Problem 5
Question
Find the least common denominator of the rational expressions. $$\frac{4}{x-3} \text { and } \frac{7}{x+1}$$
Step-by-Step Solution
Verified Answer
The least common denominator of the fractional expressions \(\frac{4}{x-3}\) and \(\frac{7}{x+1}\) is \(x^2 -2x - 3\).
1Step 1: Identify the Denominators
In the given rational expressions which are fractions, the denominators in these fractions are x-3 and x+1 respectively.
2Step 2: Determine the Least Common Denominator
To find the least common denominator (LCD) of these expressions, since both denominators, x-3 and x+1 have no common factors other than 1, the LCD is simply the product of the two, which is (x-3)*(x+1). This is obtained by multiplying the two denominators together since there are no common factors.
3Step 3: Simplify the Expression
To simplify this expression further, use the distributive property (or FOIL) where the first terms, outside terms, inside terms and last terms are multiplied. In this case, it would yield \(x^2 -3x + x -3 \), which simplified further becomes \(x^2 -2x - 3\)
Other exercises in this chapter
Problem 5
In Exercises \(5-8,\) determine the constant of variation for each stated condition. \(y\) varies directly as \(x,\) and \(y=80\) when \(x=4\)
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Simplify complex rational expression by the method of your choice. \(\frac{\frac{2}{5}-\frac{1}{3}}{\frac{2}{3}-\frac{3}{4}}\)
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Solve each rational equation. $$2-\frac{8}{x}=6$$
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