Problem 5
Question
Let \(A=(2,3), B=(-4,7),\) and \(C=(-5,-6) .\) Calculate the distance of each of these points to each of the others.
Step-by-Step Solution
Verified Answer
The distances are: AB = \(2\sqrt{13}\), AC = \(\sqrt{130}\), BC = \(\sqrt{170}\).
1Step 1: Calculate Distance Between Points A and B
To find the distance between points A and B, we use the distance formula: \[d_{AB} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substitute \((x_1, y_1) = (2, 3)\) for point A and \((x_2, y_2) = (-4, 7)\) for point B:\[d_{AB} = \sqrt{((-4) - 2)^2 + (7 - 3)^2} = \sqrt{(-6)^2 + (4)^2} = \sqrt{36 + 16} = \sqrt{52} = 2\sqrt{13}\]
2Step 2: Calculate Distance Between Points A and C
Now use the distance formula to calculate the distance between points A and C:\[d_{AC} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substitute \((x_1, y_1) = (2, 3)\) for point A and \((x_2, y_2) = (-5, -6)\) for point C:\[d_{AC} = \sqrt{((-5) - 2)^2 + ((-6) - 3)^2} = \sqrt{(-7)^2 + (-9)^2} = \sqrt{49 + 81} = \sqrt{130} = \sqrt{130}\]
3Step 3: Calculate Distance Between Points B and C
Finally, use the distance formula for points B and C:\[d_{BC} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]Substitute \((x_1, y_1) = (-4, 7)\) for point B and \((x_2, y_2) = (-5, -6)\) for point C:\[d_{BC} = \sqrt{((-5) + 4)^2 + ((-6) - 7)^2} = \sqrt{(-1)^2 + (-13)^2} = \sqrt{1 + 169} = \sqrt{170} = \sqrt{170}\]
Key Concepts
Coordinate GeometryDistance CalculationPythagorean Theorem
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, allows us to describe the position of points in a plane using numerical coordinates. These coordinates, typically represented as \((x, y)\), indicate how far the point is from the x-axis and y-axis. The system gives us a way to use algebraic equations to solve geometric problems, such as determining the distance between points, slope of a line, or the equation of a circle.
In the context of our exercise, we are dealing with three points: \(A = (2, 3)\), \(B = (-4, 7)\), and \(C = (-5, -6)\). Each of these points has an x-coordinate and a y-coordinate that show their location on a Cartesian plane. By understanding these coordinates, we can apply formulas to find distances and relationships between the points.
In the context of our exercise, we are dealing with three points: \(A = (2, 3)\), \(B = (-4, 7)\), and \(C = (-5, -6)\). Each of these points has an x-coordinate and a y-coordinate that show their location on a Cartesian plane. By understanding these coordinates, we can apply formulas to find distances and relationships between the points.
Distance Calculation
Calculating the distance between two points in coordinate geometry is straightforward once we know their coordinates. Typically, we use the distance formula, which is derived from the Pythagorean theorem. The formula looks like this:
For instance, to find the distance between points \(A\) and \(B\), substitute \((x_1, y_1) = (2, 3)\) and \((x_2, y_2) = (-4, 7)\) into the distance formula, which yields:
- \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
For instance, to find the distance between points \(A\) and \(B\), substitute \((x_1, y_1) = (2, 3)\) and \((x_2, y_2) = (-4, 7)\) into the distance formula, which yields:
- \(d_{AB} = \sqrt{((-4) - 2)^2 + (7 - 3)^2} = \sqrt{52} = 2\sqrt{13}\)
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in mathematics, especially used in geometry to relate the lengths of the sides of a right triangle. The theorem states that in a right triangle,
This theorem is the foundation for the distance formula. Imagine you are constructing a right triangle from two points in the coordinate plane. The differences in the x-coordinates and y-coordinates form the two legs of a right triangle, while the distance between the points is the hypotenuse. Thus, using this relationship, the distance formula can be shown as a direct application of the Pythagorean theorem.
- the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
This theorem is the foundation for the distance formula. Imagine you are constructing a right triangle from two points in the coordinate plane. The differences in the x-coordinates and y-coordinates form the two legs of a right triangle, while the distance between the points is the hypotenuse. Thus, using this relationship, the distance formula can be shown as a direct application of the Pythagorean theorem.
Other exercises in this chapter
Problem 5
Write the point-slope equation of the line determined by the given data. Slope \(5,\) point (-3,7)
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State the domain of the function defined by the given expression. $$ 1 /\left(x^{2}-1\right) $$
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Convert the decimal to a rational fraction. (Ellipses are included in some exercises to indicate repetition.) \(5.001001001 \ldots\)
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Calculate the given expression without using a calculator. \(\cos (0)-\cos (\pi)\)
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