Problem 5
Question
For Problems \(1-24\), divide the monomials. $$ \frac{-16 n^{6}}{2 n^{2}} $$
Step-by-Step Solution
Verified Answer
The quotient is \(-8n^4\).
1Step 1: Simplify the Coefficients
First, simplify the fraction of the numerical coefficients \(-16\) and \(2\). Divide \(-16\) by \(2\) which equals \(-8\). So, the fraction of coefficients becomes \(-8\).
2Step 2: Simplify the Variables
Next, simplify the variables by applying the quotient rule for exponents, which states that \(\frac{a^m}{a^n} = a^{m-n}\). Here, you have \(\frac{n^6}{n^2}\). Subtract the exponent of the denominator from the exponent of the numerator: \(6 - 2 = 4\). Thus, \(n^4\) is the result.
3Step 3: Write the Simplified Expression
Combine the simplified coefficient and variable from Steps 1 and 2. The resulting expression is \(-8n^4\).
Key Concepts
Simplifying CoefficientsQuotient Rule for ExponentsAlgebraic Expressions
Simplifying Coefficients
When dividing monomials, the first step is to simplify the coefficients, which are the numerical parts of the terms. In the example provided, we have the coefficients \(-16\) and \(2\) in the fraction \(\frac{-16 n^6}{2 n^2}\). Here, simplifying these coefficients involves basic division:
- Divide \(-16\) by \(2\).
- The solution to this is \(-8\).
Quotient Rule for Exponents
Once we have simplified the coefficients, the next step is dealing with the variables. In our exercise, we're working with \(n^6\) and \(n^2\). To simplify these, we apply the quotient rule for exponents. This rule is fundamental in algebra as it states:
- When dividing like bases, subtract the exponents: \(\frac{a^m}{a^n} = a^{m-n}\).
- The exponent of \(n\) in the numerator is \(6\), and in the denominator, it's \(2\).
- So, \(6 - 2 = 4\).
Algebraic Expressions
In algebra, expressions that include numbers, variables, and operations are known as algebraic expressions. Dividing and simplifying such expressions, as we observed, involves both the numerical coefficients and the variable parts. Here’s why understanding them is crucial:
- Coefficients provide the numerical value that controls the magnitude of the variable terms.
- Variables, which we can often simplify using exponent rules, determine the expression's form.
Other exercises in this chapter
Problem 5
For Problems \(1-30\), evaluate each numerical expression. $$ \left(\frac{3}{2}\right)^{-1} $$
View solution Problem 5
For Problems \(1-40\), perform the divisions. (Objective 1) $$ \left(x^{2}+11 x+28\right) \div(x+3) $$
View solution Problem 5
For Problems \(1-8\), determine the degree of each polynomial. $$ 5 x^{3}-x^{2}-x+3 $$
View solution Problem 6
For Problems \(1-10\), find the indicated products by applying the distributive property; for example, $$ \begin{aligned} (x+1)(y+5) &=x(y)+x(5)+1(y)+1(5) \\ &=
View solution