Problem 5
Question
Find the indicated products directly by inspection. It should not be necessary to write down intermediate steps [except possibly when using Eq. (6.6) ] $$40(x-y)$$
Step-by-Step Solution
Verified Answer
The product is \(40x - 40y\).
1Step 1: Identify the Components
In the expression \(40(x-y)\), the components are the constant 40 and the binomial \((x-y)\).
2Step 2: Apply Distribution
Recognize that the number 40 needs to be distributed across the binomial \((x-y)\). This means multiplying 40 by each term within the parentheses separately.
3Step 3: Multiply the First Term
Multiply 40 by \(x\): \[40 \times x = 40x\]
4Step 4: Multiply the Second Term
Multiply 40 by \(-y\): \[40 \times (-y) = -40y\]
5Step 5: Combine the Results
Combine the results from Steps 3 and 4 to form the final expression:\[40x - 40y\]
Key Concepts
Understanding the Distribution PropertyExploring BinomialsMastering Multiplication of Terms
Understanding the Distribution Property
The distribution property is a fundamental principle in algebra that helps simplify expressions and solve equations. It allows you to multiply a sum or difference by distributing a factor to each term inside the parenthesis.
When you see an expression like \(40(x-y)\), the distribution property tells us to multiply the 40 by each term in the binomial \((x-y)\). Here’s how it works:
When you see an expression like \(40(x-y)\), the distribution property tells us to multiply the 40 by each term in the binomial \((x-y)\). Here’s how it works:
- Multiply 40 by \(x\) to get \(40x\).
- Multiply 40 by \(-y\) to get \(-40y\).
Exploring Binomials
A binomial is a simple and common algebraic expression consisting of two terms separated by a plus or minus sign. For example, in our exercise, \((x-y)\) is a binomial because it consists of the terms \(x\) and \(-y\).
Binomials are everywhere in algebra, and understanding how to handle them is crucial. They often appear in equations, polynomial expressions, and may even need to be manipulated or expanded. Learning to work with binomials involves recognizing their structure:
Binomials are everywhere in algebra, and understanding how to handle them is crucial. They often appear in equations, polynomial expressions, and may even need to be manipulated or expanded. Learning to work with binomials involves recognizing their structure:
- Look for two distinct terms joined by a plus or minus.
- Understand that distribution or other operations can be used on each term separately.
Mastering Multiplication of Terms
Multiplying terms involves combining numbers and variables through a multiplication operation. When dealing with expressions like \(40(x-y)\), it's important to multiply carefully to maintain accuracy.
Here's the process broken down:
Here's the process broken down:
- Multiply a number by a variable (e.g., 40 multiplied by \(x\) becomes \(40x\)).
- Don't forget the sign of each term; multiplying 40 by \(-y\) gives \(-40y\), not \(40y\).
- A positive times a negative gives a negative.
- Positive times positive and negative times negative both result in a positive.
Other exercises in this chapter
Problem 5
Simplify the given expressions involving the indicated multiplications and divisions. $$\frac{3}{8} \times \frac{2}{7}$$
View solution Problem 5
Multiply the numerator and the denominator of each fraction by the given factor and obtain an equivalent fraction. $$\left.\frac{2}{3} \quad \text { (by } 7\rig
View solution Problem 5
Factor the given expressions completely. $$6 x+6 y$$
View solution Problem 6
Perform the indicated operations and simplify. $$\frac{2}{13}+\frac{6}{13}$$
View solution