Problem 5
Question
Find the derivative. Assume that \(a, b, c\), and \(k\) are constants. $$ y=5 x e^{x^{2}} $$
Step-by-Step Solution
Verified Answer
The derivative is \( \frac{dy}{dx} = e^{x^2}(5 + 10x^2) \).
1Step 1: Identify the Function
First, recognize that the given function is in the form of a product, specifically \( y = 5x \cdot e^{x^2} \). Here, \( u = 5x \) and \( v = e^{x^2} \). We will need to use the product rule to differentiate.
2Step 2: Recall the Product Rule
To differentiate a product of two functions \( u \cdot v \), use the product rule: \( \frac{d}{dx}(u \cdot v) = u'v + uv' \). We will apply this rule to find \( \frac{dy}{dx} \).
3Step 3: Differentiate Each Component
Differentiate \( u = 5x \) to get \( u' = 5 \). Differentiate \( v = e^{x^2} \) using the chain rule: \( v' = \frac{d}{dx}(e^{x^2}) = 2xe^{x^2} \).
4Step 4: Apply the Product Rule
Substitute \( u' \), \( u \), \( v \), and \( v' \) into the product rule formula: \( \frac{dy}{dx} = 5 \cdot e^{x^2} + 5x \cdot 2xe^{x^2} \).
5Step 5: Simplify the Expression
Simplify the derivative: \( \frac{dy}{dx} = 5e^{x^2} + 10x^2e^{x^2} \). Factor out \( e^{x^2} \) from the expression to get \( \frac{dy}{dx} = e^{x^2}(5 + 10x^2) \).
Key Concepts
Product RuleChain RuleDerivative CalculationExponential Functions
Product Rule
The product rule is an essential technique in calculus used to differentiate functions that are products of two simpler functions. With the function from our exercise, which is given by
To differentiate this, the product rule formula states:
- \( y = 5x \cdot e^{x^2} \)
To differentiate this, the product rule formula states:
- \[ \frac{d}{dx}(uv) = u'v + uv' \]
Chain Rule
The chain rule is another pivotal rule in calculus, used for differentiating composite functions. In the derivative calculation of \( e^{x^2} \), the chain rule is applied. The expression \( e^{x^2} \) can be seen as a composite function, namely \( e^{u} \) where \( u = x^2 \).
When differentiating \( e^{x^2} \), the chain rule allows us to break down the process into more manageable parts:
When differentiating \( e^{x^2} \), the chain rule allows us to break down the process into more manageable parts:
- First, differentiate the outer function: the derivative of \( e^u \) with respect to \( u \) is \( e^u \).
- Then, differentiate the inside function: the derivative of \( x^2 \) with respect to \( x \) is \( 2x \).
Derivative Calculation
In calculus, calculating the derivative of a function is crucial as it represents the rate of change. In the original exercise, we were tasked with finding the derivative of
Let's break it down further:
- \( y = 5x \cdot e^{x^2} \)
Let's break it down further:
- Differentiate \( u = 5x \) to get \( u' = 5 \).
- Apply the chain rule to \( v = e^{x^2} \) to find \( v' = 2xe^{x^2} \).
- \( \frac{dy}{dx} = u'v + uv' = 5e^{x^2} + 5x \cdot 2xe^{x^2} \)
- \( \frac{dy}{dx} = e^{x^2}(5 + 10x^2) \)
Exponential Functions
Exponential functions are a key element in calculus and other areas of mathematics. They are of the form \( y = a^x \) or the natural exponential function \( y = e^x \), which is encountered in the original problem.
The natural exponential function, \( e^{x^2} \), exhibits unique properties:
The natural exponential function, \( e^{x^2} \), exhibits unique properties:
- The base \( e \) is approximately equal to 2.71828, which has special properties in calculus.
- Derivative of \( e^x \) with respect to \( x \) is \( e^x \), making it easy to manage compared to other functions.
Other exercises in this chapter
Problem 4
Differentiate the functions in Problems 1-28. Assume that \(A\), \(B\), and \(C\) are constants. \(f(x)=x^{3}+3^{x}\)
View solution Problem 4
Find the derivative. Assume \(a, b, c, k\) are constants. $$y=x^{-12}$$
View solution Problem 5
Differentiate the functions in Problems 1-20. Assume that \(A\) and \(B\) are constants. $$ R(q)=q^{2}-2 \cos q $$
View solution Problem 5
Differentiate the functions in Problems 1-28. Assume that \(A\), \(B\), and \(C\) are constants. \(y=2^{x}+\frac{2}{x^{3}}\)
View solution