Problem 5
Question
Find \(f^{\prime}(x)\) $$ f(x)=\frac{5-\cos x}{5+\sin x} $$
Step-by-Step Solution
Verified Answer
The derivative is \( f^{\prime}(x) = \frac{5\sin x + 1 - 5\cos x}{(5 + \sin x)^2} \).
1Step 1: Identify the Quotient Rule
To find the derivative of a function of the form \( \frac{u(x)}{v(x)} \), we use the quotient rule. The formula is given by: \( \left( \frac{u}{v} \right)^{\prime} = \frac{u^{\prime}v - uv^{\prime}}{v^2} \). In this problem, \( u(x) = 5 - \cos x \) and \( v(x) = 5 + \sin x \).
2Step 2: Differentiate the Numerator
Find the derivative of the numerator \( u(x) = 5 - \cos x \). The derivative of a constant is zero, and the derivative of \( -\cos x \) is \( \sin x \). Therefore, \( u^{\prime}(x) = \sin x \).
3Step 3: Differentiate the Denominator
Find the derivative of the denominator \( v(x) = 5 + \sin x \). Similarly, the derivative of \( \sin x \) is \( \cos x \), so \( v^{\prime}(x) = \cos x \).
4Step 4: Apply the Quotient Rule
Substitute \( u(x), v(x), u^{\prime}(x), \) and \( v^{\prime}(x) \) into the quotient rule: \[ f^{\prime}(x) = \frac{(\sin x)(5 + \sin x) - (5 - \cos x)(\cos x)}{(5 + \sin x)^2} \].
5Step 5: Simplify the Expression
Expand the numerator: \( \sin x (5 + \sin x) = 5\sin x + \sin^2 x \) and \( (5 - \cos x)\cos x = 5\cos x - \cos^2 x \). Substitute back: \[ f^{\prime}(x) = \frac{5\sin x + \sin^2 x - 5\cos x + \cos^2 x}{(5 + \sin x)^2} \].
6Step 6: Further Simplify
Combine like terms in the numerator: \[ f^{\prime}(x) = \frac{5\sin x + \sin^2 x + \cos^2 x - 5\cos x}{(5 + \sin x)^2} \]. Recognize that \( \sin^2 x + \cos^2 x = 1 \), leading to: \[ f^{\prime}(x) = \frac{5\sin x + 1 - 5\cos x}{(5 + \sin x)^2} \].
7Step 7: Present the Final Answer
The derivative of the function \( f(x) = \frac{5 - \cos x}{5 + \sin x} \) is \( f^{\prime}(x) = \frac{5\sin x + 1 - 5\cos x}{(5 + \sin x)^2} \).
Key Concepts
Understanding Derivatives with the Quotient RuleTrigonometric Functions in DerivativesSimplifying the Derivative Expression
Understanding Derivatives with the Quotient Rule
The Quotient Rule is a method for finding the derivative of a function that is a quotient of two other functions. Think of it like dividing two parts and wanting to know how their rates of change compare. Specifically, if you have a function in the form of \( \frac{u(x)}{v(x)} \), the rule states that the derivative \( \left( \frac{u}{v} \right)^{\prime} \) is given by:
- Find the derivatives of the top (numerator) and bottom (denominator) parts separately.
- Apply the formula: \( \frac{u^{\prime}v - uv^{\prime}}{v^2} \).
Trigonometric Functions in Derivatives
Trigonometric functions like sine and cosine play a significant role when differentiating. They frequently appear and have straightforward derivatives:
These rules allow for seamless differentiation, making managing expressions much easier. Always check the function components individually when trigonometric aspects come into play.
- The derivative of \( \cos x \) is \( -\sin x \).
- The derivative of \( \sin x \) is \( \cos x \).
These rules allow for seamless differentiation, making managing expressions much easier. Always check the function components individually when trigonometric aspects come into play.
Simplifying the Derivative Expression
Once you've applied the quotient rule and found a derivative, a significant step follows: simplification. Simplifying makes expressions cleaner and easier to understand. Here's how to simplify effectively:
- First, distribute any multiplied terms across their parentheses.
- Next, combine like terms. For instance, \( 5\sin x + \cos^2 x \) in the expression.
- If you encounter identities, such as \( \sin^2 x + \cos^2 x = 1 \), use them to rewrite terms more simply.
Other exercises in this chapter
Problem 4
Given that the tangent line to \(y=f(x)\) at the point \((1,2)\) passes through the point \((-1,-1),\) find \(f^{\prime}(1) .\)
View solution Problem 5
Given the following table of values, find the indicated derivatives in parts (a) and (b). $$ \begin{array}{|c|c|c|c|c|}\hline x & {f(x)} & {f^{\prime}(x)} & {g(
View solution Problem 5
Find \(d y / d x\) $$ y=\pi^{3} $$
View solution Problem 5
Find \(f^{\prime}(x)\). \(f(x)=\left(3 x^{2}+6\right)\left(2 x-\frac{1}{4}\right)\)
View solution