Problem 5
Question
Find the vertex of the graph of each quadratic function by completing the square or using the vertex formula. $$ f(x)=5 x^{2}-10 x+3 $$
Step-by-Step Solution
Verified Answer
The vertex of the quadratic function is (1, -2).
1Step 1: Identify the form of the quadratic equation
The given quadratic function is \( f(x) = 5x^2 - 10x + 3 \). This is in the standard form \( ax^2 + bx + c \), where \( a = 5 \), \( b = -10 \), and \( c = 3 \).
2Step 2: Use the Vertex Formula
The vertex of a parabola of form \( ax^2 + bx + c \) can be found using the vertex formula \( x = -\frac{b}{2a} \). Substitute \( a = 5 \) and \( b = -10 \) into the formula.
3Step 3: Calculate the x-coordinate of the vertex
Plug in the values into the formula: \( x = -\frac{-10}{2\times 5} = \frac{10}{10} = 1 \). The x-coordinate of the vertex is 1.
4Step 4: Find the y-coordinate of the vertex
Substitute \( x = 1 \) back into the original function to find the y-coordinate: \( f(1) = 5(1)^2 - 10(1) + 3 = 5 - 10 + 3 = -2 \).
5Step 5: Write the vertex in coordinate form
The vertex of the function, expressed as a coordinate, is \( (1, -2) \).
Key Concepts
Quadratic FunctionCompleting the SquareParabola Vertex
Quadratic Function
A quadratic function is a type of polynomial function that is crucial in mathematics because it represents parabolas when graphed. It is generally written in the form \( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( x \) represents the variable. The graph of a quadratic function is a curve known as a parabola.
Some interesting features of quadratic functions include:
Some interesting features of quadratic functions include:
- The degree of the function is 2, which means the highest power of \( x \) is \( x^2 \).
- The graph of a quadratic function is symmetric.
- The sign of \( a \) determines whether the parabola opens upwards \((a > 0)\) or downwards \((a < 0)\).
- The vertex of the parabola represents the minimum point if \( a > 0 \), or the maximum point if \( a < 0 \).
Completing the Square
Completing the square is a method used to transform a quadratic equation into a perfect square trinomial, making it easier to determine characteristics of its graph, such as the vertex. This involves creating an expression that looks like \((x-h)^2 + k\), where \( (h, k) \) is the vertex of the parabola.
Here's how you can complete the square for a quadratic function:
Here's how you can complete the square for a quadratic function:
- Start with the standard quadratic form \( ax^2 + bx + c \).
- Factor out \( a \) from the first two terms, if \( a eq 1 \). This gives you \( a(x^2 + \frac{b}{a}x) + c \).
- Within the parentheses, add and subtract \( (\frac{b}{2a})^2 \) to create a perfect square trinomial.
- Rewrite the expression as \( a(x-h)^2 + k \) where \( h = \frac{-b}{2a} \) and \( k \) is adjusted to complete the equation.
Parabola Vertex
The vertex of a parabola is a significant point that defines its position and orientation, acting as either the lowest or highest point of the graph. For any quadratic function of the form \( ax^2 + bx + c \), the vertex serves as a pivot point that highlights the symmetry of the parabola.
To find the vertex, one can use the vertex formula \( x = -\frac{b}{2a} \), which calculates the x-coordinate of the vertex. By substituting this x-value back into the original quadratic equation, the corresponding y-coordinate can be found.
For example, given the quadratic function \( f(x) = 5x^2 - 10x + 3 \):
To find the vertex, one can use the vertex formula \( x = -\frac{b}{2a} \), which calculates the x-coordinate of the vertex. By substituting this x-value back into the original quadratic equation, the corresponding y-coordinate can be found.
For example, given the quadratic function \( f(x) = 5x^2 - 10x + 3 \):
- Use \( x = -\frac{-10}{2 \times 5} = 1 \) to find the x-coordinate.
- Substitute \( x = 1 \) back into the equation: \( f(1) = 5(1)^2 - 10(1) + 3 = -2 \), making the vertex \( (1, -2) \).
Other exercises in this chapter
Problem 5
Use the quadratic formula to solve each equation. These equations have real number solutions only. $$ x^{2}-6 x+9=0 $$
View solution Problem 5
Write the solution set in interval notation. $$ x^{2}+8 x+15 \geq 0 $$
View solution Problem 5
Use the square root property to solve each equation. $$ x^{2}=18 $$
View solution Problem 5
Solve. See Example 1. $$ \sqrt{9 x}=x+2 $$
View solution