Problem 5
Question
For the following exercises, find the average rate of change of each function on the interval specified for real numbers \(b\) or \(h\) in simplest form. \(f(x)=4 x^{2}-7\) on \([1, \quad b]\)
Step-by-Step Solution
Verified Answer
Average rate of change is \(4(b + 1)\).
1Step 1: Understand the Formula for Average Rate of Change
The average rate of change of a function between two points is calculated using the formula: \( \frac{f(b) - f(a)}{b - a} \). This is similar to finding the slope of the line connecting two points \((a, f(a))\) and \((b, f(b))\) on the graph of the function.
2Step 2: Evaluate the Function at Given Points
First, we need to find the values of the function \( f(x) = 4x^2 - 7 \) at the endpoints of the interval \([1, b]\).- Calculate \( f(1) = 4(1)^2 - 7 \):\[ f(1) = 4 - 7 = -3 \]- Now calculate \( f(b) = 4b^2 - 7 \). We will leave this expression in terms of \( b \) since we do not have a specific numeric value for \( b \).
3Step 3: Substitute into Average Rate of Change Formula
Substitute \( f(1) \) and \( f(b) \) into the average rate of change formula:\[\frac{f(b) - f(1)}{b - 1} = \frac{(4b^2 - 7) - (-3)}{b - 1}\]Simplify the expression in the numerator:\[ 4b^2 - 7 + 3 = 4b^2 - 4 \].
4Step 4: Simplify the Expression
The expression for the average rate of change is:\[\frac{4b^2 - 4}{b - 1}\]This can be factored in the numerator as:\[ 4(b^2 - 1) = 4(b - 1)(b + 1) \]So the expression becomes:\[\frac{4(b - 1)(b + 1)}{b - 1}\]We can cancel \(b - 1\) from the numerator and denominator:\[ 4(b + 1) \]
5Step 5: Final Result
So, the average rate of change of \( f(x) = 4x^2 - 7 \) on \([1, b]\) is: \[ 4(b + 1) \].
Key Concepts
Quadratic FunctionsInterval NotationFunction Evaluation
Quadratic Functions
Quadratic functions are an essential part of algebra and calculus, often appearing in many areas of mathematics. At their core, a quadratic function is defined as any function that can be written in the form:
\( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, with \( a eq 0 \).
In our exercise, the function \( f(x) = 4x^2 - 7 \) is a quadratic function. The main characteristic of quadratic functions is their U-shaped graph known as a parabola. The exact shape and position of the parabola depend on the coefficients \( a \), \( b \), and \( c \).
\( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, with \( a eq 0 \).
In our exercise, the function \( f(x) = 4x^2 - 7 \) is a quadratic function. The main characteristic of quadratic functions is their U-shaped graph known as a parabola. The exact shape and position of the parabola depend on the coefficients \( a \), \( b \), and \( c \).
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), it opens downwards.
- The vertex of the parabola is the highest or lowest point, depending on the direction it opens.
Interval Notation
Interval notation is a crucial concept in mathematics, particularly when dealing with functions on certain domains. It is a way of specifying a particular range of x-values.
This notation is designed to help us easily communicate which values are included or excluded from a given set. In interval notation, a pair of numbers are used within brackets:
This notation is designed to help us easily communicate which values are included or excluded from a given set. In interval notation, a pair of numbers are used within brackets:
- Square brackets [ ] mean the endpoint is included.
- Parentheses ( ) mean the endpoint is not included.
Function Evaluation
Function evaluation is a fundamental skill in algebra used often in calculus problems like finding average rates of change. It involves calculating the output of a function for given input values.
For example, in our task, we're dealing with \( f(x) = 4x^2 - 7 \).When evaluating this function for a specific x-value, such as \( x = 1 \), simply substitute '1' into every \( x \) in the function:
\( f(1) = 4(1)^2 - 7 = -3 \).Evaluating at \( x = b \) requires a slightly different approach since 'b' is a variable:
Function evaluation is the process that ensures you're working with accurate values warranted by the problem setup or user-given conditions.
For example, in our task, we're dealing with \( f(x) = 4x^2 - 7 \).When evaluating this function for a specific x-value, such as \( x = 1 \), simply substitute '1' into every \( x \) in the function:
\( f(1) = 4(1)^2 - 7 = -3 \).Evaluating at \( x = b \) requires a slightly different approach since 'b' is a variable:
- We substitute \( b \) into the function instead of a number.
- This keeps the function in terms of \( b \), allowing for algebraic simplification.
Function evaluation is the process that ensures you're working with accurate values warranted by the problem setup or user-given conditions.
Other exercises in this chapter
Problem 5
How can you determine whether a function is odd or even from the formula of the function?
View solution Problem 5
Given \(f(x)=x^{2}+2 x\) and \(g(x)=6-x^{2},\) find \(f+g, \quad f-g, \quad f g,\) and \(\quad \frac{f}{g}\)
View solution Problem 5
Why does the horizontal line test tell us whether the graph of a function is one-to-one?
View solution Problem 6
Show that the function \(f(x)=a-x\) is its own inverse for all real numbers \(a\).
View solution