Problem 5
Question
Graph the equation. State whether the two quantities have direct variation. If they have direct variation, find the constant of variation and the slope of the direct variation model. $$y=\frac{1}{2} x$$
Step-by-Step Solution
Verified Answer
Yes, the given equation \(y = \frac{1}{2} x\) represents a direct variation. The constant of variation and the slope of the direct variation model is \(\frac{1}{2}\). The graph would be a straight line passing through the origin with a slope of \(\frac{1}{2}\).
1Step 1: Identify the direct variation
The given equation is \(y = \frac{1}{2} x\). This matches the form \(y = kx\), hence there is a direct variation.
2Step 2: Identify the constant of variation
The constant of variation \(k\) is the coefficient of \(x\) in the equation. From the equation \(y = \frac{1}{2} x\), the constant of variation is \(\frac{1}{2}\).
3Step 3: Identify the slope of the direct variation model
For a direct variation equation, the slope is same as the constant of variation. So, the slope of the line representing the direct variation is also \(\frac{1}{2}\).
4Step 4: Graph the equation
On the graph, plot the line that passes through the point (0, 0) and has a slope of \(\frac{1}{2}\). This line represents the direct variation model of the given equation.
Key Concepts
Constant of VariationSlopeGraphing Linear EquationsAlgebra 1
Constant of Variation
In mathematics, especially in algebra, a constant of variation is a crucial concept when dealing with direct variation. Direct variation is a specific relationship between two variables where one is a constant multiple of the other.
In the equation format, this is usually described as \( y = kx \). Here, \( k \) is known as the constant of variation, and it acts as the coefficient of \( x \).
For example, in the equation \( y = \frac{1}{2} x \), the constant of variation \( k \) is \( \frac{1}{2} \). This means that for every unit increase in \( x \), \( y \) increases by half a unit. The constant of variation effectively scales the input \( x \) to produce the output \( y \).
Understanding this constant helps in identifying the nature of the relationship between the two variables and directly influences how the graph will look.
In the equation format, this is usually described as \( y = kx \). Here, \( k \) is known as the constant of variation, and it acts as the coefficient of \( x \).
For example, in the equation \( y = \frac{1}{2} x \), the constant of variation \( k \) is \( \frac{1}{2} \). This means that for every unit increase in \( x \), \( y \) increases by half a unit. The constant of variation effectively scales the input \( x \) to produce the output \( y \).
Understanding this constant helps in identifying the nature of the relationship between the two variables and directly influences how the graph will look.
Slope
The slope is an integral part of understanding linear equations and is especially important in direct variation models. Simply put, the slope is a measure of how steep a line is. It describes the direction and steepness of a line on a graph.
In the context of direct variation, the slope is equivalent to the constant of variation. This means that in the equation \( y = \frac{1}{2} x \), the slope is \( \frac{1}{2} \).
In the context of direct variation, the slope is equivalent to the constant of variation. This means that in the equation \( y = \frac{1}{2} x \), the slope is \( \frac{1}{2} \).
- This positive value indicates that the line rises as you move from left to right on the graph.
- A larger slope means a steeper line, while a smaller slope suggests a gentler incline.
Graphing Linear Equations
Graphing linear equations is a key skill in algebra that helps visualize relationships between variables. When graphing, the equation defines a line on a coordinate plane.
For direct variation equations like \( y = \frac{1}{2} x \), you will notice that the line passes through the origin (0,0). This is because direct variation requires the line to start at the origin.
For direct variation equations like \( y = \frac{1}{2} x \), you will notice that the line passes through the origin (0,0). This is because direct variation requires the line to start at the origin.
- To graph: Start at point (0,0), as that's where the line will cross both axes.
- Use the slope, \( \frac{1}{2} \), to determine the next point. This tells you to rise 1 unit for every 2 units you move across.
- Draw a straight line through these points to complete the graph.
Algebra 1
Algebra 1 serves as a foundational course in mathematics, introducing essential algebraic concepts and techniques. It provides students with a comprehensive understanding of variables, equations, and functions.
In Algebra 1, direct variation models are a key focus. Students learn how to recognize equations of the form \( y = kx \) and understand the meaning behind the constant \( k \).
In Algebra 1, direct variation models are a key focus. Students learn how to recognize equations of the form \( y = kx \) and understand the meaning behind the constant \( k \).
- Skills like identifying slopes and graphing equations are introduced here.
- Students practice creating and interpreting graphs from equations.
- These fundamentals are not only essential for advanced math courses but also practical in real-world applications.
Other exercises in this chapter
Problem 5
Plot the ordered pairs in a coordinate plane. (GRAPH CANNOT COPY) $$A(-2,-3), B(-3,-2)$$
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Evaluate the function \(f(x)=3 x-10\) for the given value of \(x .\) $$ x=-2 $$
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Plot the points and draw a line through them. Find the slope of the line passing through the points. $$(0,0),(1,2)$$
View solution Problem 5
Find the slope and the y-intercept of the graph of the equation. $$ y=2 x+1 $$
View solution