Problem 5
Question
If \(0<\alpha<\beta<\frac{\pi}{2}\) then (A) \(\frac{\tan \beta}{\tan \alpha}<\frac{\alpha}{\beta}\) (B) \(\frac{\tan \beta}{\tan \alpha}>\frac{\alpha}{\beta}\) (C) \(\frac{\tan \alpha}{\tan \beta}<\frac{\alpha}{\beta}\) (D) \(\frac{\tan \alpha}{\tan \beta}>\frac{\alpha}{\beta}\)
Step-by-Step Solution
Verified Answer
Option (B) \(\frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta}\) is correct.
1Step 1: Understand the Given Condition
We are given that \(0 < \alpha < \beta < \frac{\pi}{2}\). This indicates that both \(\alpha\) and \(\beta\) are angles in the first quadrant where the tangent function is positive and increasing.
2Step 2: Compare Tan Values
Since \(\tan(x)\) is an increasing function in the interval \( (0, \frac{\pi}{2})\), we know that \( \tan(\alpha) < \tan(\beta) \). This implies that \( \frac{\tan(\beta)}{\tan(\alpha)} > 1\).
3Step 3: Analyze Given Options
Given the result from Step 2, option (B) \(\frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta}\) needs to be evaluated.
4Step 4: Evaluate Option B
We know \( \alpha < \beta \) implies \( \frac{\alpha}{\beta} < 1\). Since \(\frac{\tan \beta}{\tan \alpha} > 1\) from Step 2, we conclude that \( \frac{\tan \beta}{\tan \alpha} > \frac{\alpha}{\beta} \). Thus, option (B) is correct.
5Step 5: Verify Other Options
For completeness, verify the other options:- Option (A) \(\frac{\tan \beta}{\tan \alpha} < \frac{\alpha}{\beta}\) contradicts Step 4.- Option (C) and (D) involve \(\frac{\tan \alpha}{\tan \beta}\) which will be less than 1, conflicting with the given options suggesting inequality with \(\frac{\alpha}{\beta}\).
Key Concepts
Tangent FunctionInequalityFirst Quadrant Angles
Tangent Function
The tangent function is a fundamental component in trigonometry, especially when dealing with right triangles and circles. It expresses the ratio of the opposite side to the adjacent side in a right-angled triangle. Mathematically, it is written as \( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \). The function is defined for all angles, but in the context of this problem, we focus on the interval \( (0, \frac{\pi}{2}) \), which is the first quadrant of the unit circle.
The tangent function is a continuous and increasing function within this quadrant. This means as the angle \( \theta \) increases from 0 to \( \frac{\pi}{2} \), the value of \( \tan(\theta) \) increases without bound. Understanding the behavior of \( \tan \) in the first quadrant allows us to predict how it behaves relative to other trigonometric functions such as sine and cosine.
The tangent function is a continuous and increasing function within this quadrant. This means as the angle \( \theta \) increases from 0 to \( \frac{\pi}{2} \), the value of \( \tan(\theta) \) increases without bound. Understanding the behavior of \( \tan \) in the first quadrant allows us to predict how it behaves relative to other trigonometric functions such as sine and cosine.
- \( \tan(0) = 0 \)
- \( \tan(\frac{\pi}{4}) = 1 \)
- \( \tan(\theta) \to \infty \) as \( \theta \to \frac{\pi}{2} \)
Inequality
Inequalities allow us to demonstrate the relative size between two expressions. They are crucial in mathematical reasoning and proofs. When we say \( a < b \), it implies that \( a \) is smaller than \( b \). Similarly, \( a > b \) means \( a \) is bigger than \( b \).
In trigonometry, inequalities help compare trigonometric values at different angles. For instance, knowing that the tangent function is increasing in the first quadrant, we can assert \( \tan(\alpha) < \tan(\beta) \) if \( \alpha < \beta \). This inequality holds because in the interval \( (0, \frac{\pi}{2}) \), \( \tan \) maps to positive numbers increasing with the angle.
In trigonometry, inequalities help compare trigonometric values at different angles. For instance, knowing that the tangent function is increasing in the first quadrant, we can assert \( \tan(\alpha) < \tan(\beta) \) if \( \alpha < \beta \). This inequality holds because in the interval \( (0, \frac{\pi}{2}) \), \( \tan \) maps to positive numbers increasing with the angle.
- \( \frac{\tan(\beta)}{\tan(\alpha)} > 1 \) because \( \tan(\alpha) < \tan(\beta) \)
- \( \frac{\alpha}{\beta} < 1 \) under the condition \( \alpha < \beta \)
First Quadrant Angles
First quadrant angles are those angles measured from 0 to \( \frac{\pi}{2} \), or 0 to 90 degrees, and they have special properties in trigonometric contexts.
In this quadrant, all trigonometric functions — sine, cosine, and tangent — yield positive values. This positivity is why these angles are crucial in many applications, like physics and engineering, where non-negative results are often required.
In this quadrant, all trigonometric functions — sine, cosine, and tangent — yield positive values. This positivity is why these angles are crucial in many applications, like physics and engineering, where non-negative results are often required.
- For any angle \( \theta \) in the first quadrant, \( 0 < \sin(\theta), \cos(\theta), \tan(\theta) \)
- Knowing the function's behavior, \( \tan \) here is crucial; it’s increasing, meaning that larger angles produce larger tangent values.
Other exercises in this chapter
Problem 3
The function \(f(x)=\frac{\sin x}{x}\) is decreasing in the interval (A) \(\left(-\frac{\pi}{2}, 0\right)\) (B) \(\left(0, \frac{\pi}{2}\right)\) (C) \((0, \pi)
View solution Problem 4
If \(a x+\frac{b}{x} \geq c\) for all positive \(x\), where \(a, b>0\), then (A) \(a b
View solution Problem 7
The range of values of \(a\) for which the function \(f(x)=x^{3}+(a+2) x^{2}+3 a x+5\) may be monotonic in \(R\), is (A) \(a4\) (D) None of these
View solution Problem 8
The values of \(k\) for which the function \(f(x)=k x^{3}-9 x^{2}+9 x+3\) may be increasing on \(R\) are (A) \(k>3\) (B) \(k
View solution