Problem 5
Question
In Exercises 5-14, solve the system by the method of substitution. $$ \left\\{\begin{array}{l} x=4 y-5 \\ x=3 y \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system of equations is \(x = 15, y = 5\).
1Step 1: Equate the expressions for \(x\)
Since both equations express \(x\), set them equal to each other.\nHence, \(4y - 5 = 3y\)
2Step 2: Isolate \(y\)
Given the equation \(4y - 5 = 3y\), we need to manipulate this equation in a way that will allow us to solve for \(y\). To achieve this, we can subtract \(3y\) from both sides. This leaves us with \(y - 5 = 0\). Adding 5 to both sides, we then get \(y = 5\).
3Step 3: Substitute \(y\) back to find \(x\)
Now that we have found \(y = 5\), we can substitute \(y\) back into one of the original equations to find \(x\). For example, using the second equation, where \(x = 3y\), if we substitute \(y = 5\), this gives us \(x = 3*5 = 15\). Thus, the solution to the system of equations is \(x = 15, y = 5\).
Key Concepts
Solving Systems of EquationsIsolation of VariablesStep-by-Step Solution
Solving Systems of Equations
To solve systems of equations like the one provided in the exercise, we need to find values for the variables that satisfy all equations simultaneously. In this case, we have a system with two equations involving the variables \(x\) and \(y\). The goal is to determine specific values where both equations are true at the same time.
One reliable way to solve systems of equations is by the substitution method. This involves expressing one of the variables in terms of the other, which simplifies the process. With the system given, both equations already express \(x\) in terms of \(y\):
One reliable way to solve systems of equations is by the substitution method. This involves expressing one of the variables in terms of the other, which simplifies the process. With the system given, both equations already express \(x\) in terms of \(y\):
- \(x = 4y - 5\)
- \(x = 3y\)
Isolation of Variables
Isolation of variables is a critical step in simplifying and solving equations. Once we equate the two expressions for \(x\), we get: \(4y - 5 = 3y\). Here, our task is to isolate the variable \(y\) to solve for its value. This process involves rearranging the equation to have \(y\) alone on one side.
The steps to isolate \(y\) are straightforward:
The steps to isolate \(y\) are straightforward:
- Subtract \(3y\) from both sides to simplify the equation to \(y - 5 = 0\).
- Add 5 to both sides to get \(y = 5\).
Step-by-Step Solution
Following a step-by-step approach helps build a clear path to solving complex problems. After isolating \(y\) and finding \(y = 5\), our next journey is discovering the value of \(x\). By substituting the value of \(y\) into any one of the original equations, we find \(x\). Here’s how it plays out:
- Start with an equation that contains both \(x\) and \(y\), let's use \(x = 3y\).
- Substitute \(y = 5\) into this equation, giving \(x = 3 \times 5 = 15\).
Other exercises in this chapter
Problem 5
How many liters of a \(35 \%\) alcohol solution and a \(60 \%\) alcohol solution must be mixed to obtain 10 liters of a \(50 \%\) alcohol solution?
View solution Problem 5
In Exercises \(1-6\), solve the system by the method of elimination. $$ \left\\{\begin{array}{l} 3 x-5 y=1 \\ 2 x+5 y=9 \end{array}\right. $$
View solution Problem 5
In Exercises \(5-10\), solve the system by graphing. $$ \left\\{\begin{array}{l} y=-x+3 \\ y=x+1 \end{array}\right. $$
View solution Problem 6
In Exercises \(1-6\), sketch the graph of the system of linear inequalities. $$ \left\\{\begin{array}{l} x+y \geq 2 \\ x-y \leq 2 \end{array}\right. $$
View solution