Problem 5
Question
In \(3-26,\) prove that each equation is an identity. $$ \cot \theta \sin \theta \cos \theta=\cos ^{2} \theta $$
Step-by-Step Solution
Verified Answer
The equation is an identity, as simplifying gives \( \cos^2 \theta = \cos^2 \theta \).
1Step 1: Rewrite Given Equation
The problem statement gives us the equation \( \cot \theta \sin \theta \cos \theta = \cos^2 \theta \). Our goal is to prove that this equation is an identity.
2Step 2: Express \(\cot\theta\) in Terms of Sine and Cosine
Recall the trigonometric identity that \( \cot \theta = \frac{\cos \theta}{\sin \theta} \). Substitute this expression into the given equation: \( \frac{\cos \theta}{\sin \theta} \sin \theta \cos \theta \).
3Step 3: Simplify the Left Side
Substitute \( \cot \theta \) into the original equation and simplify: \( \left( \frac{\cos \theta}{\sin \theta} \right) \sin \theta \cos \theta = \cos \theta \cos \theta \). Since \( \sin \theta \) is in both the numerator and denominator, they cancel out, yielding \( \cos^2 \theta \).
4Step 4: Confirm the Identity
We are left with \( \cos^2 \theta = \cos^2 \theta \), which is true for all valid values of \( \theta \). Thus, the equation is indeed an identity.
Key Concepts
CotangentSine and CosineTrigonometric Simplification
Cotangent
Cotangent is one of the six fundamental trigonometric functions. In simpler terms, it’s the reciprocal of the tangent function.
- Definition: The cotangent of an angle, written as \( \cot \theta \), is defined as the ratio of the adjacent side to the opposite side in a right triangle.
- In terms of sine and cosine: \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
Sine and Cosine
Sine and cosine are the foundational trigonometric functions, taught at the start of trigonometry courses.
- Sine: The function \( \sin \theta \) measures the ratio of the length of the opposite side to the hypotenuse in a right triangle.
- Cosine: The function \( \cos \theta \) measures the ratio of the length of the adjacent side to the hypotenuse.
Trigonometric Simplification
Trigonometric simplification involves breaking down complex trigonometric expressions into simpler, more understandable ones. This process often uses fundamental identities like the Pythagorean identities.Consider the expression given in our exercise: \( \cot \theta \sin \theta \cos \theta = \cos^2 \theta \). To simplify:1. Replace \( \cot \theta \) with \( \frac{\cos \theta}{\sin \theta} \).2. You then have: \( \frac{\cos \theta}{\sin \theta} \times \sin \theta \times \cos \theta \).3. The \( \sin \theta \) terms in the numerator and denominator cancel, simplifying to \( \cos \theta \cos \theta \) or \( \cos^2 \theta \).This example shows how transforming an expression into familiar terms can lead to straightforward simplification. Using consistent techniques helps uncover proofs effectively and ensures no steps are skipped. Simplification is a powerful tool, particularly when proving that an equation or identity holds true for all permissible values.
Other exercises in this chapter
Problem 5
In \(3-8,\) for each value of \(\theta,\) use double-angle formulas to find a. \(\sin 2 \theta,\) b. \(\cos 2 \theta,\) c. \(\tan 2 \theta .\) Show all work. $$
View solution Problem 5
In \(3-17,\) find the exact value of \(\tan (A+B)\) and of \(\tan (A-B)\) for each given pair of values. $$ A=60^{\circ}, B=60^{\circ} $$
View solution Problem 5
\(\ln 3-17,\) find the exact value of \(\sin (A-B)\) and of \(\sin (A+B)\) for each given pair of values. \(A=180^{\circ}, B=30^{\circ}\)}
View solution Problem 5
In \(3-17,\) find the exact value of \(\cos (A+B)\) for each given pair of values. \(A=90^{\circ}, B=30^{\circ}\)
View solution