Problem 5
Question
For the following power series, find if they are convergent or not, and if so find their radius of convergence. a) \(\sum_{n=0}^{\infty} 2^{n} x^{n}\) b) \(\sum_{n=0}^{\infty} n x^{n}\) c) \(\sum_{n=0}^{\infty} n ! x^{n}\) d) \(\sum_{n=0}^{\infty} \frac{1}{(2 n) !}(x-10)^{n}\) e) \(\left.\sum_{n=0}^{\infty} x^{2 n} \quad f\right) \sum_{n=0}^{\infty} n ! x^{n !}\)
Step-by-Step Solution
Verified Answer
a) R=0.5; b) R=1; c) R=0; d) R=∞; e) R=1; f) R=0. Convergence depends on the radius for each.
1Step 1: Analyze Series a
To determine the radius of convergence of the series \( \sum_{n=0}^{\infty} 2^n x^n \), we apply the formula for the radius of convergence: \[ R = \frac{1}{\limsup_{n \to \infty} \sqrt[n]{|a_n|}} \]Here, \( a_n = 2^n \). Thus, \[ \sqrt[n]{|a_n|} = \sqrt[n]{2^n} = 2 \]Therefore, \( \limsup_{n \to \infty} \sqrt[n]{|a_n|} = 2 \), and hence:\[ R = \frac{1}{2} \] The series converges for \( |x| < \frac{1}{2} \).
2Step 2: Analyze Series b
The series \( \sum_{n=0}^{\infty} n x^n \) can be evaluated using the radius of convergence formula. Here, \( a_n = n \), so:\[ \limsup_{n \to \infty} \sqrt[n]{n} = 1 \] Thus, the radius is given by:\[ R = \frac{1}{1} = 1 \]The series converges for \( |x| < 1 \).
3Step 3: Analyze Series c
For the series \( \sum_{n=0}^{\infty} n! x^n \), calculate the radius of convergence:\[ \limsup_{n \to \infty} \sqrt[n]{n!} \to \infty \] because factorials grow very quickly, leading to:\[ R = \frac{1}{\infty} = 0 \]This series converges only at \( x = 0 \).
4Step 4: Analyze Series d
Consider \( \sum_{n=0}^{\infty} \frac{1}{(2n)!}(x-10)^n \): \( a_n = \frac{1}{(2n)!} \), and \[ \limsup_{n \to \infty} \sqrt[n]{\frac{1}{(2n)!}} = 0 \] because \( (2n)! \) grows extremely fast, giving us:\[ R = \infty \]The series converges for all \( x \).
5Step 5: Analyze Series e
For \( \sum_{n=0}^{\infty} x^{2n} \), recognize this as a geometric series with \( a = 1 \) and \( r = x^2 \), which converges when \( |x^2| < 1 \) or \( |x| < 1 \). Thus, the radius is:\[ R = 1 \]
6Step 6: Analyze Series f
For \( \sum_{n=0}^{\infty} n! x^{n!} \), using the same reasoning as in series c, the terms grow quickly:\[ \limsup_{n \to \infty} \sqrt[n]{n!} \to \infty \]Thus, the radius of convergence is:\[ R = 0 \]The series converges only at \( x = 0 \).
Key Concepts
Power SeriesFactorialGeometric SeriesLimsup
Power Series
A power series is a series of the form \( \sum_{n=0}^{\infty} a_n x^n \), where \( a_n \) is the coefficient of each term and \( x \) is a variable. Understanding power series is fundamental to many areas in mathematics, particularly calculus and complex analysis.
A power series converges when the variable \( x \) lies within a particular region around a central point. This region is determined by the radius of convergence, which defines how far from the center point the series will converge.
When working with power series, it's essential to understand:
A power series converges when the variable \( x \) lies within a particular region around a central point. This region is determined by the radius of convergence, which defines how far from the center point the series will converge.
When working with power series, it's essential to understand:
- Convergence: Whether the series sums up to a finite value in a particular range of \( x \)
- Radius of Convergence \( R \): Indicates the interval \( |x| < R \) where the series converges
Factorial
The factorial of a non-negative integer \( n \), denoted \( n! \), is the product of all positive integers less than or equal to \( n \). Factorials play a crucial role in combinations, permutations, and series such as Taylor series.
A crucial point about factorials is their rapid growth rate. For example:
A crucial point about factorials is their rapid growth rate. For example:
- \( 3! = 3 \times 2 \times 1 = 6 \)
- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
Geometric Series
A geometric series is a series with a constant ratio between successive terms. It takes the form \( \sum_{n=0}^{\infty} ar^n \), where \( a \) is the first term and \( r \) is the common ratio.
Geometric series are a fundamental concept and are one of the few infinite series that possess a simple convergence condition:
Geometric series are a fundamental concept and are one of the few infinite series that possess a simple convergence condition:
- The series converges when the absolute value of the ratio \( |r| < 1 \)
- The sum of a convergent geometric series is given by \( \frac{a}{1-r} \)
Limsup
The term \( \limsup \), or limit superior, is a concept used in analysis that describes the limiting behavior of a sequence. In the context of series, it helps determine the radius of convergence by evaluating the growth of the series terms.
For a sequence \( \{a_n\} \), the \( \limsup \) of \( a_n \) as \( n \to \infty \) is the greatest limit point of the sequence. It's a way to capture the "upper bound trend" of the sequence. In terms of finding the radius of convergence \( R \), it is used in:
For a sequence \( \{a_n\} \), the \( \limsup \) of \( a_n \) as \( n \to \infty \) is the greatest limit point of the sequence. It's a way to capture the "upper bound trend" of the sequence. In terms of finding the radius of convergence \( R \), it is used in:
- The formula \( R = \frac{1}{\limsup_{n \to \infty} \sqrt[n]{|a_n|}} \)
Other exercises in this chapter
Problem 4
In the following exercises, feel free to use what you know from calculus to find the limit, if it exists. But you must prove that you found the correct limit, o
View solution Problem 5
Let \(x_{n}:=\frac{n-\cos (n)}{n} .\) Use the squeeze lemma to show that \(\left\\{x_{n}\right\\}\) converges and find the limit.
View solution Problem 5
Suppose a Cauchy sequence \(\left\\{x_{n}\right\\}\) is such that for every \(M \in \mathbb{N},\) there exists a \(k \geq M\) and an \(n \geq M\) such that \(x_
View solution Problem 5
a) Let \(x_{n}:=\frac{(-1)^{n}}{n} .\) Find \(\limsup x_{n}\) and \(\liminf x_{n}\). b) Let \(x_{n}:=\frac{(n-1)(-1)^{n}}{n} .\) Find \(\limsup x_{n}\) and \(\l
View solution