Problem 5
Question
Graph the solution set of each inequality on a number line and then write it in interval notation. $$ \\{x \mid-7 \leq x\\} $$
Step-by-Step Solution
Verified Answer
The solution set is \([-7, \infty)\).
1Step 1: Understand the Inequality
The inequality is given in set-builder notation: \( \{x \mid-7 \leq x\} \). This reads as the set of all \( x \) such that \( -7 \leq x \). This means \( x \) can be any number greater than or equal to \(-7\).
2Step 2: Represent the Inequality on a Number Line
To graph the solution set on a number line, we place a closed circle at \(-7\) because \( x \) can be equal to \(-7\). Then, since \( x \) can take any value greater than \(-7\), we shade the number line to the right of \(-7\). This shaded region represents all numbers greater than or equal to \(-7\).
3Step 3: Express the Solution in Interval Notation
In interval notation, we express the solution set as \([-7, \, \infty)\). The square bracket \([-7\) indicates that \(-7\) is included in the solution set (due to the \( \leq \) inequality), and the parenthesis \(, \infty)\) indicates that there is no upper bound on \( x \).
Key Concepts
Set-Builder NotationGraphing on a Number LineInterval Notation
Set-Builder Notation
Set-builder notation is a way to describe a set of numbers or values that satisfy a particular condition. In our example, the inequality is given as \( \{x \mid -7 \leq x\} \). This notation tells us that we are looking at all possible values of \( x \) that are greater than or equal to -7.
This is read aloud as "the set of all \( x \) such that \( -7 \leq x \)."
Set-builder notation is particularly useful because:
This is read aloud as "the set of all \( x \) such that \( -7 \leq x \)."
Set-builder notation is particularly useful because:
- It succinctly describes complex sets.
- It clearly states the rule or condition that elements of the set should satisfy.
- It is a common mathematical language for representing conditions, making it widely understood.
Graphing on a Number Line
Graphing an inequality on a number line is an excellent way to visualize its solution set. To graph \( \{x \mid -7 \leq x\} \) on a number line, you need to identify all numbers that meet the inequality's conditions.
Here is a step-by-step guide to graph this inequality:
Visualizing an inequality on a number line can clarify which numbers satisfy it and highlight the endpoints' inclusion or exclusion.
Here is a step-by-step guide to graph this inequality:
- Start by drawing a horizontal line that represents the number line.
- Locate the point \(-7\) on this number line.
- Place a closed circle on \(-7\) because the inequality includes \(-7\), as denoted by the "less than or equal to" symbol \(\leq\).
- Since \(x\) can be any number greater than \(-7\), shade the line extending to the right from \(-7\). The shading indicates that all those numbers are part of the solution set.
Visualizing an inequality on a number line can clarify which numbers satisfy it and highlight the endpoints' inclusion or exclusion.
Interval Notation
Interval notation is a concise way of expressing the set of numbers that represent the solution to an inequality. In the exercise, the interval notation for \( \{x \mid -7 \leq x\} \) is \([-7, \infty)\). Here's how interval notation works:
Remember:
- The square bracket \([-7\) means that \(-7\) is included in the set because the inequality \(-7 \leq x\) allows \(x\) to equal \(-7\).
- The parenthesis \(\infty)\) indicates that there is no upper bound on \(x\), and \(\infty\) is never included because it is not a definite number.
Remember:
- Square brackets mean that the endpoint is included in the interval.
- Parentheses mean that the endpoint is not included.
Other exercises in this chapter
Problem 5
Find the domain and the range of each relation. Also determine whether the relation is a function. $$ \\{(1,1),(1,2),(1,3),(1,4)\\} $$
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Write an equation of each line with the given slope and containing the given point. Write the equation in the slope-intercept form \(y=m x+b .\) See Example \(1
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If \(P(x)=x^{2}+x+1\) and \(Q(x)=5 x^{2}-1,\) find each function value. $$ Q(0) $$
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Sketch the graph of each function. $$ f(x)=|x+3| $$
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