} / q_2 \mathbb{Z}) \).
These groups allow for operations like matrix multiplication and inversion while respecting the modulo conditions specified by the respective rings.
Homomorphism
Homomorphism is a fundamental concept in abstract algebra. It is a structure-preserving map between two algebraic structures, such as groups, rings, or vector spaces.
To qualify as a homomorphism, a function must respect the operations of the structures involved. In the case of groups, this translates to preserving the group operation.
To qualify as a homomorphism, a function must respect the operations of the structures involved. In the case of groups, this translates to preserving the group operation.
- If you have a homomorphism \( \phi: G \rightarrow H\) between groups, and \(a, b \in G\),
- then the image of the product is the product of the images: \( \phi(ab) = \phi(a)\phi(b) \).
Isomorphism
Isomorphism is a special type of homomorphism which admits an inverse, thereby creating a one-to-one correspondence between structures. When two structures, say groups or rings, are isomorphic, it means they are equivalent in an algebraic sense, though they may appear different on the surface.
From the exercise, when applying the Chinese Remainder Theorem, we find that the homomorphism \( \mathbb{Z} / q_1 q_2 \mathbb{Z} \rightarrow \mathbb{Z} / q_1 \mathbb{Z} \times \mathbb{Z} / q_2 \mathbb{Z} \) is indeed an isomorphism, since it retains both injectivity and surjectivity.
From the exercise, when applying the Chinese Remainder Theorem, we find that the homomorphism \( \mathbb{Z} / q_1 q_2 \mathbb{Z} \rightarrow \mathbb{Z} / q_1 \mathbb{Z} \times \mathbb{Z} / q_2 \mathbb{Z} \) is indeed an isomorphism, since it retains both injectivity and surjectivity.
- This means every element in the source structure has a unique match in the target structure, and vice versa.
Other exercises in this chapter
Problem 4
Let \(p\) be a prime, and let \(m\) be a natural number. The kernel of the natural homomorphism $$ G L\left(2, Z / p^{m} Z\right) \longrightarrow G \mathrm{~L}\
View solution Problem 5
Any meromorphic modular form is representable as a quotient of two entire modular forms.
View solution Problem 6
Express the EisENSTEIN series \(G_{4}\) and \(G_{6}\) as polynomials in \(\vartheta^{4}, \bar{\vartheta}^{4}\) and \(\overline{\bar{y}}^{4}\) Hint. The searched
View solution Problem 4
For any point \(a \in \mathbb{H}\) there exists an entire modular form (even of weight 12 ), which vanishes at \(a\), but does not vanish identically. Hint. Use
View solution