Problem 5
Question
In Exercises \(5-18\), solve each system by the substitution method. $$ \begin{aligned} &x+y=4\\\ &y=3 x \end{aligned} $$
Step-by-Step Solution
Verified Answer
(x, y) = (1, 3)
1Step 1: Substitution
Replace \(y\) in the first equation with \(3x\) from the second equation. This gives us the equation \(x + 3x = 4\).
2Step 2: Solve for x
Combine like terms on the left side of the equation to get \(4x = 4\). Then, divide each side of the equation by 4 to isolate x, which gives us the solution \(x = 1\).
3Step 3: Solve for y
Substitute \(x = 1\) into the second equation, yielding \(y = 3*1\). Therefore, \(y = 3\).
Key Concepts
System of EquationsSolving EquationsAlgebraic SubstitutionSteps in Problem Solving
System of Equations
A system of equations is a set of two or more equations that have common variables. In our problem, we have two linear equations:
When dealing with a system of equations, the solutions represent the points where the equations intersect if we were to graph them. In this context, intersection means that the values of \(x\) and \(y\) make both equations true simultaneously.
Systems of equations can be solved using various methods like substitution, elimination, and graphical methods. Here, we are focusing on the substitution method.
- \(x + y = 4\)
- \(y = 3x\)
When dealing with a system of equations, the solutions represent the points where the equations intersect if we were to graph them. In this context, intersection means that the values of \(x\) and \(y\) make both equations true simultaneously.
Systems of equations can be solved using various methods like substitution, elimination, and graphical methods. Here, we are focusing on the substitution method.
Solving Equations
Solving equations involves finding the values of the unknown variables that make the equation true. For any algebraic equation, our goal is to manipulate the equation so that the variable is isolated on one side.
Starting with the given system, solve for one variable in terms of the other using the substitution method. For instance, from \(y = 3x\), we already have \(y\) expressed in terms of \(x\). This makes one step of solving easier because we can replace \(y\) in other equations.
The solution requires basic operations, such as:
Starting with the given system, solve for one variable in terms of the other using the substitution method. For instance, from \(y = 3x\), we already have \(y\) expressed in terms of \(x\). This makes one step of solving easier because we can replace \(y\) in other equations.
The solution requires basic operations, such as:
- Combining like terms
- Isolating the variable through addition, subtraction, multiplication, or division
Algebraic Substitution
Algebraic substitution is a method where one variable in an equation is replaced by an expression derived from another equation. This approach helps simplify systems of equations, reducing the number of unknowns in each equation.
For our problem:
Now we have a value for \(x\), allowing us to backtrack and find \(y\) using the same substitution method, giving \(y = 3 * 1 = 3\). Thus, substitution efficiently reduces complexity, allowing for easier solutions.
For our problem:
- The second equation \(y = 3x\) serves as an expression for \(y\).
- We substitute \(3x\) in place of \(y\) in the first equation \(x + y = 4\).
Now we have a value for \(x\), allowing us to backtrack and find \(y\) using the same substitution method, giving \(y = 3 * 1 = 3\). Thus, substitution efficiently reduces complexity, allowing for easier solutions.
Steps in Problem Solving
Problem solving using substitution generally involves strategic steps that guide us toward a solution:
This method not only offers analytical clarity but also boosts confidence in solving future equations because of its orderly nature.
- Identify the equations in the system.
- Solve one of the equations for one variable, if it isn’t already.
- Substitute the expression found into the other equation.
- Simplify and solve the resulting equation for the single variable.
- Use the value obtained to back-substitute and find the other variable.
This method not only offers analytical clarity but also boosts confidence in solving future equations because of its orderly nature.
Other exercises in this chapter
Problem 4
Determine if the given ordered triple is a solution of the system. $$\begin{aligned}&x-2 z=-5\\\&y-3 z=-3\\\&2 x-z=-4\\\&(-1,3,2)\end{aligned}$$
View solution Problem 4
Solve each system by the substitution method. $$\begin{aligned} &2 x+y=-5\\\ &y=x^{2}+6 x+7 \end{aligned}$$
View solution Problem 5
Write the form of the partial fraction decomposition of the rational expression. It is not necessary to solve for the constants. $$\frac{5 x^{2}-6 x+7}{(x-1)\le
View solution Problem 5
Graph each inequality. $$ y \leq \frac{1}{3} x $$
View solution