Problem 5
Question
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=2 \csc x$$
Step-by-Step Solution
Verified Answer
Period: \( 2\pi \). Asymptotes at \( x = n\pi \) for integer \( n \).
1Step 1: Understand the Function
The given function is \( y = 2 \csc x \). The cosecant function, \( \csc x \), is the reciprocal of the sine function, \( \csc x = \frac{1}{\sin x} \). The graph of \( \csc x \) has vertical asymptotes where the sine function is zero.
2Step 2: Identify Asymptotes
The sine function, \( \sin x \), equals zero at integer multiples of \( \pi \), i.e., \( x = n\pi \) where \( n \) is an integer. Therefore, the graph of \( \csc x \), and consequently \( 2\csc x \), has vertical asymptotes at these points.
3Step 3: Determine the Period
The period of \( \csc x \) is the same as the sine function, which is \( 2\pi \). Thus, the period of \( 2 \csc x \) is also \( 2\pi \).
4Step 4: Sketch the Graph
In the interval from \( 0 \) to \( 2\pi \), sketch the reciprocal of the sine function. At \( x = \frac{\pi}{2} \) and \( x = \frac{3\pi}{2} \), the sine function reaches its maximum and minimum, and the cosecant will have corresponding curves peaking at \( y = 2 \) or dipping to \( y = -2 \). Draw vertical asymptotes at \( x = 0 \), \( x = \pi \), and \( x = 2\pi \). Repeat the pattern for additional periods.
Key Concepts
Vertical AsymptotesPeriod of Trigonometric FunctionReciprocal Trigonometric Functions
Vertical Asymptotes
In trigonometric functions, especially when dealing with reciprocal functions like the cosecant, vertical asymptotes are a key characteristic. Vertical asymptotes occur where the original trigonometric function is undefined. For the cosecant function, which is defined as the reciprocal of the sine function, asymptotes arise where the sine function is equal to zero as these are points where division by zero would occur.In the function \(y = 2 \csc x\), the vertical asymptotes occur at the same places as for standard cosecant because multiplying by a constant (in this case, 2) doesn't affect the location of the asymptotes. The sine function is zero at integer multiples of \(\pi\), specifically \(x = n\pi\) where \(n\) is an integer. Therefore, the graph of \(2\csc x\) has vertical asymptotes at these values:
- \(x = 0\)
- \(x = \pi\)
- \(x = 2\pi\)
- And continuing at every integer multiple of \(\pi\)
Period of Trigonometric Function
The period of a trigonometric function is the length required for the function to complete one full cycle of its pattern and begin repeating its values. Understanding the period is crucial for graphing trigonometric functions correctly.For the sine function, which forms the basis of the cosecant function, the period is \(2\pi\). This means every \(2\pi\) units along the x-axis, the sine function repeats its pattern. Since the cosecant is the reciprocal of the sine function, it naturally inherits this period. Therefore, the period of \(\csc x\) and consequently \(2\csc x\) remains \(2\pi\).For \(y = 2\csc x\), although the vertical stretch factor of 2 amplifies the peaks and troughs, the length of one complete cycle remains the same at \(2\pi\). This constant period ensures that when sketching its graph, the repeating pattern of peaks and troughs is spaced consistently over each interval of \(2\pi\). By marking out these intervals, you can accurately represent the periodic nature of the function on a graph.
Reciprocal Trigonometric Functions
Reciprocal trigonometric functions are derived by taking the reciprocal (or inverse) of the basic trigonometric functions (sine, cosine, and tangent). The cosecant, secant, and cotangent functions are the three primary reciprocal trigonometric functions:
- Cosecant (\( \csc x = \frac{1}{\sin x} \))
- Secant (\( \sec x = \frac{1}{\cos x} \))
- Cotangent (\( \cot x = \frac{1}{\tan x} \))
Other exercises in this chapter
Problem 4
Exer. 1-4: If the given angle is in standard position, find two positive coterminal angles and two negative coterminal angles. (a) \(570^{\circ}\) (b) \(\frac{2
View solution Problem 5
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) find the exact values of the remaining parts. $$a=5, \quad b=5$$
View solution Problem 5
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=\sin \left(x-\frac{\pi}{2}\right)\)
View solution Problem 5
Find the reference angle \(\theta_{R}\) if \(\theta\) has the given measure. (a) 3 (b) \(-2\) \((c) 5.5\) (d) 100
View solution