Problem 5
Question
Find the derivative at the indicated point from the graph of \(y=f(x)\). \(f(x)=x^{2} ; x=0\)
Step-by-Step Solution
Verified Answer
The derivative of \( f(x) = x^2 \) at \( x = 0 \) is 0.
1Step 1: Identify the Function and Point
We are given the function \( f(x) = x^2 \) and asked to find the derivative at \( x = 0 \). First, recognize that \( f(x) \) is a simple quadratic function.
2Step 2: Compute the Derivative of the Function
The derivative of the function \( f(x) = x^2 \) with respect to \( x \) is calculated using the power rule. The power rule states that \( \frac{d}{dx}[x^n] = nx^{n-1} \). For \( f(x) = x^2 \), we find \( f'(x) = 2x^{2-1} = 2x \).
3Step 3: Evaluate the Derivative at the Given Point
Next, substitute \( x = 0 \) into the derivative \( f'(x) = 2x \). This gives us \( f'(0) = 2(0) = 0 \).
4Step 4: Interpret the Result
The derivative \( f'(0) = 0 \) indicates that at \( x = 0 \), the slope of the tangent to the graph of \( f(x) = x^2 \) is zero. This means the graph is flat at this point, confirming that \( x = 0 \) is the vertex of the parabola described by \( y = x^2 \).
Key Concepts
Power RuleQuadratic FunctionTangent
Power Rule
The power rule is a fundamental concept used to find the derivative of functions of the form \(f(x) = x^n\). It simplifies the differentiation process, especially for polynomial functions.
This rule makes it quick and easy to calculate derivatives of terms like \(x^3\), \(x^4\), or any power \(n\). Whenever you see a power of \(x\), the power rule is your go-to tool for finding how the function's slope changes.
- The general form of the power rule is written as \(\frac{d}{dx}[x^n] = nx^{n-1}\).
- This rule states that to find the derivative, you multiply the exponent \(n\) by the base \(x\) raised to the power of \(n-1\).
This rule makes it quick and easy to calculate derivatives of terms like \(x^3\), \(x^4\), or any power \(n\). Whenever you see a power of \(x\), the power rule is your go-to tool for finding how the function's slope changes.
Quadratic Function
A quadratic function is a type of polynomial function where the highest power of the variable is 2. This forms the general function \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants and \(a eq 0\).
For the given example, \(f(x) = x^2\), we have a simple quadratic function with \(a = 1\), \(b = 0\), and \(c = 0\). The graph of any quadratic function is a parabola, which can open upwards or downwards depending on the sign of \(a\).
For the given example, \(f(x) = x^2\), we have a simple quadratic function with \(a = 1\), \(b = 0\), and \(c = 0\). The graph of any quadratic function is a parabola, which can open upwards or downwards depending on the sign of \(a\).
- If \(a > 0\), the parabola opens upwards.
- If \(a < 0\), the parabola opens downwards.
Tangent
In calculus, a tangent refers to a straight line that just "touches" a curve at a specific point without crossing it. At that point, the tangent line's slope equals the derivative of the function at that specific point.For our function \(f(x) = x^2\), the tangent line at \(x = 0\) has a particular significance. When we computed the derivative and found \(f'(0) = 0\), it told us something crucial about the shape of the parabola at that point.
- A slope of zero for the tangent line means the line is perfectly horizontal at \(x=0\).
- This implies that the graph of \(f(x) = x^2\) is flat at the origin.
Other exercises in this chapter
Problem 4
In Problems \(1-8\), find \(\frac{d y}{d x}\) by implicit differentiation. $$ x y-y^{3}=1 $$
View solution Problem 4
In Problems 1-28, differentiate the functions with respect to the independent variable. $$ f(x)=\left(x^{2}-3 x\right)^{3} $$
View solution Problem 5
Find the derivative with respect to the independent variable. $$ f(x)=\cos (x+1) $$
View solution Problem 5
Find the inverse of each function and differentiate each inverse in two ways: (i) Differentiate the inverse function directly, and (ii) use (4.14) to find the d
View solution