Problem 5
Question
Graph each function. Identify the domain and range. \(h(x)=|x|-3\)
Step-by-Step Solution
Verified Answer
Domain: (-∞, ∞); Range: [-3, ∞)
1Step 1: Understanding Absolute Value Function
The function given is an absolute value function, \[ h(x) = |x| - 3 \]. Absolute value functions have a V-shape graph. In this case, the graph of \( y = |x| \) is shifted down by 3 units.
2Step 2: Determine the Vertex of the Graph
The vertex of the basic absolute value function \( y = |x| \) is at the origin \((0,0)\). The given function \( h(x) = |x| - 3 \) shifts this vertex down by 3 units, resulting in the new vertex at \((0, -3)\).
3Step 3: Drawing the Graph
Start plotting the graph at the vertex \((0, -3)\). Since it's a V-shaped graph, the lines extend upward to the right and left. For instance, if \( x = 1 \) or \( x = -1 \), then \( h(1) = |1| - 3 = -2 \) and \( h(-1) = |-1| - 3 = -2 \). Repeat this process for other values like \( x = 2 \), \( x = -2 \), etc., plotting points symmetrically around the y-axis.
4Step 4: Identifying the Domain
The domain of \( h(x) = |x| - 3 \) is all real numbers because there are no restrictions on \( x \). Thus, the domain is: \[ (-\infty, \infty) \].
5Step 5: Identifying the Range
The range is all possible \( y \)-values that the function can output. Since the graph reaches its minimum at \( y = -3 \) and opens upwards, the range is: \[ [-3, \infty) \].
Key Concepts
Domain and RangeGraphing FunctionsVertex of a Function
Domain and Range
The domain and range of a function are vital to understand its limitations and outputs. The **domain** comprises all possible input values (or x-values) for a function. There are no restrictions on the variable \( x \) for the function \( h(x) = |x| - 3 \). This is typical for absolute value functions unless there are additional terms that limit \( x \), such as fractions or square roots. Therefore, the domain for \( h(x) \) is all real numbers, expressed as
The **range**, however, is what the function can output (or y-values). The lowest point on the graph of \( h(x) \) is at \( y = -3 \). This value occurs when the absolute value component is zero, which is at the vertex. The V-shape indicates that as \( x \) moves away from 0, \( y \) only gets larger. Hence, the range is from \( -3 \) including all values above that, represented as:
- Domain: \((-\infty, \infty)\)
The **range**, however, is what the function can output (or y-values). The lowest point on the graph of \( h(x) \) is at \( y = -3 \). This value occurs when the absolute value component is zero, which is at the vertex. The V-shape indicates that as \( x \) moves away from 0, \( y \) only gets larger. Hence, the range is from \( -3 \) including all values above that, represented as:
- Range: \([-3, \infty)\)
Graphing Functions
To graph the absolute value function \( h(x) = |x| - 3 \), start by recognizing its basic shape. Absolute value functions have a distinct V shape. We begin sketching this function from its vertex. Since \( h(x) \) is derived from \( |x| \), the primary modification is a downward shift by 3 units.
Start at the vertex located at \( (0, -3) \). The graph then extends upward to the left and right. For better accuracy in plotting:
Start at the vertex located at \( (0, -3) \). The graph then extends upward to the left and right. For better accuracy in plotting:
- Choose integer values close to the vertex for \( x \), such as -1, 0, and 1.
- Calculate corresponding \( y \)-values: \( h(-1) = |-1| - 3 = -2 \), \( h(0) = |0| - 3 = -3 \), and \( h(1) = |1| - 3 = -2 \).
Vertex of a Function
The vertex of a function is a crucial point, especially for absolute value functions and quadratics. For \( h(x) = |x| - 3 \), the vertex represents the lowest point in its V shape. With the transformation of the basic absolute value function \( y = |x| \), the vertex shifts directly downward by 3 units. This transformation moves the vertex from \( (0,0) \) to \( (0,-3) \).
- The vertex \((0, -3)\) is significant because it marks the minimum value of the function.
- All other values of \( h(x) \) are greater than \( -3 \).
Other exercises in this chapter
Problem 4
On January \(1,1999,\) the euro became legal tender in 11 participating countries in Europe. Based on the exchange rate on one particular day, the linear functi
View solution Problem 5
Graph each inequality. $$ y > |2 x| $$
View solution Problem 5
Graph the line passing through the given point with the given slope. $$ (-3,-4), \frac{3}{2} $$
View solution Problem 5
Write each equation in standard form. Identify A, B, and C. \(y=3 x-5\)
View solution