Problem 5
Question
Let \(A=\left[\begin{array}{rrrr}-2 & 4 & 2 & 6 \\ -1 & -1 & 5 & 0\end{array}\right], B=\left[\begin{array}{rr}-3 & 0 \\ 2 & 2 \\ 1 & -3 \\\ 0 & 1\end{array}\right], C=\) \(\left[\begin{array}{r}-5 \\ -6 \\ 3 \\ 1\end{array}\right] .\) Compute the given expression, if possible. $$A B \text { and } \operatorname{tr}(A B).$$
Step-by-Step Solution
Verified Answer
The product of matrices A and B is \(\left[\begin{array}{rr}16 & 8 \\\ 6 & -17\end{array}\right]\), and the trace of this matrix is \(-1\).
1Step 1: Checking the possibility of matrix multiplication
To compute the product of matrices A and B, the number of columns in matrix A must be equal to the number of rows in matrix B. Matrix A has 4 columns and matrix B has 4 rows. Therefore, matrix multiplication between A and B is possible.
2Step 2: Performing matrix multiplication
To find the product AB, we need to compute the dot product of each row of matrix A with each column of matrix B. We will have:
\(AB = \left[\begin{array}{rrrr}-2 & 4 & 2 & 6 \\\ -1 & -1 & 5 & 0\end{array}\right] \left[\begin{array}{rr}-3 & 0 \\\ 2 & 2 \\\ 1 & -3 \\\ 0 & 1\end{array}\right]\)
= \(\left[\begin{array}{rr}
(-2)(-3)+(4)(2)+(2)(1)+(6)(0) & (-2)(0)+(4)(2)+(2)(-3)+(6)(1) \\\
(-1)(-3)+(-1)(2)+(5)(1)+(0)(0) & (-1)(0)+(-1)(2)+(5)(-3)+(0)(1)
\end{array}\right]\)
= \(\left[\begin{array}{rr}
6+8+2+0 & 0+8-6+6 \\\
3-2+5+0 & 0-2-15+0
\end{array}\right]\)
= \(\left[\begin{array}{rr}
16 & 8 \\\
6 & -17
\end{array}\right]\)
3Step 3: Finding the trace of the product
The trace of a square matrix is the sum of the diagonal elements. In this case, the trace of AB is:
\(\operatorname{tr}(AB) = 16 + (-17)\)
\(\operatorname{tr}(AB) = -1\)
So the expression \(AB\) is possible, and its value is \(\left[\begin{array}{rr}16 & 8 \\\ 6 & -17\end{array}\right]\), with a trace of \(-1\).
Key Concepts
Trace of a MatrixMatrix DimensionsDot ProductSquare Matrix
Trace of a Matrix
The trace of a matrix is a fundamental concept in linear algebra. It is defined for a square matrix and is the sum of the elements on its main diagonal. The main diagonal of a square matrix consists of elements that run from the top left to the bottom right.
For example, if you have a matrix:
Calculating the trace is a straightforward process but plays a crucial role in simplifying complex mathematical problems. It is widely used in various applications, such as quantum mechanics and system theory.
For example, if you have a matrix:
- \[\begin{bmatrix}x_{11} & x_{12} & x_{13} \x_{21} & x_{22} & x_{23} \x_{31} & x_{32} & x_{33} \\end{bmatrix}\]
Calculating the trace is a straightforward process but plays a crucial role in simplifying complex mathematical problems. It is widely used in various applications, such as quantum mechanics and system theory.
Matrix Dimensions
Understanding matrix dimensions is essential for performing operations like multiplication. Dimensions are expressed by the number of rows and columns a matrix has, typically noted as \( m \times n \).
For example, a matrix with 3 rows and 4 columns is noted as \( 3 \times 4 \). In our case:
For example, a matrix with 3 rows and 4 columns is noted as \( 3 \times 4 \). In our case:
- Matrix \( A \) has dimensions \( 2 \times 4 \), meaning it has 2 rows and 4 columns.
- Matrix \( B \) has dimensions \( 4 \times 2 \), with 4 rows and 2 columns.
Dot Product
The dot product is a mathematical operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number. When applied within the context of matrix multiplication, it involves computing the sum of the products of the corresponding entries of the sequences of numbers.
Each entry in the resulting matrix from multiplying matrices A and B is calculated through the dot product of a row from matrix A and a column from matrix B. For instance, using our matrices:
Each entry in the resulting matrix from multiplying matrices A and B is calculated through the dot product of a row from matrix A and a column from matrix B. For instance, using our matrices:
- The entry in the first row and first column of AB is the dot product of the first row of A and the first column of B:\[(-2)(-3) + (4)(2) + (2)(1) + (6)(0) = 16\]
- This operation is repeated for each entry of the resulting matrix AB.
Square Matrix
A square matrix is one where the number of rows and columns is equal, such as a 2x2, 3x3, etc. This characteristic is important, particularly when calculating the trace or certain other properties like determinants and eigenvalues.
In the problem presented, the product matrix \( AB \) is a square matrix since it has dimensions \( 2 \times 2 \). This enables us to calculate its trace and use other operations that are defined only for square matrices.
Square matrices often represent more complex systems and are pivotal in advanced mathematical theories and applications. Their properties allow calculations like the trace, playing a central role in simplifying and solving mathematical challenges.
In the problem presented, the product matrix \( AB \) is a square matrix since it has dimensions \( 2 \times 2 \). This enables us to calculate its trace and use other operations that are defined only for square matrices.
Square matrices often represent more complex systems and are pivotal in advanced mathematical theories and applications. Their properties allow calculations like the trace, playing a central role in simplifying and solving mathematical challenges.
Other exercises in this chapter
Problem 4
Verify that for all values of \(s\) and \(t\) $$(s, s-2 t, 2 s+3 t, t)$$ is a solution to the linear system $$\begin{aligned}x_{1}+x_{2}-x_{3}+5 x_{4} &=0 \\\2
View solution Problem 5
Determine elementary matrices that reduce the given matrix to row-echelon form. $$\left[\begin{array}{rrr}3 & -1 & 4 \\\2 & 1 & 3 \\\1 & 3 & 2\end{array}\right]
View solution Problem 5
Use the equivalence of (a) and (c) in the Invertible Matrix Theorem to prove that if \(A\) and \(B\) are invertible \(n \times n\) matrices, then so is \(A B.\)
View solution Problem 5
$$\begin{aligned} &\text { Let } A=\left[\begin{array}{rrrr} -3 & 2 & 7 & -1 \\ 6 & 0 & -3 & -5 \end{array}\right], B=\left[\begin{array}{rr} -2 & 8 \\ 8 & -3 \
View solution