Problem 5
Question
Find the \(n\) th term of the geometric sequence with given first term \(a\) and common ratio \(r .\) What is the fourth term? $$a=3, \quad r=5$$
Step-by-Step Solution
Verified Answer
The fourth term is 375.
1Step 1: Recall the Formula for the Geometric Sequence
The formula for the \(n\) th term of a geometric sequence is given by \( a_n = a \cdot r^{n-1} \), where \(a\) is the first term, and \(r\) is the common ratio.
2Step 2: Identify the Values
We're given the first term \(a = 3\) and the common ratio \(r = 5\). We need to find the fourth term, so we'll use \(n = 4\).
3Step 3: Substitute into the Formula
Substitute \(a = 3\), \(r = 5\), and \(n = 4\) into the formula: \( a_4 = 3 \cdot 5^{4-1} \).
4Step 4: Calculate the Exponent
Calculate \(5^{4-1} = 5^3 = 125\).
5Step 5: Multiply to Find the Fourth Term
Now, multiply by the first term: \(a_4 = 3 \cdot 125 = 375\). Therefore, the fourth term is 375.
Key Concepts
nth termfirst termcommon ratio
nth term
In a geometric sequence, the "nth term" represents the position of a specific element when counting from the beginning of the sequence. The formula to find the nth term is:
This formula is fundamental because it allows us to calculate any term in the sequence without listing all preceding terms.
In our exercise, calculating the fourth term means substituting \(a = 3\), \(r = 5\), and \(n = 4\) into the formula. This guides us naturally to the final result, illustrating how each component interacts to expand the sequence linearly based on exponential growth.
- \( a_n = a \cdot r^{n-1} \)
This formula is fundamental because it allows us to calculate any term in the sequence without listing all preceding terms.
In our exercise, calculating the fourth term means substituting \(a = 3\), \(r = 5\), and \(n = 4\) into the formula. This guides us naturally to the final result, illustrating how each component interacts to expand the sequence linearly based on exponential growth.
first term
The "first term" of a geometric sequence, denoted as \(a\), is the starting point of the sequence. It acts as the sequence's foundation.
Every other term in the sequence is derived from this initial value by repeated multiplication with the common ratio.
Every other term in the sequence is derived from this initial value by repeated multiplication with the common ratio.
- In our example, the first term \(a\) is given as 3.
common ratio
The "common ratio" in a geometric sequence is what you multiply each term by to get to the next term. It is denoted as \(r\). Each term after the first is generated by multiplying the previous term by this common ratio.
This property creates the sequence's consistent pattern of growth or decay.
Understanding the common ratio allows us to easily predict future terms and adapt the process depending on the size and direction the sequence must take according to our beginning term.
This property creates the sequence's consistent pattern of growth or decay.
- For our problem, the common ratio is given as 5.
Understanding the common ratio allows us to easily predict future terms and adapt the process depending on the size and direction the sequence must take according to our beginning term.
Other exercises in this chapter
Problem 5
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Use Pascal's triangle to expand the expression. $$(x-1)^{5}$$
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Annuity Find the amount of an annuity that consists of 16 quarterly payments of \(\$ 300\) each into an account that pays \(8 \%\) interest per year, compounded
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Find the first four terms and the 100 th term of the sequence. $$a_{n}=\frac{(-1)^{n}}{n^{2}}$$
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