Problem 5
Question
For the following exercises, evaluate the binomial coefficient. $$ \left(\begin{array}{l} 6 \\ 2 \end{array}\right) $$
Step-by-Step Solution
Verified Answer
The binomial coefficient is 15.
1Step 1: Understand the Binomial Coefficient
The binomial coefficient \( \left( \begin{array}{c} n \ r \end{array} \right) \) represents the number of ways to choose \( r \) elements from a set of \( n \) elements without regard to order. It is calculated using the formula: \( \frac{n!}{r!(n-r)!} \).
2Step 2: Substitute Values into the Formula
For \( n = 6 \) and \( r = 2 \), substitute these values into the formula: \( \left( \begin{array}{c} 6 \ 2 \end{array} \right) = \frac{6!}{2!(6-2)!} \).
3Step 3: Calculate Factorials
First, calculate the factorials: - \( 6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720 \)- \( 2! = 2 \times 1 = 2 \)- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
4Step 4: Substitute Factorials into the Formula
Substitute the calculated factorials back into the formula:\( \frac{6!}{2!4!} = \frac{720}{2 \times 24} \).
5Step 5: Simplify the Expression
Calculate the value: - First multiply \( 2 \times 24 = 48 \)- Divide the factorial result \( \frac{720}{48} = 15 \)
6Step 6: Conclude the Result
The binomial coefficient \( \left( \begin{array}{c} 6 \ 2 \end{array} \right) \) evaluates to 15.
Key Concepts
FactorialsCombinatoricsMathematical Formulas
Factorials
Factorials play a crucial role when dealing with binomial coefficients. In mathematics, a factorial is a product of all positive integers less than or equal to a given positive integer. It is denoted by an exclamation point (!). For example, the factorial of 6, written as 6!, is calculated as follows:
Understanding and calculating factorials accurately can significantly ease the computation of more complex expressions encountered in combinatorics.
- 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720
Understanding and calculating factorials accurately can significantly ease the computation of more complex expressions encountered in combinatorics.
Combinatorics
Combinatorics is the branch of mathematics that focuses on counting, arrangement, and combination of objects. The binomial coefficient is a fundamental concept in combinatorics. It allows us to determine how many ways we can choose a subset of elements from a set, without considering the sequence or order of the elements.
The formula for the binomial coefficient when choosing \( r \) elements from \( n \) elements is given as:
Combinatorics appears in many aspects of applied mathematics, including probability theory and algorithm design.
The formula for the binomial coefficient when choosing \( r \) elements from \( n \) elements is given as:
- \( \left( \begin{array}{c} n \ r \end{array} \right) = \frac{n!}{r!(n-r)!} \)
Combinatorics appears in many aspects of applied mathematics, including probability theory and algorithm design.
Mathematical Formulas
Mathematical formulas are essential tools for expressing relationships and calculations in a compact form. In the exercise about binomial coefficients, the formula \( \frac{n!}{r!(n-r)!} \) is used to simplify understanding and computation of how elements can be combined.
This formula relies on factorial expressions, which account for permutations of elements, while the denominator adjusts for the cases where order does not matter.
Substituting values into a formula allows for straightforward calculation of even complex expressions by following structured steps. Here's how values are substituted in:
This formula relies on factorial expressions, which account for permutations of elements, while the denominator adjusts for the cases where order does not matter.
Substituting values into a formula allows for straightforward calculation of even complex expressions by following structured steps. Here's how values are substituted in:
- For \( n = 6 \) and \( r = 2 \), we find \( \left( \begin{array}{c} 6 \ 2 \end{array} \right) = \frac{6!}{2!4!} \)
Other exercises in this chapter
Problem 5
What is an annuity?
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Th union of two sets is defi ed as a set of elements that are present in at least one of the sets. How is this similar to the defin tion used for the union of t
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Answer the following questions. What is the term for the arrangement that selects \(r\) objects from a set of \(n\) objects when the order of the \(r\) objects
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Describe how exponential functions and geometric sequences are similar. How are they different?
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