Problem 5
Question
Find, if possible, \(A+B, A-B, 2 A\), and \(-3 B\) $$ A=\left[\begin{array}{lll} 4 & -3 & 2 \end{array}\right], \quad B=\left[\begin{array}{lll} 7 & 0 & -5 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
\(A+B = \begin{bmatrix} 11 & -3 & -3 \end{bmatrix}\), \(A-B = \begin{bmatrix} -3 & -3 & 7 \end{bmatrix}\), \(2A = \begin{bmatrix} 8 & -6 & 4 \end{bmatrix}\), \(-3B = \begin{bmatrix} -21 & 0 & 15 \end{bmatrix}\)."
1Step 1: Check the compatibility of matrices for addition and subtraction
For matrix addition and subtraction, both matrices must have the same dimensions. Here, both matrices \(A\) and \(B\) are 1x3, so we can proceed with addition and subtraction.
2Step 2: Add matrices A and B
To add matrices \(A\) and \(B\), add their corresponding elements: \(A + B = \begin{bmatrix} 4+7 & -3+0 & 2+(-5) \end{bmatrix} = \begin{bmatrix} 11 & -3 & -3 \end{bmatrix}\).
3Step 3: Subtract matrix B from A
To subtract \(B\) from \(A\), subtract corresponding elements of \(B\) from \(A\): \(A - B = \begin{bmatrix} 4-7 & -3-0 & 2-(-5) \end{bmatrix} = \begin{bmatrix} -3 & -3 & 7 \end{bmatrix}\).
4Step 4: Multiply matrix A by scalar 2
To multiply each element of matrix \(A\) by 2, perform the operation: \(2A = \begin{bmatrix} 2\times4 & 2\times(-3) & 2\times2 \end{bmatrix} = \begin{bmatrix} 8 & -6 & 4 \end{bmatrix}\).
5Step 5: Multiply matrix B by scalar -3
To multiply each element of matrix \(B\) by \(-3\), perform the operation: \(-3B = \begin{bmatrix} -3\times7 & -3\times0 & -3\times(-5) \end{bmatrix} = \begin{bmatrix} -21 & 0 & 15 \end{bmatrix}\).
Key Concepts
Matrix AdditionMatrix SubtractionScalar Multiplication1x3 Matrices
Matrix Addition
Matrix addition is a straightforward operation where we combine two matrices of the same dimensions by adding their corresponding elements. For example, if you have two 1x3 matrices like those in our exercise, the process becomes easy to understand. You can think of it like adding each number in a list with the corresponding number in another list.
To perform matrix addition:
To perform matrix addition:
- Ensure both matrices have the same dimension.
- Add corresponding elements together.
Matrix Subtraction
Matrix subtraction is similar to matrix addition, but instead, we subtract elements of one matrix from the corresponding elements of the other. This operation requires that matrices be of the same dimensions. Like subtraction in arithmetic, matrix subtraction follows simple logic:
- Ensure both matrices have the same dimension.
- Subtract elements of one matrix from the corresponding elements of the other.
Scalar Multiplication
Scalar multiplication involves multiplying every entry in a matrix by a constant, or scalar. It is a basic yet powerful matrix operation used in various applications, like scaling matrices or adjusting their size. Here's how you can carry out scalar multiplication:
- Select a scalar value (a constant number).
- Multiply each element of the matrix by the scalar.
1x3 Matrices
The matrices used in this example are 1x3 matrices, meaning they have one row and three columns. This specific dimension is quite simple yet serves as a great introduction to matrix operations without overwhelming complexity.
Understanding 1x3 matrices includes:
Understanding 1x3 matrices includes:
- Recognizing their structure: 1 row and 3 columns.
- Realizing they're often used in vector representation in three-dimensional space.
- Being aware that operations like addition, subtraction, and scalar multiplication are directly applicable.
Other exercises in this chapter
Problem 5
Exer. 1-14: Without expanding, explain why the statement is true. $$ \left|\begin{array}{lll} 2 & 4 & 2 \\ 1 & 2 & 4 \\ 2 & 6 & 4 \end{array}\right|=4\left|\beg
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Find the inverse of the matrix if it exists. $$ \left[\begin{array}{ll} 2 & 4 \\ 4 & 8 \end{array}\right] $$
View solution Problem 5
\(\left\\{\begin{array}{rr}2 x+6 y-4 z= & 1 \\ x+3 y-2 z= & 4 \\ 2 x+y-3 z= & -7\end{array}\right.\)
View solution Problem 5
Exer. 5-6: Sketch the region \(R\) determined by the given constraints, and label its vertices. Find the minimum value of \(C\) on \(R\). $$ \begin{array}{ll} C
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